Campbell Biology: Concepts & Connections (9th Edition)
Campbell Biology: Concepts & Connections (9th Edition)
9th Edition
ISBN: 9780134296012
Author: Martha R. Taylor, Eric J. Simon, Jean L. Dickey, Kelly A. Hogan, Jane B. Reece
Publisher: PEARSON
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Chapter 4, Problem 15TYK
Summary Introduction

To calculate: The surface area, volume, and ratio of surface area to volume of a spherical cell from the given data.

Introduction: The cells have different size as per their diameter and volume ratio. Cell surface to volume ratio” is important to maintain the cell functions.

Summary Introduction

To determine: How the surface-to-volume ratios of cell 1 and cell 2 are significant to their function.

Introduction: The cells have different size as per their diameter and volume ratio. Cell surface to volume ratio” is important to maintain the cell functions.

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A typical human hepatocyte (liver cell), a widely studied eukaryotic cell, has a diameter of about 20 μm. Calculate the volume of both a prokaryotic and a eukaryotic cell. To appreciate the magnitude of the size difference between the two cell types, estimate how many bacterial cells would fit inside the liver cell. (Hint: Use the expression V = πr 2h for the volume of a cylinder and V = (4/3)π r 3 .
To get an idea of the different sizes of various cellular components, do the following calculations: Assume that the cell, its nucleus, and a globular protein – for example, and enzyme – are spherical. In addition, assume the diameter of the protein is 5 nm (nanometers), the diameter of the cell is 100 μm (micrometers), and the diameter of the nucleus is 40 μm. You may have to review your metric conversions!   If you draw the globular protein as a sphere with a diameter of 2 cm (approximately the diameter of a U.S. penny), what size would each of the following measurements of the cell be if drawn to the same scale (5 nm real length  = 2 cm)? a.      The radius of a microtubule, 15 nm   b.      The diameter of the nucleus     c.      The diameter of the cell     d.      The volume (V = 4/3 ∏r3) of the globular protein, in decimal form to the hundredths place.   e.      The volume of the nucleus     f.       The volume of the cell
Calculate the surface-to-volume ratio of a spherical cell 15 μm indiameter and of a cell 2 μm in diameter. What are the consequencesof these differences in surface-to-volume ratio for cell function?
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