Organic Chemistry (8th Edition)
Organic Chemistry (8th Edition)
8th Edition
ISBN: 9780134042282
Author: Paula Yurkanis Bruice
Publisher: PEARSON
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Chapter 4, Problem 1P

a. Draw three constitutional isomers with molecular formula C3H8O.

b. How many constitutional isomers can you draw for C4H10.O?

(a)

Expert Solution
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Interpretation Introduction

Interpretation:

The three constitutional isomers of molecular formula C3H8O has to be drawn.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

The general formula for an alkane is CnH2n+2.

Equation for finding constitutional isomers for a molecule

Answer to Problem 1P

Organic Chemistry (8th Edition), Chapter 4, Problem 1P , additional homework tip  1

Explanation of Solution

The given molecular formula is C3H8O, it fulfils the general formula for an alkane CnH2n+2, so C3H8O contains only single bonds.

Therefore,

C3H8O can be an alcohol or ether.

The two possible alcohols are,

CH3CH2CH2OH , Organic Chemistry (8th Edition), Chapter 4, Problem 1P , additional homework tip  2

The possible ether is,

CH3CH2OCH3

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The numbers of constitutional isomers of molecular formula C4H10O has to be determined.

Concept introduction:

Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

Answer to Problem 1P

The numbers of constitutional isomers of molecular formula C4H10O is 7

Explanation of Solution

The given molecular formula is C4H10O, it fulfils the general formula for an alkane CnH2n+2, so C4H10O contains only single bonds.

Therefore,

C4H10O can be an alcohol or ether.

There will be five alcohol isomers (due to four carbons) and two ether isomers.

Hence,

C4H10O have 7 constitutional isomers.

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Chapter 4 Solutions

Organic Chemistry (8th Edition)

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