College Physics, Volume 1
2nd Edition
ISBN: 9781133710271
Author: Giordano
Publisher: Cengage
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 2Q
To determine
The corresponding angle
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A friend of yours has a one story house with a pool in the backyard. Someone gets the bright idea to jump from the roof of the house into the deep end of the pool. a) If the roof of the house is 16 ft tall and the horizontal distance between the edge of the house and the pool is 10 ft, what would the jumper's minimum velocity need to be to land in the pool?
b) Let's assume your friend can jump with an initial horizontal velocity of 15 ft/s. What is their total velocity when they hit the water? (hint: determine both the x and y velocity components, find the resultant)
You are walking around your neighborhood and you see a child on top of a roof of a building kick a soccer ball. The soccer ball is kicked at 50° from the edge of the building with an initial velocity of 10 m/s and lands 20 meters away from the wall of the building. Which equation will allow you to solve for the amount of time the ball is in the air? Hint: look at your givens in the x-direction.
Group of answer choices
A. vfx2=v0x2+2axΔx
B. vfx=v0x+axt
C. Δx =v0x t + ½ axt2
For a forensics experiment, a student decides to measure the muzzle velocity of the
pellets from his BB gun. She points the gun horizontally. On a vertical wall a
distance 47.3 m away from the gun, a target is placed. The shots hit the target a
vertical distance 0.10 m below the gun's barrel. What is the initial speed of the
pellets?
Your Answer:
units
Answer
Chapter 4 Solutions
College Physics, Volume 1
Ch. 4.1 - Prob. 4.1CCCh. 4.2 - Prob. 4.2CCCh. 4.2 - Prob. 4.3CCCh. 4.4 - Prob. 4.4CCCh. 4.5 - Prob. 4.5CCCh. 4.5 - Prob. 4.6CCCh. 4 - Prob. 1QCh. 4 - Prob. 2QCh. 4 - Prob. 3QCh. 4 - Prob. 4Q
Ch. 4 - Prob. 5QCh. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - Prob. 8QCh. 4 - Prob. 9QCh. 4 - Prob. 10QCh. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 14QCh. 4 - Prob. 15QCh. 4 - Prob. 16QCh. 4 - Prob. 17QCh. 4 - Prob. 18QCh. 4 - Prob. 19QCh. 4 - Prob. 20QCh. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Several forces act on a particle as shown in...Ch. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - The sled in Figure 4.2 is stuck in the snow. A...Ch. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - A bullet is fired from a rifle with speed v0 at an...Ch. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - An airplane flies from Boston to San Francisco (a...Ch. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - Two crates of mass m1 = 35 kg and m2 = 15 kg are...Ch. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61PCh. 4 - Consider the motion of a bicycle with air drag...Ch. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 70PCh. 4 - Prob. 71PCh. 4 - Prob. 72PCh. 4 - Prob. 73PCh. 4 - Prob. 74PCh. 4 - A vintage sports car accelerates down a slope of ...Ch. 4 - Prob. 76PCh. 4 - Prob. 77PCh. 4 - Prob. 78PCh. 4 - Prob. 79PCh. 4 - Prob. 80PCh. 4 - Prob. 81PCh. 4 - Prob. 82PCh. 4 - Prob. 83PCh. 4 - Prob. 84PCh. 4 - Prob. 85PCh. 4 - Prob. 86PCh. 4 - Two blocks of mass m1 = 2.5 kg and m2 = 3.5 kg...Ch. 4 - Prob. 88PCh. 4 - Prob. 89PCh. 4 - Prob. 90PCh. 4 - Prob. 91PCh. 4 - Prob. 92P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Messi is keeping his free-kick skills sharp this quarantine by playing football with his neighbour's monkey. From the roof of his house, which is 7 meters above the ground, he kicks a ball horizontally towards his neighbour's house, which is 6 meters away and also has a roof that is 7m above the ground. At the same instance, his neighbour's pet monkey drops off the ledge of his roof to try to catch the ball. Please ignore air resistance, and take g = 9.81m/s² Minimum velocity? What is the minimum speed (in m/s) at which Messi must kick the ball horizontally so that the monkey is able to catch it just before hitting the ground? Please provide your numerical answer to three significant figures; eq in the form x.xxarrow_forwardConsider a projectile on Earth, where +z is vertically upward. A cannon that is 1.50 m tall sits on the edge of a 50.0 m tall cliff oriented to fire in the +x direction. The cannon fires a 6.50 kg cannonball with an initial velocity of 110 m/s at an angle of 55° above the horizontal. Neglect air resistance. a) Write the acceleration of the cannon ball as a function of time as a column vector. b. write the canon ball's velocity as a function of time as a column vector c. write the canon ball's position as a function of time as a column vector d. how long does it take the canon ball to reach the highest point in it's trajectory e. what is the peak height the cannon ball attains pls provide answers in handwritten mannerarrow_forwardA playground is on the flat roof of a city school, hb = 6.40 m above the street below (see figure). The vertical wall of the building is h = 7.70 m high, to form a 1.3-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of ? = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. (a) Find the speed at which the ball was launched. m/s = (b) Find the vertical distance by which the ball clears the wall. m =(c) Find the horizontal distance from the wall to the point on the roof where the ball lands. m =arrow_forward
- Messi is keeping his free-kick skills sharp this quarantine by playing football with his neighbour's monkey. From the roof of his house, which is 7 meters above the ground, he kicks a ball horizontally towards his neighbour's house, which is 6 meters away and also has a roof that is 7m above the ground. At the same instance, his neighbour's pet monkey drops off the ledge of his roof to try to catch the ball. Please ignore air resistance, and take g=9.81m/s2 Minimum velocity? What is the minimum speed (in m/s) at which Messi must kick the ball horizontally so that the monkey is able to catch it just before hitting the ground? Time? If Messi kicks the ball with the minimum required speed; at what time (in seconds) after the kick is the monkey able to catch the ball? Please provide your numerical answer to three significant figures; eg in the form x.xxarrow_forwardThe 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply upward at the end. The sharp upward slope launches them into the air, where they perform acrobatic maneuvers. In the women's competition, the end of a typical launch ramp is directed 59° above the horizontal. With this launch angle, a skier attains a height of 14 m above the end of the ramp. What is the skier's launch speed?arrow_forwardA playground is on the flat roof of a city school, hb = 6.60 m above the street below (see figure). The vertical wall of the building is h = 7.80 m high, to form a 1.2-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of ? = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. A man on the ground kicking a ball to children on a flat rooftop is shown. The distance between the man and the building is labeled d. The height of the left wall of the building is labeled h. The motion of the ball is depicted as a parabola originating from the man on the ground and ending at the rooftop. The vector of the initial motion of the ball makes an angle ? with the horizontal.arrow_forward
- A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above the horizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to the horizontal. Relative to the coordinate system shown in the following figure, the equation of this straight line is y = (tan20°)x − 109. Where on the hill does the projectile land?arrow_forwardA playground is on the flat roof of a city school, hb = 6.70 m above the street below (see figure). The vertical wall of the building is h = 7.90 m high, to form a 1.2-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of ? = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. A man on the ground kicking a ball to children on a flat rooftop is shown. The distance between the man and the building is labeled d. The height of the left wall of the building is labeled h. The motion of the ball is depicted as a parabola originating from the man on the ground and ending at the rooftop. The vector of the initial motion of the ball makes an angle ? with the horizontal. (b) Find the vertical distance by which the ball clears the wall. m(c) Find the horizontal distance from the wall to the point on the roof where the…arrow_forwardHole number 7 at Pebble Beach golf course is one of the shortest championship holes in the world. The hole is only 100m away from the tee, and it is also 12m lower. Champion golfer Shooter McGavin hits a 9-iron at an angle of 50◦ with respect to the horizontal, and lands the ball right in the hole. Assume there is no wind or air resistance, and g = 9.8 m/s^2. (sin 50◦ = 0.766, cos 50◦ = 0.643, tan 50◦ = 1.19, sin 45◦ = 0.707, cos 45◦ = 0.707, tan 45◦ = 1.00). What is the initial velocity of the ball? How long was the ball in the air? What was the maximum height? If Shooter had misjudged the hole, and hit the ball with the same velocity but at an angle of 45◦ instead, by how much would he have overshot the hole?arrow_forward
- A playground is on the flat roof of a city school, hb = 6.70 m above the street below (see figure). The vertical wall of the building is h = 7.90 m high, to form a 1.2-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of ? = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. Question: (a) Find the speed at which the ball was launched.arrow_forwardA playground is on the flat roof of a city school, h = 6.00 m above the street below (see figure). The vertical wall of the building is h = 7.50 m high, to form a 1.5-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of 0 = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. (a) Find the speed at which the ball was launched. (No Response) m/s (b) Find the vertical distance by which the ball clears the wall. (No Response) m (c) Find the horizontal distance from the wall to the point on the roof where the ball lands. (No Response) marrow_forwardA projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above the horizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to the horizontal. Relative to the coordinate system shown in the figure, the equation of this straight y = (tan 20°) x - 109. Where on the hill does the projectile land? 75 m/s 60⁰ y = (tan 20°)x - 109 -300 m- 20⁰arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
Kinematics Part 3: Projectile Motion; Author: Professor Dave explains;https://www.youtube.com/watch?v=aY8z2qO44WA;License: Standard YouTube License, CC-BY