Physics for Scientists and Engineers with Modern Physics, Technology Update
Physics for Scientists and Engineers with Modern Physics, Technology Update
9th Edition
ISBN: 9781305401969
Author: SERWAY, Raymond A.; Jewett, John W.
Publisher: Cengage Learning
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Chapter 4, Problem 1OQ
To determine

The direction of the car’s average acceleration between these two points.

Expert Solution & Answer
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Answer to Problem 1OQ

Option (e) The resultant vector of average acceleration is directed towards South-West.

Explanation of Solution

As the car moves from point 1 to point 2, its speed doubles. Consider that speed at point 1 is v and speed at point 2 is 2v.

Write the expression for velocity vector at point 1 in xy plane as.

    v1=vj^

Here, v1 is velocity vector at point 1 and v is the velocity of car.

Write the expression for velocity vector at point 2 in xy plane as.

    v2=2v(i^)

Here, v2 is the velocity vector at point 2.

Write the expression for average acceleration as

  aavg=v2v1Δt                                                                                                (I)

Conclusion:

Substitute 2v(i^) for v2 and vj^ for v1 in equation (I).

    aavg=2v(i^)vj^Δt=2vi^vj^Δt

Draw the figure for the average acceleration for the above equation as.

Physics for Scientists and Engineers with Modern Physics, Technology Update, Chapter 4, Problem 1OQ

Thus option (e) is correct.

As per the above figure, the direction of arrow is towards North-East. The direction does not match with the resultant obtained. Thus option (a) is incorrect.

The direction of the average acceleration is towards North-West. The direction does not match with the resultant obtained. Thus option (b) is incorrect.

The direction of the average acceleration is towards North-West at some angle less that in option (b). This does not match with the resultant obtained. Thus, option (c) is incorrect.

The direction of average acceleration is towards west. This is not the resultant vector. Thus option (d) is incorrect.

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Chapter 4 Solutions

Physics for Scientists and Engineers with Modern Physics, Technology Update

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