Chapter 4, Problem 40A

(a)

Interpretation Introduction

Interpretation:

The formula of binary compound is to be predicted.

Concept introduction:

The principle of electrical neutrality is followed when cation and anion combine together and form a neutral binary compound.

Answer to Problem 40A

  $N{a}_{2}S$

Explanation of Solution

  $N{a}^{+}$ has one positive charge and $S^{-2}$ has two negative charge. Thus, to maintain electrical neutrality, two ions of $N{a}^{+}$ are combined with one ion of $S^{-2}$ . So, the formula is $N{a}_{2}S$ .

(b)

Interpretation Introduction

Interpretation:

The formula of binary compound is to be predicted.

Concept introduction:

The principle of electrical neutrality is followed when cation and anion combine together and form a neutral binary compound.

Answer to Problem 40A

  $KCl$

Explanation of Solution

  $K^{+}$ has two unit positive charge and $C{l}^{-}$ has one unit negative charge. Thus, to maintain electrical neutrality, one ion of $K^{+}$ is combined with one ion of $C{l}^{-}$ . So, the formula is $KCl$ .

(c)

Interpretation Introduction

Interpretation:

The formula of binary compound is to be predicted.

Concept introduction:

The principle of electrical neutrality is followed when cation and anion combine together and form a neutral binary compound.

Answer to Problem 40A

  $BaO$

Explanation of Solution

  $B{a}^{2+}$ has two unit positive charge and $O^{2-}$ has two unit negative charge. Thus, to maintain electrical neutrality, one ion of $B{a}^{2+}$ is combined with one ion of $O^{2-}$ . So, the formula is $BaO$ .

(d)

Interpretation Introduction

Interpretation:

The formula of binary compound is to be predicted.

Concept introduction:

The principle of electrical neutrality is followed when cation and anion combine together and form a neutral binary compound.

Answer to Problem 40A

  $MgSe$

Explanation of Solution

  $M{g}^{2+}$ has two unit positive charge and $S{e}^{2-}$ has two unit negative charge. Thus, to maintain electrical neutrality, one ion of $M{g}^{2+}$ is combined with one ion of $S{e}^{2-}$ . So, the formula is $MgSe$ .

(e)

Interpretation Introduction

Interpretation:

The formula of binary compound is to be predicted.

Concept introduction:

The principle of electrical neutrality is followed when cation and anion combine together and form a neutral binary compound.

Answer to Problem 40A

  $CuB{r}_2$

Explanation of Solution

  $C{u}^{2+}$ has two unit positive charge and $B{r}^{-}$ has one unit negative charge. Thus, to maintain electrical neutrality, one ion of $C{u}^{2+}$ is combined with two ions of $B{r}^{-}$ . So, the formula is $CuB{r}_2$ .

(f)

Interpretation Introduction

Interpretation:

The formula of binary compound is to be predicted.

Concept introduction:

The principle of electrical neutrality is followed when cation and anion combine together and form a neutral binary compound.

Answer to Problem 40A

  $Al{I}_3$

Explanation of Solution

  $A{l}^{3+}$ has three unit positive charge and $I^{-}$ has one unit negative charge. Thus, to maintain electrical neutrality, one ion of $A{l}^{3+}$ is combined with three ions of $I^{-}$ . So, the formula is $Al{I}_3$ .

(g)

Interpretation Introduction

Interpretation:

The formula of binary compound is to be predicted.

Concept introduction:

The principle of electrical neutrality is followed when cation and anion combine together and form a neutral binary compound.

Answer to Problem 40A

  $A{l}_2{O}_3$

Explanation of Solution

  $A{l}^{3+}$ has three unit positive charge and $O^{2-}$ has two unit negative charge. Thus, to maintain electrical neutrality, two ions of $A{l}^{3+}$ is combined with three ions of $O^{2-}$ . So, the formula is $A{l}_2{O}_3$ .

(h)

Interpretation Introduction

Interpretation:

The formula of binary compound is to be predicted.

Concept introduction:

The principle of electrical neutrality is followed when cation and anion combine together and form a neutral binary compound.

Answer to Problem 40A

  $C{a}_3{N}_2$

Explanation of Solution

  $C{a}^{2+}$ has two unit positive charge and $N^{3-}$ has three unit negative charge. Thus, to maintain electrical neutrality, three ions of $C{a}^{2+}$ is combined with two ions of $N^{3-}$ . So, the formula is $C{a}_3{N}_2$ .