A playground is on the flat roof of a city school, h, = 6.70 m above the street below (see figure). The vertical wall of the building is h = 7.90 m high, to form a 1.2-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of 0 = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. (a) Find the speed at which the ball was launched. 18.0 m/s (b) Find the vertical distance by which the ball clears the wall. m (c) Find the horizontal distance from the wall to the point on the roof where the ball lands. m

Principles of Physics: A Calculus-Based Text
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Chapter3: Motion In Two Dimensions
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A playground is on the flat roof of a city school, hb = 6.70 m above the street below (see figure). The vertical wall of the building is h = 7.90 m high, to form a 1.2-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of ? = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall.

A man on the ground kicking a ball to children on a flat rooftop is shown. The distance between the man and the building is labeled d. The height of the left wall of the building is labeled h. The motion of the ball is depicted as a parabola originating from the man on the ground and ending at the rooftop. The vector of the initial motion of the ball makes an angle ? with the horizontal.


(b) Find the vertical distance by which the ball clears the wall.
 m

(c) Find the horizontal distance from the wall to the point on the roof where the ball lands.
 m
A playground is on the flat roof of a city school, h, = 6.70 m above the street below (see figure). The vertical wall of the building is h = 7.90 m high, to form a 1.2-m-high railing around the playground. A ball has
fallen to the street below, and a passerby returns it by launching it at an angle of 0 = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point
vertically above the wall.
(a) Find the speed at which the ball was launched.
18.0 V m/s
(b) Find the vertical distance by which the ball clears the wall.
m
(c) Find the horizontal distance from the wall to the point on the roof where the ball lands.
m
Transcribed Image Text:A playground is on the flat roof of a city school, h, = 6.70 m above the street below (see figure). The vertical wall of the building is h = 7.90 m high, to form a 1.2-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of 0 = 53.0° above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. (a) Find the speed at which the ball was launched. 18.0 V m/s (b) Find the vertical distance by which the ball clears the wall. m (c) Find the horizontal distance from the wall to the point on the roof where the ball lands. m
Expert Solution
Step 1

Height of playground above the street (hb) = 6.70 m Height of vertical wall of the building (h) = 7.90 m Railing of the wall around the playground (h1) = 1.2 m Angle of launch of the ball (θ) = 53oHorizontal distance of the building from the point of launch (d) = 24 m Time taken by the ball to reach a point vertically above the wall (t) = 2.20 seconds 

 

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