Concept explainers
4.93 A mixture of methane (CH4) and propane (C3H8) has a total mass of 29.84 g. When the mixture is burned completely in excess oxygen, the CO2 and H2O products have a combined mass of 142.97 g. Calculate the mass of methane in the original mixture.
Interpretation: The mass of methane in the original mixture should be found out if
Concept introduction:
Burning of methane and propane in excess oxygen is a combustion reaction. When hydrocarbons burn out, that results in water and carbon dioxide gas. To complete combustion, there should be enough oxygen supply. Otherwise half combustion can occur. As a result of half combustion carbon monoxide and carbon particles are released to the environment.
Answer to Problem 4.93PAE
Solution:
Explanation of Solution
Completecombustion (Balance equation) reaction for both
Let’s take initial weight of propane as X, then initial weight of methane should be (29.84-X).
Using above equation, number of moles of each molecules present can be found out.
After the combustion of methane,
After the combustion of propane,
So final products weight can be obtained as follows,
So the mass of methane in original sample = 29.84 g -17.31 g
= 12.53 g
When the mas of a hydrocarbon mixture is known along with the mass of the product mix formed when it has undergone combustion reaction, the mass of individual hydrocarbons can be found out if the corresponding molar masses of the hydrocarbons are known.
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Chapter 4 Solutions
Chemistry for Engineering Students
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