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A ball swings counterclockwise in a vertical circle at the end of a rope 1.50 m long. When the ball is 36.9° past the lowest point on its way up, its total acceleration is
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- Which of the following correctly describes the centripetal acceleration vector for a particle moving in a circular path? (a) constant and always perpendicular to the velocity vector for the particle (b) constant and always parallel to the velocity vector for the particle (c) of constant magnitude and always perpendicular to the velocity vector for the particle (d) of constant magnitude and always parallel to the velocity vector for the particlearrow_forwardYou can use the formula for centripetal acceleration OR You have to calculate the average acceleration directly from the definition, a = delta v / delta t. You have to first get a_x by using the velocity's initial and final x components, do a_y from the y components, and then use the Pythagorean formula to get the magnitude of the acceleration vector.arrow_forwardA ball swings counterclockwise in a vertical circle at the end of a rope 1.23 m long. When the ball is 37.4° past the lowest point on its way up, its total acceleration is (-17.21 + 22.6ĵ) m/s². For that instant, do the following. (a) Sketch a vector diagram showing the components of its acceleration. Choose File No file chosen This answer has not been graded yet. (b) Determine the magnitude of its radial acceleration. m/s² (c) Determine the velocity of the ball. m/s ° counterclockwise from the +î direction magnitude direction Nood Help?arrow_forward
- A ball swings counterclockwise in a vertical circle at the end of a rope 1.50 m long. When the ball is 36.9° past the lowest point on its way up, its resultant acceleration is a = (-22.5i + 20.2j) m/s2 , where i is the unit vector along the horizontal direction (you can treat it as pointing to the right), and j is the unit vector along the vertical direction (you can treat it as pointing upward). For that instant, (i) determine the magnitude of its centripetal acceleration in m/s2 (ii) determine the speed of the ball in in m/s (iii) determine the velocity of the ball in m/s, i and j.arrow_forwardA ball swings counterclockwise in a vertical circle at the end of a rope 1.50 m long. When the ball is 36.9° past the lowest point on its way up, its resultant acceleration is à = (-22.5î + 20.2j) m/s², where i is the unit vector along the horizontal direction (you can treat it as pointing to the right), and j is the unit vector along the vertical direction (you can treat it as pointing upward). For that instant, (i) determine the magnitude of its centripetal acceleration in m/s? (ii) determine the speed of the ball in in m/s (iii) determine the velocity of the ball in m/s, i and j.arrow_forwardA ball swings counterclockwise in a vertical circle at the end of a rope 1.32 m long. When the ball is 36.3° past the lowest point on its way up, its total acceleration is (-20.2î + 27.5j) m/s?. For that instant, do the following. (a) Sketch a vector diagram showing the components of its acceleration. 55cc36c335a46544b0c2a7cd126a5f89.pdf Key: Score: 1 out of 1 Comment: (b) Determine the magnitude of its radial acceleration. 34.12 34.1 m/s? (c) Determine the velocity of the ball. magnitude 6.71 6.71 m/s direction 36.3 36.3 ° counterclockwise from the +î directionarrow_forward
- A ball swings in a vertical circle at the end of a rope 1.50 m long. When the ball is 36.9° past the lowest point on its way up, its total acceleration (-22.5i + 20m2j)m/s^2. At that instant, (a) sketch a vector diagram showing the components of its acceleration, (b) determine the magnitude of its radial acceleration, and (c) determine the speed and velocity of the ball. Assume that motion is uniform.arrow_forwardA ball swings counterclockwise in a vertical circle at the end of a rope 1.50 m long. When the ball is 36.9° past the lowest point on its way up, its resultant acceleration is a=(-22.5î+ 20.2j) m/s , where î is the unit vector along the horizontal direction (you can treat it as pointing to the right), and j is the unit vector along the vertical direction (you can treat it as pointing upward). For that instant, (1) determine the magnitude of its centripetal acceleration in m/s? (ii) determine the speed of the ball in in m/s (iii) determine the velocity of the ball in m/s, i and j.arrow_forwardA ball swings counterclockwise in a vertical circle at the end of a rope 1.32 m long. When the ball is 36.3° past the lowest point on its way up, its total acceleration is (-20.2Î + 27.5ĵ) m/s². For that instant, do the following. (a) Sketch a vector diagram showing the components of its acceleration. (b) Determine the magnitude of its radial acceleration. |m/s² (c) Determine the velocity of the ball. magnitude m/s direction ° counterclockwise from the +î directionarrow_forward
- An object travels in a vertical circle of 1.43 m radius. When the object is traveling downward and is 28.0° from its lowest point, its total acceleration is a = (18.51 + 16.2ĵ) m/s². At this instant, determine the following. (Take the angle 28.0° clockwise from the axis of the circle that intersects the center and the lowest point. Assume that the +x axis is to the right and the +y axis is up along the page.) esc 7 (a) magnitude of the radial acceleration m/s² (b) magnitude of the tangential acceleration m/s² (c) speed of the object m/s (d) velocity of the object (Express your answer in vector form.) m/s v= 1 ² F1 Q A 1 N 2 Q F2 W S 3 X # H option command 80 F3 E D $ 4 C 990 GOD F4 R F % 67 8 5 F5 V T MacBook Air 6 G F6 Y B & 7 H 4 F7 U N 00 * 8 J FB 1 ( 9 M F9 K O O < A I -10 L || ! P V F11 1 + { [ 2 412 1 - option commandarrow_forwardA particle is traveling counterclockwise in a circle of radius r = 2.75m. At some instant in time, the particle is located by the angular coordinate alpha = 24o, the acceleration has a magnitude of 12 m/s2 and is directed at an angle beta = 20o with respect to the radial coordinate. Determine the velocity total acceleration. Give your answers in vector notation.arrow_forwardAn object travels in a vertical circle of 1.50 m radius. When the object is traveling downward and is 31.5° from its lowest point, its total acceleration is a = (18.5î + 16.2ĵ) m/s2. At this instant, determine the following. (Take the angle 31.5° clockwise from the axis of the circle that intersects the center and the lowest point. Assume that the +x axis is to the right and the +y axis is up along the page.) a)magnitude of radial acceleration b)magnitude of tangential acceleration c)speed of the object d)velocity of the object (Express your answer in vector form.)arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning