A car drives around a circular track of diameter 67 m at a constant speed of 35.5 m/s. During the time it takes the car to travel 157 degrees around, what is the magnitude of the car s average acceleration? O m/s^2 37.62 m/s^2 O 18.81 m/s^2 26.91 m/s^2

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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You can use the formula for centripetal acceleration OR You have to calculate the average acceleration directly from the definition, a = delta v / delta t.  You have to first get a_x by using the velocity's initial and final x components, do a_y from the y components, and then use the Pythagorean formula to get the magnitude of the acceleration vector.

A car drives around a circular track of diameter 67 m at a constant speed of 35.5 m/s. During the time it takes the car to travel 157 degrees around,
what is the magnitude of the car s average acceleration?
0 m/s^2
37.62 m/s^2
18.81 m/s^2
26.91 m/s^2
Transcribed Image Text:A car drives around a circular track of diameter 67 m at a constant speed of 35.5 m/s. During the time it takes the car to travel 157 degrees around, what is the magnitude of the car s average acceleration? 0 m/s^2 37.62 m/s^2 18.81 m/s^2 26.91 m/s^2
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