21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 4, Problem 33QP
To determine
The mass of the Sun.
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To model a moon in the solar system, consider a sphere with radius R
and uniform mass density p. Let gm = the acceleration due to gravity
on the surface of the sphere. Calculate gm for these values of R and p:
R = 2.0×106 m; p= 2.7x103 kg/m^3;
(in m/s^2)
OA:
OB:
1.509 2.007
OC:
2.669
OD:
3.549
OE:
OF:
4.721 6.279
OG:
8.351
OH:
1.111x101
According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is approximately 3.82 x 105 km. The Moon orbits the
Earth and completes one revolution relative to the stars in approximately 27.5 days (a sidereal month).
Calculate the orbital velocity of the Moon in m/s.
A)At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law.
Chapter 4 Solutions
21st Century Astronomy
Ch. 4.1 - Prob. 4.1ACYUCh. 4.1 - Prob. 4.1BCYUCh. 4.2 - Prob. 4.2CYUCh. 4.3 - Prob. 4.3CYUCh. 4.4 - Prob. 4.4CYUCh. 4 - Prob. 1QPCh. 4 - Prob. 2QPCh. 4 - Prob. 3QPCh. 4 - Prob. 4QPCh. 4 - Prob. 5QP
Ch. 4 - Prob. 6QPCh. 4 - Prob. 7QPCh. 4 - Prob. 8QPCh. 4 - Prob. 9QPCh. 4 - Prob. 10QPCh. 4 - Prob. 11QPCh. 4 - Prob. 12QPCh. 4 - Prob. 13QPCh. 4 - Prob. 14QPCh. 4 - Prob. 15QPCh. 4 - Prob. 16QPCh. 4 - Prob. 17QPCh. 4 - Prob. 18QPCh. 4 - Prob. 19QPCh. 4 - Prob. 20QPCh. 4 - Prob. 21QPCh. 4 - Prob. 22QPCh. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Prob. 25QPCh. 4 - Prob. 26QPCh. 4 - Prob. 27QPCh. 4 - Prob. 28QPCh. 4 - Prob. 29QPCh. 4 - Prob. 30QPCh. 4 - Prob. 31QPCh. 4 - Prob. 32QPCh. 4 - Prob. 33QPCh. 4 - Prob. 34QPCh. 4 - Prob. 35QPCh. 4 - Prob. 36QPCh. 4 - Prob. 37QPCh. 4 - Prob. 38QPCh. 4 - Prob. 39QPCh. 4 - Prob. 40QPCh. 4 - Prob. 41QPCh. 4 - Prob. 42QPCh. 4 - Prob. 43QPCh. 4 - Prob. 44QPCh. 4 - Prob. 45QP
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- If the mass of Jupiter is defined as 1 MJ = 1.90 ✕ 1027 kg, what is the mass of Saturn (5.68 ✕ 1026 kg) in units of MJ? What is the mass of Venus (4.86 ✕ 1024 kg) in MJ? What is the mass of Earth (5.97 ✕ 1024 kg) in MJ?arrow_forwardThe Sun’s center is at one focus of Earth’s orbit. How far from this focus is the other focus, (a) in meters and (b) in terms of the solar radius, 6.96 *10^8 m? The eccentricity is 0.0167, and the semimajor axis is 1.50 * 10^11 m.arrow_forwardAccording to Lunar Laser Ranging experiments the average distance L M from the Earth to the Moon is approximately 3.85 × 105 km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). Calculate mass of the Eartharrow_forward
- The Magellan orbiter orbits Venus with a period of 3.26 hours. How far (in km) above the surface of the planet is it? (The mass of Venus is 4.87 ✕ 1024 kg, and the radius of Venus is 6.05 ✕ 103 km.)arrow_forwardLike all planets, the planet Venus orbits the Sun in periodic motion and simultaneously spins about its axis. Just as on Earth, the time to make one complete orbit (i.e., the period of orbit) is what defines a year. And the time to make one complete revolution about its axis (i.e., the period of rotation) is what defines a day. The period of orbit for the Earth is 365.25 days and the period of rotation is 24 hours (1.00 day). But when these same values for Venus are expressed relative to Earth, it is found that Venus has a period of orbit of 225 days and a period of rotation of 243 days. So for Venus inhabitants, a day would last longer than a year! Determine the frequency of orbit and the frequency of rotation (in Hertz) on Venus.arrow_forwardNeptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x10^30 kg, use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). C) Convert the period in part b) to years (Round to the nearest tenth)arrow_forward
- Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1 A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x 10^30 kg , use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). c) Convert the period in part b) to years(Round to the nearest tenth).arrow_forwardCompare the masses of the Sun (1.99×10° kg) and Earth (5.98×10* kg).arrow_forwardWhat arc length does the Earth travel in a three month period in its nearly circular orbit about the sun with a radius of 1.5 x 10^(11) m?Required to answer. Single choice.arrow_forward
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