4.10 How many moles of oxygen can be obtained by the decomposition of 7.5 mol of reactant in each of the following reactions? 2KClO 3 → 2KCl + 3O 2 2H 2 O 2 → 2H 2 O + O 2 2HgO → 2Hg + O 2 2NaNO 3 → 2NaNO 2 + O 2 KClO 4 → KCl + 2O 2

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Answer 1

Textbook Question

Chapter 4, Problem 4.10PAE

4.10 How many moles of oxygen can be obtained by the decomposition of 7.5 mol of reactant in each of the following reactions?

$2KClO 3 → 2KCl + 3O 2$

$2H 2 O 2 → 2H 2 O + O 2$

$2HgO → 2Hg + O 2$

$2NaNO 3 → 2NaNO 2 + O 2$

$KClO 4 → KCl + 2O 2$

Expert Solution

Interpretation Introduction

Interpretation:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant in each of the following reactions have to be calculated.

Concept Introduction:

The molar ratio can be used to relate:
The moles of product formed from certain moles of reactant.
The moles of reactant needed to form certain moles of a product.
The moles of a reactant needed to react with certain moles of a second reactant.

Given:

$2 KClO3→2 KCl + 3O22 H2O2→2 H2O + O22 HgO→2 Hg + O22 NaNO3→2 NaNO2 + O2KClO4→KCl+ 2 O2$

(a) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant $2 KClO3→2 KCl + 3O2$ .

Answer to Problem 4.10PAE

Solution:

a) 11.25 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO3 and O2$

2 moles of $KClO3$ reacting with 3 moles of $O2$ .

So that, the molar ratio is:

$3 mol O22 moles KClO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO3×3 moles O22 moles KClO3=11.25 moles of O2$

Conclusion

a) 11.25 moles of $O2$ .

Expert Solution

Interpretation Introduction

(b) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 H2O2→2 H2O + O2$ .

Answer to Problem 4.10PAE

Solution:

b) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $H2O2 and O2$

2 moles of $H2O2$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles H2O2$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles H2O2×1 mol O22 moles H2O2=3.75 moles of O2$

Conclusion

b) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(c) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 HgO→2 Hg + O2$ .

Answer to Problem 4.10PAE

Solution:

c) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $HgO and O2$

2 moles of $HgO$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles HgO$

2-Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles HgO×1 mol O22 moles HgO=3.75 moles of O2$

Conclusion

c) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(d) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 NaNO3→2 NaNO2 + O2$ .

Answer to Problem 4.10PAE

Solution:

d) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $NaNO3 and O2$

2 moles of $NaNO3$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles NaNO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles NaNO3×1 mol O22 moles NaNO3=3.75 moles of O2$

Conclusion

d) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(e) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $KClO4→KCl+ 2 O2$ .

Answer to Problem 4.10PAE

Solution:

e) 15 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO4 and O2$

1 mol of $KClO4$ react with 2 moles of $O2$

So that, the molar ratio is:

$2 moles O21 moles KClO4$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO4×2 moles O21 moles KClO4=15 moles of O2$

Conclusion

e) 15 moles of $O2$ .

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Answer 2

Textbook Question

Chapter 4, Problem 4.10PAE

4.10 How many moles of oxygen can be obtained by the decomposition of 7.5 mol of reactant in each of the following reactions?

$2KClO 3 → 2KCl + 3O 2$

$2H 2 O 2 → 2H 2 O + O 2$

$2HgO → 2Hg + O 2$

$2NaNO 3 → 2NaNO 2 + O 2$

$KClO 4 → KCl + 2O 2$

Expert Solution

Interpretation Introduction

Interpretation:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant in each of the following reactions have to be calculated.

Concept Introduction:

The molar ratio can be used to relate:
The moles of product formed from certain moles of reactant.
The moles of reactant needed to form certain moles of a product.
The moles of a reactant needed to react with certain moles of a second reactant.

Given:

$2 KClO3→2 KCl + 3O22 H2O2→2 H2O + O22 HgO→2 Hg + O22 NaNO3→2 NaNO2 + O2KClO4→KCl+ 2 O2$

(a) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant $2 KClO3→2 KCl + 3O2$ .

Answer to Problem 4.10PAE

Solution:

a) 11.25 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO3 and O2$

2 moles of $KClO3$ reacting with 3 moles of $O2$ .

So that, the molar ratio is:

$3 mol O22 moles KClO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO3×3 moles O22 moles KClO3=11.25 moles of O2$

Conclusion

a) 11.25 moles of $O2$ .

Expert Solution

Interpretation Introduction

(b) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 H2O2→2 H2O + O2$ .

Answer to Problem 4.10PAE

Solution:

b) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $H2O2 and O2$

2 moles of $H2O2$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles H2O2$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles H2O2×1 mol O22 moles H2O2=3.75 moles of O2$

Conclusion

b) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(c) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 HgO→2 Hg + O2$ .

Answer to Problem 4.10PAE

Solution:

c) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $HgO and O2$

2 moles of $HgO$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles HgO$

2-Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles HgO×1 mol O22 moles HgO=3.75 moles of O2$

Conclusion

c) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(d) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 NaNO3→2 NaNO2 + O2$ .

Answer to Problem 4.10PAE

Solution:

d) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $NaNO3 and O2$

2 moles of $NaNO3$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles NaNO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles NaNO3×1 mol O22 moles NaNO3=3.75 moles of O2$

Conclusion

d) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(e) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $KClO4→KCl+ 2 O2$ .

Answer to Problem 4.10PAE

Solution:

e) 15 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO4 and O2$

1 mol of $KClO4$ react with 2 moles of $O2$

So that, the molar ratio is:

$2 moles O21 moles KClO4$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO4×2 moles O21 moles KClO4=15 moles of O2$

Conclusion

e) 15 moles of $O2$ .

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Answer 3

Textbook Question

Chapter 4, Problem 4.10PAE

4.10 How many moles of oxygen can be obtained by the decomposition of 7.5 mol of reactant in each of the following reactions?

$2KClO 3 → 2KCl + 3O 2$

$2H 2 O 2 → 2H 2 O + O 2$

$2HgO → 2Hg + O 2$

$2NaNO 3 → 2NaNO 2 + O 2$

$KClO 4 → KCl + 2O 2$

Expert Solution

Interpretation Introduction

Interpretation:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant in each of the following reactions have to be calculated.

Concept Introduction:

The molar ratio can be used to relate:
The moles of product formed from certain moles of reactant.
The moles of reactant needed to form certain moles of a product.
The moles of a reactant needed to react with certain moles of a second reactant.

Given:

$2 KClO3→2 KCl + 3O22 H2O2→2 H2O + O22 HgO→2 Hg + O22 NaNO3→2 NaNO2 + O2KClO4→KCl+ 2 O2$

(a) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant $2 KClO3→2 KCl + 3O2$ .

Answer to Problem 4.10PAE

Solution:

a) 11.25 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO3 and O2$

2 moles of $KClO3$ reacting with 3 moles of $O2$ .

So that, the molar ratio is:

$3 mol O22 moles KClO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO3×3 moles O22 moles KClO3=11.25 moles of O2$

Conclusion

a) 11.25 moles of $O2$ .

Expert Solution

Interpretation Introduction

(b) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 H2O2→2 H2O + O2$ .

Answer to Problem 4.10PAE

Solution:

b) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $H2O2 and O2$

2 moles of $H2O2$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles H2O2$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles H2O2×1 mol O22 moles H2O2=3.75 moles of O2$

Conclusion

b) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(c) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 HgO→2 Hg + O2$ .

Answer to Problem 4.10PAE

Solution:

c) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $HgO and O2$

2 moles of $HgO$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles HgO$

2-Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles HgO×1 mol O22 moles HgO=3.75 moles of O2$

Conclusion

c) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(d) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 NaNO3→2 NaNO2 + O2$ .

Answer to Problem 4.10PAE

Solution:

d) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $NaNO3 and O2$

2 moles of $NaNO3$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles NaNO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles NaNO3×1 mol O22 moles NaNO3=3.75 moles of O2$

Conclusion

d) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(e) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $KClO4→KCl+ 2 O2$ .

Answer to Problem 4.10PAE

Solution:

e) 15 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO4 and O2$

1 mol of $KClO4$ react with 2 moles of $O2$

So that, the molar ratio is:

$2 moles O21 moles KClO4$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO4×2 moles O21 moles KClO4=15 moles of O2$

Conclusion

e) 15 moles of $O2$ .

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Answer 4

Textbook Question

Chapter 4, Problem 4.10PAE

4.10 How many moles of oxygen can be obtained by the decomposition of 7.5 mol of reactant in each of the following reactions?

$2KClO 3 → 2KCl + 3O 2$

$2H 2 O 2 → 2H 2 O + O 2$

$2HgO → 2Hg + O 2$

$2NaNO 3 → 2NaNO 2 + O 2$

$KClO 4 → KCl + 2O 2$

Expert Solution

Interpretation Introduction

Interpretation:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant in each of the following reactions have to be calculated.

Concept Introduction:

The molar ratio can be used to relate:
The moles of product formed from certain moles of reactant.
The moles of reactant needed to form certain moles of a product.
The moles of a reactant needed to react with certain moles of a second reactant.

Given:

$2 KClO3→2 KCl + 3O22 H2O2→2 H2O + O22 HgO→2 Hg + O22 NaNO3→2 NaNO2 + O2KClO4→KCl+ 2 O2$

(a) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant $2 KClO3→2 KCl + 3O2$ .

Answer to Problem 4.10PAE

Solution:

a) 11.25 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO3 and O2$

2 moles of $KClO3$ reacting with 3 moles of $O2$ .

So that, the molar ratio is:

$3 mol O22 moles KClO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO3×3 moles O22 moles KClO3=11.25 moles of O2$

Conclusion

a) 11.25 moles of $O2$ .

Expert Solution

Interpretation Introduction

(b) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 H2O2→2 H2O + O2$ .

Answer to Problem 4.10PAE

Solution:

b) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $H2O2 and O2$

2 moles of $H2O2$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles H2O2$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles H2O2×1 mol O22 moles H2O2=3.75 moles of O2$

Conclusion

b) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(c) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 HgO→2 Hg + O2$ .

Answer to Problem 4.10PAE

Solution:

c) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $HgO and O2$

2 moles of $HgO$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles HgO$

2-Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles HgO×1 mol O22 moles HgO=3.75 moles of O2$

Conclusion

c) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(d) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 NaNO3→2 NaNO2 + O2$ .

Answer to Problem 4.10PAE

Solution:

d) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $NaNO3 and O2$

2 moles of $NaNO3$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles NaNO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles NaNO3×1 mol O22 moles NaNO3=3.75 moles of O2$

Conclusion

d) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(e) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $KClO4→KCl+ 2 O2$ .

Answer to Problem 4.10PAE

Solution:

e) 15 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO4 and O2$

1 mol of $KClO4$ react with 2 moles of $O2$

So that, the molar ratio is:

$2 moles O21 moles KClO4$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO4×2 moles O21 moles KClO4=15 moles of O2$

Conclusion

e) 15 moles of $O2$ .

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

Interpretation:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant in each of the following reactions have to be calculated.

Concept Introduction:

The molar ratio can be used to relate:
The moles of product formed from certain moles of reactant.
The moles of reactant needed to form certain moles of a product.
The moles of a reactant needed to react with certain moles of a second reactant.

Given:

$2 KClO3→2 KCl + 3O22 H2O2→2 H2O + O22 HgO→2 Hg + O22 NaNO3→2 NaNO2 + O2KClO4→KCl+ 2 O2$

(a) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant $2 KClO3→2 KCl + 3O2$ .

Answer to Problem 4.10PAE

Solution:

a) 11.25 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO3 and O2$

2 moles of $KClO3$ reacting with 3 moles of $O2$ .

So that, the molar ratio is:

$3 mol O22 moles KClO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO3×3 moles O22 moles KClO3=11.25 moles of O2$

Conclusion

a) 11.25 moles of $O2$ .

Expert Solution

Interpretation Introduction

(b) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 H2O2→2 H2O + O2$ .

Answer to Problem 4.10PAE

Solution:

b) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $H2O2 and O2$

2 moles of $H2O2$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles H2O2$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles H2O2×1 mol O22 moles H2O2=3.75 moles of O2$

Conclusion

b) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(c) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 HgO→2 Hg + O2$ .

Answer to Problem 4.10PAE

Solution:

c) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $HgO and O2$

2 moles of $HgO$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles HgO$

2-Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles HgO×1 mol O22 moles HgO=3.75 moles of O2$

Conclusion

c) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(d) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 NaNO3→2 NaNO2 + O2$ .

Answer to Problem 4.10PAE

Solution:

d) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $NaNO3 and O2$

2 moles of $NaNO3$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles NaNO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles NaNO3×1 mol O22 moles NaNO3=3.75 moles of O2$

Conclusion

d) 3.75 moles of $O2$ .

Expert Solution

Interpretation Introduction

(e) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $KClO4→KCl+ 2 O2$ .

Answer to Problem 4.10PAE

Solution:

e) 15 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO4 and O2$

1 mol of $KClO4$ react with 2 moles of $O2$

So that, the molar ratio is:

$2 moles O21 moles KClO4$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO4×2 moles O21 moles KClO4=15 moles of O2$

Conclusion

e) 15 moles of $O2$ .

Answer 8

Expert Solution

Interpretation Introduction

Interpretation:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant in each of the following reactions have to be calculated.

Concept Introduction:

The molar ratio can be used to relate:
The moles of product formed from certain moles of reactant.
The moles of reactant needed to form certain moles of a product.
The moles of a reactant needed to react with certain moles of a second reactant.

Given:

$2 KClO3→2 KCl + 3O22 H2O2→2 H2O + O22 HgO→2 Hg + O22 NaNO3→2 NaNO2 + O2KClO4→KCl+ 2 O2$

(a) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant $2 KClO3→2 KCl + 3O2$ .

Answer to Problem 4.10PAE

Solution:

a) 11.25 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO3 and O2$

2 moles of $KClO3$ reacting with 3 moles of $O2$ .

So that, the molar ratio is:

$3 mol O22 moles KClO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO3×3 moles O22 moles KClO3=11.25 moles of O2$

Conclusion

a) 11.25 moles of $O2$ .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

Interpretation:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant in each of the following reactions have to be calculated.

Concept Introduction:

The molar ratio can be used to relate:
The moles of product formed from certain moles of reactant.
The moles of reactant needed to form certain moles of a product.
The moles of a reactant needed to react with certain moles of a second reactant.

Given:

$2 KClO3→2 KCl + 3O22 H2O2→2 H2O + O22 HgO→2 Hg + O22 NaNO3→2 NaNO2 + O2KClO4→KCl+ 2 O2$

(a) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant $2 KClO3→2 KCl + 3O2$ .

Answer 13

Answer to Problem 4.10PAE

Solution:

a) 11.25 moles of O₂.

Answer 14

Explanation of Solution

Write the molar ratio between the $KClO3 and O2$

2 moles of $KClO3$ reacting with 3 moles of $O2$ .

So that, the molar ratio is:

$3 mol O22 moles KClO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO3×3 moles O22 moles KClO3=11.25 moles of O2$

Answer 15

Conclusion

a) 11.25 moles of $O2$ .

Answer 16

Expert Solution

Interpretation Introduction

(b) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 H2O2→2 H2O + O2$ .

Answer to Problem 4.10PAE

Solution:

b) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $H2O2 and O2$

2 moles of $H2O2$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles H2O2$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles H2O2×1 mol O22 moles H2O2=3.75 moles of O2$

Conclusion

b) 3.75 moles of $O2$ .

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Interpretation Introduction

(b) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 H2O2→2 H2O + O2$ .

Answer 21

Answer to Problem 4.10PAE

Solution:

b) 3.75 moles of O₂.

Answer 22

Explanation of Solution

Write the molar ratio between the $H2O2 and O2$

2 moles of $H2O2$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles H2O2$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles H2O2×1 mol O22 moles H2O2=3.75 moles of O2$

Answer 23

Conclusion

b) 3.75 moles of $O2$ .

Answer 24

Expert Solution

Interpretation Introduction

(c) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 HgO→2 Hg + O2$ .

Answer to Problem 4.10PAE

Solution:

c) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $HgO and O2$

2 moles of $HgO$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles HgO$

2-Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles HgO×1 mol O22 moles HgO=3.75 moles of O2$

Conclusion

c) 3.75 moles of $O2$ .

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Interpretation Introduction

(c) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 HgO→2 Hg + O2$ .

Answer 29

Answer to Problem 4.10PAE

Solution:

c) 3.75 moles of O₂.

Answer 30

Explanation of Solution

Write the molar ratio between the $HgO and O2$

2 moles of $HgO$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles HgO$

2-Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles HgO×1 mol O22 moles HgO=3.75 moles of O2$

Answer 31

Conclusion

c) 3.75 moles of $O2$ .

Answer 32

Expert Solution

Interpretation Introduction

(d) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 NaNO3→2 NaNO2 + O2$ .

Answer to Problem 4.10PAE

Solution:

d) 3.75 moles of O₂.

Explanation of Solution

Write the molar ratio between the $NaNO3 and O2$

2 moles of $NaNO3$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles NaNO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles NaNO3×1 mol O22 moles NaNO3=3.75 moles of O2$

Conclusion

d) 3.75 moles of $O2$ .

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Interpretation Introduction

(d) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $2 NaNO3→2 NaNO2 + O2$ .

Answer 37

Answer to Problem 4.10PAE

Solution:

d) 3.75 moles of O₂.

Answer 38

Explanation of Solution

Write the molar ratio between the $NaNO3 and O2$

2 moles of $NaNO3$ react with 1 mol of $O2$

So that, the molar ratio is:

$1 mol O22 moles NaNO3$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles NaNO3×1 mol O22 moles NaNO3=3.75 moles of O2$

Answer 39

Conclusion

d) 3.75 moles of $O2$ .

Answer 40

Expert Solution

Interpretation Introduction

(e) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $KClO4→KCl+ 2 O2$ .

Answer to Problem 4.10PAE

Solution:

e) 15 moles of O₂.

Explanation of Solution

Write the molar ratio between the $KClO4 and O2$

1 mol of $KClO4$ react with 2 moles of $O2$

So that, the molar ratio is:

$2 moles O21 moles KClO4$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO4×2 moles O21 moles KClO4=15 moles of O2$

Conclusion

e) 15 moles of $O2$ .

Answer 41

Expert Solution

Answer 42

Expert Solution

Answer 43

Expert Solution

Answer 44

Interpretation Introduction

(e) To determine:

The moles of oxygen that is obtained by the decomposition of 7.5 moles of reactant of $KClO4→KCl+ 2 O2$ .

Answer 45

Answer to Problem 4.10PAE

Solution:

e) 15 moles of O₂.

Answer 46

Explanation of Solution

Write the molar ratio between the $KClO4 and O2$

1 mol of $KClO4$ react with 2 moles of $O2$

So that, the molar ratio is:

$2 moles O21 moles KClO4$

Calculate the moles of $O2$ produced

$moles of O2 produced= 7.5 moles KClO4×2 moles O21 moles KClO4=15 moles of O2$

Answer 47

Conclusion

e) 15 moles of $O2$ .

Answer 48

Ch. 4 - Describe the chemical composition of gasoline.Ch. 4 - Write balanced chemical equations for the...Ch. 4 - Prob. 3CO Ch. 4 - Calculate the amounts of reactants needed in a...Ch. 4 - Prob. 5CO Ch. 4 - Prob. 6CO Ch. 4 - Prob. 7CO Ch. 4 - 4.1 List at least two factors that make it...Ch. 4 - 4.2 What is an alkane?Ch. 4 - 4.3 Explain the difference between complete and...

4.10 How many moles of oxygen can be obtained by the decomposition of 7.5 mol of reactant in each of the following reactions? 2KClO 3 → 2KCl + 3O 2 2H 2 O 2 → 2H 2 O + O 2 2HgO → 2Hg + O 2 2NaNO 3 → 2NaNO 2 + O 2 KClO 4 → KCl + 2O 2

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Answer to Problem 4.10PAE

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Answer to Problem 4.10PAE

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Answer to Problem 4.10PAE

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Answer to Problem 4.10PAE

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Answer to Problem 4.10PAE

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