Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
8th Edition
ISBN: 9780134015187
Author: John E. McMurry, David S. Ballantine, Carl A. Hoeger, Virginia E. Peterson
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 3.10, Problem 3.5CIAP
Interpretation Introduction
Interpretation: The reason for RTIL in liquid to be predicted.
Concept Introduction:
Properties of ionic compound: Ionic compounds are usually crystalline solids. Ions are generally varies in size and charges, so ions are packed together in different ways in crystal. Ionic compounds dissolves in water if the attraction between the ion and the water molecule overcomes the attraction of the ions for one another.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Ionic interactions are weaker in water than they are in an anhydrous medium. Describe how water reduces the strength of these interactions.
An aqueous solution contains 0.448 M dimethylamine ((CH3)2NH).How many mL of 0.240 M hydroiodic acid would have to be added to 150 mL of this solution in order to prepare a buffer with a pH of 10.500? ______________ml
An aqueous antifreeze solution is 45.0% ethylene glycol () by mass. The density of the solution is 1.05. Calculate the molality, molarity, and mole fraction of the ethylene glycol
Chapter 3 Solutions
Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
Ch. 3.1 - Magnesium atoms lose two electrons when they...Ch. 3.1 - Prob. 3.2PCh. 3.1 - Prob. 3.3KCPCh. 3.2 - Prob. 3.4PCh. 3.2 - Prob. 3.5PCh. 3.2 - Prob. 3.6KCPCh. 3.3 - Iron is an important component of hemoglobin, a...Ch. 3.3 - Prob. 3.8PCh. 3.3 - Blood serum in healthy adults normally contains...Ch. 3.4 - Prob. 3.10P
Ch. 3.4 - Which element in the following pairs is likely to...Ch. 3.4 - Prob. 3.12PCh. 3.5 - Prob. 3.1CIAPCh. 3.5 - Prob. 3.13PCh. 3.5 - Prob. 3.14PCh. 3.5 - Prob. 3.15PCh. 3.6 - Prob. 3.16PCh. 3.6 - Prob. 3.17PCh. 3.6 - Prob. 3.3CIAPCh. 3.6 - Prob. 3.4CIAPCh. 3.8 - Prob. 3.18PCh. 3.8 - Prob. 3.19PCh. 3.8 - Prob. 3.20PCh. 3.8 - Prob. 3.21KCPCh. 3.9 - Prob. 3.22PCh. 3.9 - Name the following compounds: (a)SnO2 (b)Ca(CN)2...Ch. 3.9 - Prob. 3.24PCh. 3.9 - Prob. 3.25KCPCh. 3.10 - Prob. 3.26PCh. 3.10 - Prob. 3.5CIAPCh. 3.11 - Prob. 3.27PCh. 3.11 - Prob. 3.28KCPCh. 3.11 - Prob. 3.7CIAPCh. 3 - Prob. 3.29UKCCh. 3 - Prob. 3.30UKCCh. 3 - Write the symbols for the ions represented in the...Ch. 3 - Prob. 3.32UKCCh. 3 - Prob. 3.33UKCCh. 3 - Prob. 3.34UKCCh. 3 - Prob. 3.35UKCCh. 3 - Prob. 3.36UKCCh. 3 - Prob. 3.37APCh. 3 - Prob. 3.38APCh. 3 - Prob. 3.39APCh. 3 - Prob. 3.40APCh. 3 - Prob. 3.41APCh. 3 - Identify the element X in the following ions and...Ch. 3 - Prob. 3.43APCh. 3 - Prob. 3.44APCh. 3 - Based on the following atomic numbers and...Ch. 3 - Prob. 3.46APCh. 3 - Prob. 3.47APCh. 3 - Prob. 3.48APCh. 3 - Prob. 3.49APCh. 3 - Prob. 3.50APCh. 3 - Prob. 3.51APCh. 3 - Prob. 3.52APCh. 3 - Prob. 3.53APCh. 3 - Prob. 3.54APCh. 3 - Prob. 3.55APCh. 3 - Prob. 3.56APCh. 3 - (a)Write equations for the loss of an electron by...Ch. 3 - Prob. 3.58APCh. 3 - Prob. 3.59APCh. 3 - Prob. 3.60APCh. 3 - Prob. 3.61APCh. 3 - Prob. 3.62APCh. 3 - Prob. 3.63APCh. 3 - Prob. 3.64APCh. 3 - Prob. 3.65APCh. 3 - Prob. 3.66APCh. 3 - Prob. 3.67APCh. 3 - Prob. 3.68APCh. 3 - Prob. 3.69APCh. 3 - Prob. 3.70APCh. 3 - Prob. 3.71APCh. 3 - Prob. 3.72APCh. 3 - Prob. 3.73APCh. 3 - Prob. 3.74APCh. 3 - Prob. 3.75APCh. 3 - Prob. 3.76APCh. 3 - Give the formula and the name of the anions for...Ch. 3 - Explain why the hydride ion, H, has a noble gas...Ch. 3 - The H ion (Problem 3.78) is stable but the Li ion...Ch. 3 - Prob. 3.80CPCh. 3 - Prob. 3.81CPCh. 3 - The names given for the following compounds are...Ch. 3 - The formulas given for the following compounds are...Ch. 3 - Prob. 3.84CPCh. 3 - Element X reacts with element Y to give a product...Ch. 3 - Prob. 3.86CPCh. 3 - The term alum" refers to a group of ionic...Ch. 3 - Prob. 3.88GPCh. 3 - Prob. 3.89GPCh. 3 - Prob. 3.90GP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.Similar questions
- A patient’s treatment plan requires two IV solutions to be administered:20% magnesium sulfate, MgSO4, and 10% calcium chloride, CaCl2. Thenurse is concerned, MgSO4 and CaCl2 are listed as incompatible IVsolutions with the risk of solid precipitate formation (image shown toright). Write the chemical equation that predicts the products thatform when combining MgSO4 and CaCl2. Please use the providedsolubility chart to help you determine chemical phases.arrow_forwardCalculate the theoretical pH of a Tris buffer (pH 8.0) at 0 ºC. Assume that room temperature is 22 ºCarrow_forwardCalculate the molarity of dilute Ca(OH)2 solution if the titration of 30.00 mL of 0.05231 M HCl required 24.76 mL of the acid. An 0.2500 g hydroxide tablet sample submitted in the lab used 36.75 mL during titration. How much is the hydroxide in mg present?arrow_forward
- A base is added to a 0.050 M solution of MnCl2, raising the pH gradually. Calculate the pH of the solution when 88 of the manganese has precipitated? Table 5-7 Solubility-Product Constants, K, at 25°C Fluorides Chromates (cont.) Ag, Cro, PbCro, Hydroxides (cont) Ni(OH), Zn(OH), Cu(OH), Hg(OH), Sn(OH), Cr(OH), A(OH), BaF, MgF, PbF, SrF, CaF, 2.4 x 10-5 X 10-8 x 10-8 1.9 x 10-12 1.6 x 10-16 4.5 X 10-17 1.6 x 10-19 3 2 x 10-16 4 Carbonates 7.9 x 10-10 3.9 x 10-11 X 10-26 NiCO, CaCO, BaCo, SrCO, CuCO, ZnCO, MnCO, 1.4 x 10-7 3 10-27 4.7 x 10- 6.7 x 5 x 6 x 10-38 2.5 x 10-43 Chlorides 10-31 1.6 x 10- 1.7 x 10-10 1.1 x 10-18 1.6 x 10-9 7 x 10-10 2.5 x 10-10 10-33 PBCI, AgCi Hg,Cl, Fe(OH), Co(OH), Sulfides 2 x 10-10 8.8 x 10-11 2.1 x 10-11 Bromides X 10-16 X 10-19 3 x 10-21 X 10-22 2.5 x 10-22 X 10-26 1.0 x 10-28 MnS 7. PbBr, AgBr Hg, Br, 4.6 x 10-6 5.0 x 10-13 Feco Ag,CO, CdCo, PBCO, MgCO, Hg,CO, Fes 4 8.2 x 10-12 5.2 x 10-12 1.5 x 10-15 1 x 10-15 NiS 1.3 x 10-22 Cos ZnS lodides Pbl, Agl…arrow_forwardGiven Reactants: Sodium Hydroxide (NaOH) Potassium Permanganate (KMnO4) Glucose (C₆H₁₂O₆) Find the following: 1. Molecular equation 2. Total ionic equation 3. Net ionic equationarrow_forwardWhat is the molarity of the following solution: 47g of KCl dissolved in enough water to give 375 mL of solutionarrow_forward
- A base is added to a 0.050 M solution of MnCl2, raising the pH gradually. Calculate the pH of the solution when 70 of the manganese has precipitated? Table 5-7 Solubility-Product Constants, K, at 25°C Fluorides Chromates (cont.) Ag, Cro, PbCro, Hydroxides (cont.) Ni(OH), Zn(OH), Cu(OH), Hg(OH)2 Sn(OH), Cr(OH), Al(OH), Fe(OH), Co(OH), Sulfides Baf, MGF2 PbF, SrF, CaF, 2.4 x 10-6 1.9 x 10-12 1.6 x 10-16 8 x 10-8 X 10-8 7.9 x 10-10 3.9 x 10-11 2 x 10-16 4.5 X 10-17 4 1.6 x 10-19 X 10-26 X 10-27 6.7 x 10-31 Carbonates NiCO, CaCO, BaCO, SrCO, CuCO, ZnCO, MNCO, FeCo, Ag,CO, CdCo, PbCO, M9CO, Hg,CO, 1.4 X 10-7 4.7 x 10-9 3. Chlorides 1.6 x 10-9 PbCl, AgCI Hg,Cl, х 10-33 X 10-38 2.5 x 10-43 1.6 x 10-5 X 10-10 2.5 x 10-10 2 x 10-1o 8.8 x 10-11 2.1 X 10-11 7 1.7 x 10-10 1.1 X 10-18 6. Bromides PbBr2 X 10-16 X 10-19 X 10-21 5 x 10-22 2.5 x 10-22 X 10-26 1.0 x 10-28 MnS 4.6 x 10-6 5.0 x 10-13 Fes 4. AgBr Hg,Br, 8.2 x 10-12 NiS Cos Zns 1.3 x 10-22 3 5.2 x 10-12 1.5 x 10-15 1 x 10-15 9.0 x 10-15…arrow_forwardoriginal molarity= .548 A 5.00 mL sample of this KOH solution is added to a 100 mL volumetric flask, and water is added to the mark. What is the new molarity of K+ ions in this solution?arrow_forwardWhat mass of sodium glycolate (NaC2H3O3) should be added to 400.0 mL of 1.00 M glycolic acid to produce a buffer solution with a pH of 4.00? Ka = 1.47 x 10-4. Please indicate the full solutions.arrow_forward
- An aqueous solution contains 0.34 M potassium cyanide. One liter of this solution could be converted into a buffer by the addition of: (Assume that the volume remains constant as each substance is added.) 0.34 mol HCI04 0.16 mol NaOH 0.33 mol KCIO4 0.16 mol HCIO4 0.33 mol HCNarrow_forwardEmergency treatment of cardiac arrest victims sometimes involves injection of a calcium chloride solution directly into the heart muscle. How many grams of CaCl2 are administered in an injection of 5.0 mL of a 5.0% 1m/v2 solution? How many milliequivalents of Ca2+?arrow_forwardmeasured by molarity (M), which is the number of moles per liter of solution (moles/L). For example, 1M = 1 mole/L. To determine how many grams of a substance is equal to one mole the molecular mass is needed (we will not explore this in this lab rather this is taught in your Chemistry subjects). The general formula for making a dilution solution is the following: CıV1 = C2V2 where C: = the original concentration of stock solution Vi = the volume of stock solution needed to make working solution C2 = the desired concentration of working solution V: = the desired final volume of working solution For Educational Purposes Only SLSU-TO/NCMatondo 18 What would be the working stock concentration (in molarity) if you diluted 250 ul of a stock concentration of 10 µM in a total volume of 1 mL? LAB EXERCISE NO. 4. PATTERN OF INHERITANCEarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
GCSE Chemistry - Acids and Bases #34; Author: Cognito;https://www.youtube.com/watch?v=vt8fB3MFzLk;License: Standard youtube license