Precalculus: Mathematics for Calculus - 6th Edition
Precalculus: Mathematics for Calculus - 6th Edition
6th Edition
ISBN: 9780840068071
Author: Stewart, James, Redlin, Lothar, Watson, Saleem
Publisher: Cengage Learning
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Textbook Question
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Chapter 3.7, Problem 85E

Drug Concentration A drug is administered to a patient, and the concentration of the drug in the bloodstream is monitored. At time t ≥ 0 (in hours since giving the drug) the concentration (in mg/L) is given by

c ( t ) = 5 t t 2 + 1

Graph the function c with a graphing device.

  1. (a) What is the highest concentration of drug that is reached in the patient’s bloodstream?
  2. (b) What happens to the drug concentration after a long period of time?
  3. (c) How long does it take for the concentration to drop below 0.3 mg/L?

(a)

Expert Solution
Check Mark
To determine

The highest concentration of drug that is reached in the patient’s bloodstream.

Answer to Problem 85E

The highest concentration of drug reached in the patient’s bloodstream is 2.5 mg/L.

Explanation of Solution

Given:

The drug concentration in the bloodstream is given below,

c(t)=5tt2+1

Where tis the time in hours since giving the drug c is the concentration of drug in bloodstream in mg/L.

Calculation:

The given rational function is c(t) .

Sketch the graph of given rational function by graphing device,

Precalculus: Mathematics for Calculus - 6th Edition, Chapter 3.7, Problem 85E

Figure (1)

The highest concentration of drug is the maximum point in graph of rational function.

From the graph, the local maximum is (1,2.5) . So, the highest concentration reached in patient’s bloodstream is 2.5 mg/L.

(b)

Expert Solution
Check Mark
To determine

The drug concentration after a long period of time.

Explanation of Solution

From the Figure (1), it can be noticed that the graph of rational function decreases at the time increases.

Thus, the concentration of drug decreases to 0 after a long period of time.

(c)

Expert Solution
Check Mark
To determine

The time for the concentration to drop below 0.3 mg/L.

Answer to Problem 85E

The time for the concentration to drop below 0.3 mg/L is 16.6 hours.

Explanation of Solution

Given:

The drug concentration in the bloodstream is given below,

c(t)=5tt2+1

Where t is the time in hours since giving the drug and c is the concentration of drug in bloodstream in mg/L.

Calculation:

Substitute 0.3 for c(t) in given rational function to find the value of t,

0.3=5tt2+10.3t2+0.3=5t0.3t2−5t+0.3=0

Solve the above quadratic equation by following formula which is used to find the solutions for x if the quadratic equation is ax2+bx+c=0 ,

x=−b±b2−4ac2a

Substitute t for x, 5 for b, 0.3 for c and 0.3 for a in above given formula,

t=−(−5)±(−5)2−4⋅0.3⋅0.32⋅0.3=5±25−0.360.6=5±24.640.6=5±4.960.6

Take positive sign first and find the value of t,

t=5+4.960.6=9.960.6=16.6

Take negative sign and find the value of t,

t=5−4.960.6=0.040.6=0.066

From the Figure (1), the value of t, where the concentration drops below 0.3 mg/L is 16.6.

Thus, the time for the concentration to drop below 0.3 mg/L is 16.6 hours.

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Chapter 3.7, Problem 84E
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Chapter 3.7, Problem 86E

Chapter 3 Solutions

Precalculus: Mathematics for Calculus - 6th Edition

Ch. 3.1 - To put the quadratic function f(x)=ax2+bx+c in...Ch. 3.1 - The quadratic function f(x) = a(x - h)2 + k is in...Ch. 3.1 - The graph of f(x) = 3(x - 2)2 - 6 is a parabola...Ch. 3.1 - The graph of f(x) = -3(x - 2)2 - 6 is a parabola...Ch. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10E
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Possible Rational Zeros A polynomial function P...Ch. 3.4 - Possible Rational Zeros A polynomial function P...Ch. 3.5 - Prob. 1ECh. 3.5 - Prob. 2ECh. 3.5 - Prob. 3ECh. 3.5 - Prob. 4ECh. 3.5 - Prob. 5ECh. 3.5 - Prob. 6ECh. 3.5 - Prob. 7ECh. 3.5 - Prob. 8ECh. 3.5 - Prob. 9ECh. 3.5 - Prob. 10ECh. 3.5 - Prob. 11ECh. 3.5 - Prob. 12ECh. 3.5 - Prob. 13ECh. 3.5 - Prob. 14ECh. 3.5 - Prob. 15ECh. 3.5 - Prob. 16ECh. 3.5 - Prob. 17ECh. 3.5 - Prob. 18ECh. 3.5 - Prob. 19ECh. 3.5 - Prob. 20ECh. 3.5 - Prob. 21ECh. 3.5 - Prob. 22ECh. 3.5 - Prob. 23ECh. 3.5 - Prob. 24ECh. 3.5 - Prob. 25ECh. 3.5 - Prob. 26ECh. 3.5 - Prob. 27ECh. 3.5 - Prob. 28ECh. 3.5 - Prob. 29ECh. 3.5 - Prob. 30ECh. 3.5 - Prob. 31ECh. 3.5 - Prob. 32ECh. 3.5 - Prob. 33ECh. 3.5 - Prob. 34ECh. 3.5 - Prob. 35ECh. 3.5 - Prob. 36ECh. 3.5 - Prob. 37ECh. 3.5 - Prob. 38ECh. 3.5 - Prob. 39ECh. 3.5 - Prob. 40ECh. 3.5 - Prob. 41ECh. 3.5 - Prob. 42ECh. 3.5 - Prob. 43ECh. 3.5 - Prob. 44ECh. 3.5 - Prob. 45ECh. 3.5 - Prob. 46ECh. 3.5 - Prob. 47ECh. 3.5 - 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Prob. 88ECh. 3.7 - Prob. 89ECh. 3.7 - Prob. 90ECh. 3.7 - Prob. 91ECh. 3.7 - Prob. 92ECh. 3 - Prob. 1RCCCh. 3 - Prob. 2RCCCh. 3 - Prob. 3RCCCh. 3 - Prob. 4RCCCh. 3 - Prob. 5RCCCh. 3 - Prob. 6RCCCh. 3 - Prob. 7RCCCh. 3 - Prob. 8RCCCh. 3 - Prob. 9RCCCh. 3 - Prob. 10RCCCh. 3 - Prob. 11RCCCh. 3 - Prob. 12RCCCh. 3 - Prob. 13RCCCh. 3 - Prob. 1RECh. 3 - Prob. 2RECh. 3 - Prob. 3RECh. 3 - Prob. 4RECh. 3 - Prob. 5RECh. 3 - Prob. 6RECh. 3 - Prob. 7RECh. 3 - Prob. 8RECh. 3 - Prob. 9RECh. 3 - Prob. 10RECh. 3 - Prob. 11RECh. 3 - Prob. 12RECh. 3 - Prob. 13RECh. 3 - Prob. 14RECh. 3 - Prob. 15RECh. 3 - Prob. 16RECh. 3 - Prob. 17RECh. 3 - Prob. 18RECh. 3 - Prob. 19RECh. 3 - Prob. 20RECh. 3 - Prob. 21RECh. 3 - Prob. 22RECh. 3 - Prob. 23RECh. 3 - Prob. 24RECh. 3 - Prob. 25RECh. 3 - Prob. 26RECh. 3 - Prob. 27RECh. 3 - Prob. 28RECh. 3 - Prob. 29RECh. 3 - Prob. 30RECh. 3 - Prob. 31RECh. 3 - Prob. 32RECh. 3 - Prob. 33RECh. 3 - Prob. 34RECh. 3 - Prob. 35RECh. 3 - Prob. 36RECh. 3 - Prob. 37RECh. 3 - Prob. 38RECh. 3 - Prob. 39RECh. 3 - Prob. 40RECh. 3 - Prob. 41RECh. 3 - Prob. 42RECh. 3 - Prob. 43RECh. 3 - Prob. 44RECh. 3 - Prob. 45RECh. 3 - Prob. 46RECh. 3 - Prob. 47RECh. 3 - Prob. 48RECh. 3 - Prob. 49RECh. 3 - Prob. 50RECh. 3 - Prob. 51RECh. 3 - Prob. 52RECh. 3 - Prob. 53RECh. 3 - Prob. 54RECh. 3 - Prob. 55RECh. 3 - Prob. 56RECh. 3 - Prob. 57RECh. 3 - Prob. 58RECh. 3 - Prob. 59RECh. 3 - Prob. 60RECh. 3 - Prob. 61RECh. 3 - Prob. 62RECh. 3 - Prob. 63RECh. 3 - Prob. 64RECh. 3 - Prob. 65RECh. 3 - Prob. 66RECh. 3 - Prob. 67RECh. 3 - Prob. 68RECh. 3 - Prob. 69RECh. 3 - Prob. 70RECh. 3 - Prob. 71RECh. 3 - Prob. 72RECh. 3 - Prob. 73RECh. 3 - Prob. 74RECh. 3 - Prob. 75RECh. 3 - Prob. 76RECh. 3 - Prob. 77RECh. 3 - Prob. 78RECh. 3 - Prob. 79RECh. 3 - Prob. 80RECh. 3 - Prob. 81RECh. 3 - Prob. 82RECh. 3 - Prob. 83RECh. 3 - Prob. 84RECh. 3 - Prob. 85RECh. 3 - Prob. 86RECh. 3 - Express the quadratic function f(x) = x2 x 6 in...Ch. 3 - Find the maximum or minimum value of the quadratic...Ch. 3 - A cannonball fired out to sea from a shore battery...Ch. 3 - Graph the polynomial P(x) = (x + 2)3 + 27, showing...Ch. 3 - (a) Use synthetic division to find the quotient...Ch. 3 - Let P(x) = 2x3 5x2 4x + 3. (a) List all possible...Ch. 3 - Prob. 7TCh. 3 - Find all real and complex zeros of P(x) = x3 x2 ...Ch. 3 - Find the complete factorization of P(x) = x4 2x3...Ch. 3 - Find a fourth-degree polynomial with integer...Ch. 3 - Let P(x) = 2x4 7x3 + x2 18x + 3. (a) Use...Ch. 3 - Prob. 12TCh. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - How Fast Can You List Your Favorite Things? If you...Ch. 3 - Prob. 4PCh. 3 - Height of a Baseball A baseball is thrown upward,...Ch. 3 - Torricelli's Law Water in a tank will flow out of...
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08 - Conic Sections - Hyperbolas, Part 1 (Graphing, Asymptotes, Hyperbola Equation, Focus); Author: Math and Science;https://www.youtube.com/watch?v=Ryj0DcdGPXo;License: Standard YouTube License, CC-BY