Videos
(a)
Interpretation:
The formula of the given hydroxide ion has to be written
Concept Introduction:
Polyatomic Ions:
An ion that is composed of more than one atom.
Naming polyatomic Ions:
When anions contain the same two types of atoms and one of them is oxygen, the one with the fewer oxygen atoms is named with an ‘-ite’ ending and the one with the greater number of oxygen atoms is named with an ‘-ate’ ending.
The prefix ‘per-’ is used for the ion with the most oxygen atoms. ‘Hypo-’ is used for the ion with the least oxygen atoms.
Naming Anions:
Anions are named by replacing the end of the element name with ‘-ide’, followed by the word ‘ion’.
(b)
Interpretation:
The formula of the given bisulfate ion has to be written
Concept Introduction:
Polyatomic Ions:
An ion that is composed of more than one atom.
Naming polyatomic Ions:
When anions contain the same two types of atoms and one of them is oxygen, the one with the fewer oxygen atoms is named with an ‘-ite’ ending and the one with the greater number of oxygen atoms is named with an ‘-ate’ ending.
The prefix ‘per-’ is used for the ion with the most oxygen atoms. ‘Hypo-’ is used for the ion with the least oxygen atoms.
Naming Anions:
Anions are named by replacing the end of the element name with ‘-ide’, followed by the word ‘ion’.
(c)
Interpretation:
The formula of the given acetate ion has to be written
Concept Introduction:
Polyatomic Ions:
An ion that is composed of more than one atom.
Naming polyatomic Ions:
When anions contain the same two types of atoms and one of them is oxygen, the one with the fewer oxygen atoms is named with an ‘-ite’ ending and the one with the greater number of oxygen atoms is named with an ‘-ate’ ending.
The prefix ‘per-’ is used for the ion with the most oxygen atoms. ‘Hypo-’ is used for the ion with the least oxygen atoms.
Naming Anions:
Anions are named by replacing the end of the element name with ‘-ide’, followed by the word ‘ion’.
(d)
Interpretation:
The formula of the given permanganate ion has to be written
Concept Introduction:
Polyatomic Ions:
An ion that is composed of more than one atom.
Naming polyatomic Ions:
When anions contain the same two types of atoms and one of them is oxygen, the one with the fewer oxygen atoms is named with an ‘-ite’ ending and the one with the greater number of oxygen atoms is named with an ‘-ate’ ending.
The prefix ‘per-’ is used for the ion with the most oxygen atoms. ‘Hypo-’ is used for the ion with the least oxygen atoms.
Naming Anions:
Anions are named by replacing the end of the element name with ‘-ide’, followed by the word ‘ion’.
(e)
Interpretation:
The formula of the given hypochlorite ion has to be written
Concept Introduction:
Polyatomic Ions:
An ion that is composed of more than one atom.
Naming polyatomic Ions:
When anions contain the same two types of atoms and one of them is oxygen, the one with the fewer oxygen atoms is named with an ‘-ite’ ending and the one with the greater number of oxygen atoms is named with an ‘-ate’ ending.
The prefix ‘per-’ is used for the ion with the most oxygen atoms. ‘Hypo-’ is used for the ion with the least oxygen atoms.
Naming Anions:
Anions are named by replacing the end of the element name with ‘-ide’, followed by the word ‘ion’.
(f)
Interpretation:
The formula of the given nitrate ion has to be written
Concept Introduction:
Polyatomic Ions:
An ion that is composed of more than one atom.
Naming polyatomic Ions:
When anions contain the same two types of atoms and one of them is oxygen, the one with the fewer oxygen atoms is named with an ‘-ite’ ending and the one with the greater number of oxygen atoms is named with an ‘-ate’ ending.
The prefix ‘per-’ is used for the ion with the most oxygen atoms. ‘Hypo-’ is used for the ion with the least oxygen atoms.
Naming Anions:
Anions are named by replacing the end of the element name with ‘-ide’, followed by the word ‘ion’.
(g)
Interpretation:
The formula of the given carbonate ion has to be written
Concept Introduction:
Polyatomic Ions:
An ion that is composed of more than one atom.
Naming polyatomic Ions:
When anions contain the same two types of atoms and one of them is oxygen, the one with the fewer oxygen atoms is named with an ‘-ite’ ending and the one with the greater number of oxygen atoms is named with an ‘-ate’ ending.
The prefix ‘per-’ is used for the ion with the most oxygen atoms. ‘Hypo-’ is used for the ion with the least oxygen atoms.
Naming Anions:
Anions are named by replacing the end of the element name with ‘-ide’, followed by the word ‘ion’.
(h)
Interpretation:
The formula of the given dichromate ion has to be written
Concept Introduction:
Polyatomic Ions:
An ion that is composed of more than one atom.
Naming polyatomic Ions:
When anions contain the same two types of atoms and one of them is oxygen, the one with the fewer oxygen atoms is named with an ‘-ite’ ending and the one with the greater number of oxygen atoms is named with an ‘-ate’ ending.
The prefix ‘per-’ is used for the ion with the most oxygen atoms. ‘Hypo-’ is used for the ion with the least oxygen atoms.
Naming Anions:
Anions are named by replacing the end of the element name with ‘-ide’, followed by the word ‘ion’.
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Chapter 3 Solutions
Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
- An unknown mixture is known to contain only Ba(OH)2 (MW=171.34 g/mole) and NaOH (MW=40.0 g/mole). If the mixture is known to contain 45% by mass NaOH, and 8.0 grams of the mixture is dissolved completely in 50.0 ml of solution, answer the following. c).If 10.0 ml of a 0.2 M solution of Na2SO4 was added to the 50.0 ml solution, what would be the final concentration of Na+ in solution.arrow_forwardBenzalkonium chloride 17% w/v . . . . . qs Water qs . . . . . . . . . . . . . . . . . . . . . . 120 mL M. ft . solution such that 2 tbsp added to a pint of water will yield a 1:750 solution. How many milliliters of the 17% w/v stock solution will be needed to prepare the 120 mL? a 2.68 mL b 7.90 mL c 15.80 mL d 20.40 mL e 6.28 mLarrow_forwardFor each of the following reactions, give a balanced net-ionic equation. Sulfate Ion a) MgSO4 + H2SO4 b) MgSO4 + BaCl2 Sulfite Ion a) Na2SO3 + H2SO4 b) Na2SO3 + BaCl2 c) BaSO3 + HNO3 Iodide Ion a) NaI + NaOCl b) NaI + AgNO3 c) AgI + NH3 d) NaI + H2SO4arrow_forward
- A 35 mL of solution of hydrochloric acid is neutralized by 15 mL of 0.5 M potassium hydroxide. What is the concentration of hydrochloric acid? The balanced equation is HCI + KOH - H,O + KCI O 0.75 M O 0.25 M O 0.214 M O 0.786 Marrow_forwardWhich of the following compounds would you expect to have the highest boiling pointand which the lowest boiling point? Explain your answer.(a) CH3OCH3 (b) CH3COOH (c) CH3CH2CH3arrow_forwardGive the formulas for the ions in the following two ionic compoundscation (+) anion (-)ammonium chloride _________ _________sodium chloride _________ _________The bromide ion (made from bromine atoms) has the same charge as the chloride ion. Writethe chemical formula for the following two ionic compounds where the bromide ion issubstituted for the chloride ion.ammonium bromide = ________________; sodium bromide =____________________arrow_forward
- Write a skeletal equation for the following chemical change. Solid lithium reacts with chlorine gas to produce solid lithium chloride.arrow_forwardA 1.000-g sample containing bromide was dissolved in sufficient water to give 100.0 mL. A 50.00 mL aliquot was measured and after acidification, silver nitrate was introduced to precipitate AgBr, which was filtered, washed, and then dissolved in an ammoniacal solution of potassium tetracyanonickelate(II): Ni(CN)42- + 2AgBr(s) → 2Ag(CN)2- + Ni2+ + 2Br- The liberated nickel ion required 11.70 mL of 0.002146 M EDTA. The other 50.00 mL remaining solution was also analyzed for its Br- content by potentiometry using a metallic electrode of the second kind. e) Write the cell notation of the potentiometric set-up with SCE as the reference electrode. f) Write the Nernst equation that describes the indicator electrode set-up.arrow_forwardThe precipitation of three solid compounds: X, Y, Z, have the following equilibrium constants: Kx = 1.7 x 104 Ky = 0.6 x 108 Kz = 9.2 x 1012 Assuming a solution contains equal concentrations of ions to form these compounds, which among the three would have the least amount of precipitate at equilibrium? A) Not enough information в) х c) Y D) zarrow_forward
- 75 mL of 0.300 mol/L sodium phosphate solution is combined with 67.5 mL of 0.350 mol/L calcium bicarbonate. a)Before you begin your reaction, you must accurately produce 1.500 L of your sodium phosphate solution from sodium phosphate trihydrate solid. Write out a procedure to explain all the steps you will take in the lab when making the solution to ensure that your solution concentration is accurate. Please include calculations that show the required mass of solid. Also include the correct names of all equipment used. b)You have a super powerful microscope in your lab! You are able to zoom in on your sodium phosphate solution and take a picture at the molecular level. Label the diagram on the left with the correct choices from the box on the right. You may use arrows or rewrite the symbols in one appropriate place. c)In one sentence, explain what the diagram is showing.arrow_forwardCarbon dioxide is dissolved in blood (pH 7.4) to form a mixture of carbonic acid and bicarbonate. Neglecting free CO2, what fraction will be present as carbonic acid? Would you expect a significant amount of carbonate (CO32-)?arrow_forwardWrite balanced ionic equations and net ionic equations forthe following reactions: (a) Aqueous sulfuric acid is neutralized by aqueous potassiumhydroxide.(b) Aqueous magnesium hydroxide is neutralized by aqueoushydrochloric acid.arrow_forward
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