Elements Of Physical Chemistry
Elements Of Physical Chemistry
7th Edition
ISBN: 9780198796701
Author: ATKINS, P. W. (peter William), De Paula, Julio
Publisher: Oxford University Press
Question
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Chapter 4, Problem 4A.4E

(a)

Interpretation Introduction

Interpretation:

Change in molar Gibbs energy of carbon dioxide at 20oC when its pressure is changed isothermally from 1.0 bar to 3.0 bar has to be determined.

Concept introduction:

The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔG.

Molal Gibbs free energy can be determined using the following formulas as shown below,

ΔG=RTlnV1V2Where,ΔG:ChangeinGibbsfreeenergyR:GasconstantT:TemperatureV1:InitialvolumeV2:Finalvolume

ΔG=ΔHTΔSwhere,ΔH:EnthalpychangeT:TemperatureΔS:Changeinentropy

For an isothermal reaction enthalpy change is zero, thus this equation can be written as,

ΔG=TΔS=T(CPlnT2T1RlnP2P1)=T(0RlnP2P1)

(a)

Expert Solution
Check Mark

Explanation of Solution

Change in molar Gibbs energy of carbon dioxide at 20oC when its pressure is changed isothermally from 1.0 bar to 3.0 bar can be determined as follows,

Herein,

Temperature,T=293KInitialpressure(P1)=1barFinalpressure(P2)=3bar

Substituting the known values in the above following equation,

ΔG=-T(0-RlnP2P1)=-293K(0-8.314Jmol-1K-1×ln31)=2676.22Jmol-1

As per the above calculation, the change in molar Gibbs energy in the given sample is found to be 2676.22Jmol-1

(b)

Interpretation Introduction

Interpretation:

Change in molar Gibbs energy of carbon dioxide at 20oC when its pressure is changed isothermally from 1.0 bar to 2.7×104atm has to be determined.

Concept introduction:

The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔG.

Molal Gibbs free energy can be determined using the following formulas as show below,

ΔG=RTlnV1V2Where,ΔG:ChangeinGibbsfreeenergyR:GasconstantT:TemperatureV1:InitialvolumeV2:Finalvolume

ΔG=ΔHTΔSwhere,ΔH:EnthalpychangeT:TemperatureΔS:Changeinentropy

For an isothermal reaction enthalpy change is zero, thus this equation can be written as,

ΔG=TΔS=T(CPlnT2T1RlnP2P1)=T(0RlnP2P1)

(b)

Expert Solution
Check Mark

Explanation of Solution

Change in molar Gibbs energy of carbon dioxide at 20oC when its pressure is changed isothermally from 1.0 bar to 3.0 bar can be determined as follows,

Herein,

Temperature,T=293KInitialpressure(P1)=1barFinalpressure(P2)=2.735×104bar (2.7×104atm×1.013bar1atm)

Substituting the known values in the above following equation,

ΔG=-T(0-RlnP2P1)=-293K(0-8.314Jmol-1K-1×ln2.735×1041)=-19985.47Jmol-1

As per the above calculation, the change in molar Gibbs energy in the given sample is found to be -19985.47Jmol-1

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Chapter 4 Solutions

Elements Of Physical Chemistry

Ch. 4 - Prob. 4D.1STCh. 4 - Prob. 4D.2STCh. 4 - Prob. 4D.3STCh. 4 - Prob. 4D.4STCh. 4 - Prob. 4E.1STCh. 4 - Prob. 4E.2STCh. 4 - Prob. 4F.1STCh. 4 - Prob. 4A.1ECh. 4 - Prob. 4A.2ECh. 4 - Prob. 4A.3ECh. 4 - Prob. 4A.4ECh. 4 - Prob. 4A.5ECh. 4 - Prob. 4A.6ECh. 4 - Prob. 4B.1ECh. 4 - Prob. 4B.2ECh. 4 - Prob. 4B.3ECh. 4 - Prob. 4B.4ECh. 4 - Prob. 4B.5ECh. 4 - Prob. 4B.6ECh. 4 - Prob. 4B.7ECh. 4 - Prob. 4B.8ECh. 4 - Prob. 4C.1ECh. 4 - Prob. 4C.2ECh. 4 - Prob. 4C.3ECh. 4 - Prob. 4C.4ECh. 4 - Prob. 4C.5ECh. 4 - Prob. 4C.6ECh. 4 - Prob. 4C.7ECh. 4 - Prob. 4D.1ECh. 4 - Prob. 4D.2ECh. 4 - Prob. 4D.3ECh. 4 - Prob. 4D.4ECh. 4 - Prob. 4D.5ECh. 4 - Prob. 4D.6ECh. 4 - Prob. 4D.7ECh. 4 - Prob. 4D.8ECh. 4 - Prob. 4D.9ECh. 4 - Prob. 4D.10ECh. 4 - Prob. 4D.11ECh. 4 - Prob. 4D.12ECh. 4 - Prob. 4D.13ECh. 4 - Prob. 4E.1ECh. 4 - Prob. 4E.2ECh. 4 - Prob. 4E.3ECh. 4 - Prob. 4E.4ECh. 4 - Prob. 4F.1ECh. 4 - Prob. 4F.2ECh. 4 - Prob. 4F.3ECh. 4 - Prob. 4.1DQCh. 4 - Prob. 4.2DQCh. 4 - Prob. 4.3DQCh. 4 - Prob. 4.4DQCh. 4 - Prob. 4.5DQCh. 4 - Prob. 4.6DQCh. 4 - Prob. 4.8DQCh. 4 - Prob. 4.9DQCh. 4 - Prob. 4.10DQCh. 4 - Prob. 4.11DQCh. 4 - Prob. 4.12DQCh. 4 - Prob. 4.13DQCh. 4 - Prob. 4.14DQCh. 4 - Prob. 4.15DQCh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.1PRCh. 4 - Prob. 4.2PRCh. 4 - Prob. 4.3PRCh. 4 - Prob. 4.4PRCh. 4 - Prob. 4.5PRCh. 4 - Prob. 4.6PR
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