(a) Explanation Given info: The total energy is − 0 .85 eV . The expression for the kinetic energy of electron in Bohr orbit of hydrogen atom is, K = k e 2 r Here, K is the kinetic energy. k is the coulombs’ constant. e is the mass of electron. r is the radius. The expression for the total energy of electron in Bohr orbit of hydrogen atom is, E = − k e 2 r Therefore, Kinetic energy = − Total energy Substitute − 0 (b) To determine The electrical potential energy of the system.

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ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Question

Chapter 31, Problem 76GP

(a)

To determine

The kinetic energy of the electron in the given particular Bohr orbit.

(b)

To determine

The electrical potential energy of the system.

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Chapter 31, Problem 75GP

Chapter 31, Problem 77GP

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Chapter 31 Solutions

Physics (5th Edition)

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The kinetic energy of the electron in the given particular Bohr orbit.

Solution Summary: The author explains that the kinetic energy of the electron in the given particular Bohr orbit is -0 eV.

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The kinetic energy of the electron in the given particular Bohr orbit.

The electrical potential energy of the system.

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Chapter 31 Solutions