Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
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Chapter 4, Problem 5STP
To determine

To Choose: The correct option.

Expert Solution & Answer
Check Mark

Answer to Problem 5STP

The height by which the box should be raised is 3.5 m_ , so option A is the correct answer.

Explanation of Solution

Given data:

Mass of the box, m=10 kg

Gravitational potential energy, GPE=350J

Gravity, g = 9.8 N/kg

Formula used:

Gravitational Potential Energy Equation:

  GPE=mgh

Where GPE is the gravitational potential energy of the object in joules, m is the mass of the object in kg and h is the height of the object in meters from the ground.

Calculation:

As per the problem,

  m=10 kgg= 9.8 N/kgGPE=350J

Substitute the values of mass, gravity and gravitational potential energy in the rearranged gravitational potential energy equation to get height:

  GPE=mghh=GPEmgh=350 J(10 kg)(9.8 N/kg)h=3.57 m3.5 m

Conclusion:

The height by which the box should be raised is 3.5 m_ , so option A is the correct answer.

Chapter 4 Solutions

Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)

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