Chapter 3.4, Problem 38PPS

To determine

To write in point-slope form for the line parallel to $y=7$ and contain $(-1,-10)$

Answer to Problem 38PPS

Slope intercept form

  $y=-10$

Explanation of Solution

Given information:

Line parallel to $y=7$ and contain $(-1,-10)$

Formula used:

Point-slope form

  $y-y_1=m(x-x_1)$

Calculation:

Let required line is $y=m_{1}x+c$

Here

  $m_1$ is slope of required line

  $c$ is y-intercept of required line

Given line

  $y=7$

Then slope of given line

  $m_2=0$

When lines are parallel

Then

  $m_1=m_2$

Then slope of required line is

  $m_1=0$

Point containing $(-1,-10)$

  $x_1=-1$

  $y_1=-10$

Using point slope formula

  $y-(-10)=0(x-(-1))$

On solving

  $y+10=0$

Subtract 10 both sides

  $y+10-10=0-10$

On solving

  $y=-10$

Hence, slope intercept form is $y=-10$