21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 4, Problem 11QP
To determine
The change in the tides on Earth, if the Moon is
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Currently, the moon goes around the earth once every 27.3 days. If the moon could be brought into a new circular orbit with a smaller radius, its orbital period would beA. More than 27.3 days.B. 27.3 days.C. Less than 27.3 days.
Each year, the radius of the moon’s orbit increases by about 3.8 cm. How does this change affect the length of a month?A. A month gets longer.B. A month gets shorter.C. The length of a month stays the same.
8. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of
Mercury from the Sun is 57.9 x 10° km. The period of Earth's revolutions is 1 year,
what is the period of Mercury's revolution?
a. 0.24 year on Earth
b. 0.42 year on Earth
C. 1.13 year on Earth
d. 1.31 year on Earth
9. The planet Delta has 2 times the gravitational field strength and 3 times the radius of
Earth. How does the mass of the planet Delta compare with the mass of Earth?
Chapter 4 Solutions
21st Century Astronomy
Ch. 4.1 - Prob. 4.1ACYUCh. 4.1 - Prob. 4.1BCYUCh. 4.2 - Prob. 4.2CYUCh. 4.3 - Prob. 4.3CYUCh. 4.4 - Prob. 4.4CYUCh. 4 - Prob. 1QPCh. 4 - Prob. 2QPCh. 4 - Prob. 3QPCh. 4 - Prob. 4QPCh. 4 - Prob. 5QP
Ch. 4 - Prob. 6QPCh. 4 - Prob. 7QPCh. 4 - Prob. 8QPCh. 4 - Prob. 9QPCh. 4 - Prob. 10QPCh. 4 - Prob. 11QPCh. 4 - Prob. 12QPCh. 4 - Prob. 13QPCh. 4 - Prob. 14QPCh. 4 - Prob. 15QPCh. 4 - Prob. 16QPCh. 4 - Prob. 17QPCh. 4 - Prob. 18QPCh. 4 - Prob. 19QPCh. 4 - Prob. 20QPCh. 4 - Prob. 21QPCh. 4 - Prob. 22QPCh. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Prob. 25QPCh. 4 - Prob. 26QPCh. 4 - Prob. 27QPCh. 4 - Prob. 28QPCh. 4 - Prob. 29QPCh. 4 - Prob. 30QPCh. 4 - Prob. 31QPCh. 4 - Prob. 32QPCh. 4 - Prob. 33QPCh. 4 - Prob. 34QPCh. 4 - Prob. 35QPCh. 4 - Prob. 36QPCh. 4 - Prob. 37QPCh. 4 - Prob. 38QPCh. 4 - Prob. 39QPCh. 4 - Prob. 40QPCh. 4 - Prob. 41QPCh. 4 - Prob. 42QPCh. 4 - Prob. 43QPCh. 4 - Prob. 44QPCh. 4 - Prob. 45QP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- According to Lunar Laser Ranging experiments the average distance LM from the Earth to the Moon is approximately 3.85 × 10° km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). How can the mass of the Earth be calculated using the information above? Select the correct statements. Select one or more: O a. Use Newton's third law. O b. Use Newton's first law. c. Use Coulombs law. O d. Use Newton's second law.arrow_forwardWhich of the following is a measurable effect of the tidal interactions between the Earth and the moon? choose 1 of the following: a. The moon is constantly getting closer to the Earth, and will one day collide with our planet. b. The rotation rate of the Earth is gradually slowing down. c. The rotation rate of the moon is gradually speeding up. d. The moon pulls more strongly on the far side of the Earth than it does on the near side.arrow_forwardThe friction created when tidal forces move ocean waters over the seabeds a. causes the lunar phases. b. slows the rotation of Earth, gradually making the days longer c. forces the moon to approach Earth. d. has no effect on Earth. e. has no effect on the moon.arrow_forward
- 1. Mars takes 1.88 years to complete one orbit around the sun. What is its average distance from the sun?arrow_forward6. Determine what the period of revolution of the Earth would be if its distance from the Sun were 4 AU rather than 1 AU. Assume that the mass of the Sun remains the same.arrow_forward1. The reason that there are two daily tides on Earth is that one occurs when the sun is overhead and the other when the Moon is overhead. True or False 2. Tides are approximately 24 hours apart. True or Falsearrow_forward
- 2. An unknown planet was accidentally discovered by NASA. It has a mean distance of 2.15 E11 meters from the sun. Assuming it has a mass of 6.02 E24 kg, how long (in Earth Years) will it take for the said planet to revolve around the sun?arrow_forwardThe rotation of the planets around the sun is governed by: A. The gravitational field of the sun. B. The gravity of the stars. C. The heat energy of the sun. D. The gravity of the other planets of the solar system. Kelper's second law relates between them: O A. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the sun. OB. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the earth. C. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the moon. OD. The time period of rotation of the orbiting planet around the earth and the average distance of the planet to the sun.arrow_forward1. The tides are present on earth because... A) the sun causes the earth to orbit B) the moon has a negligible gravitational effect on the earth except for in the oceans C) there is a different force of gravity acting on either side of the earth resulting from the moon D) tectonic plates shift as the earth rotates causing the water levels to vary.arrow_forward
- 7. What is the gravity constant in our planet? a. 10 m/s2 b. 2.3 m/s2 c. 1.0 m/s2 d. 9.8 m/s2arrow_forward6. A synchronous orbit is an orbit about a planet's equator that always remains above the same spot of the planet because the synchronous orbit matches the planet's rotational period. The pilot of the Mars spacecraft (which was named Cheetah 1 and had a 9556 kg mass) asked Tarzan to calculate the altitude of a synchronous orbit so they could remain over a particular geological feature on the Martian equator. Calculate the altitude above the Martian equator using the data above and Johannes Kepler's genius.arrow_forward25. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of Mercury from the Sun is 57.9 x 106 km. The period of Earth's revolutions is 1 year, what is the period of Mercury's revolution? a. 0.24 year on Earth b. 0.42 year on Earth C. 1.13 year on Earth d. 1.31 year on Eartharrow_forward
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