Physics (5th Edition)
5th Edition
ISBN: 9780321976444
Author: James S. Walker
Publisher: PEARSON
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Chapter 31, Problem 61PCE
To determine
The energy emitted by
K α
X-ray in Lead by Bohr model.
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The first line in the Lyman series of H is at 82257.098 cm-1, while that line in the spectrum of deuterium (D) is at 82281.476 cm-1.Check the option that contains the mass of the D nucleus, calculated from this spectral information.
Assume that h = 6,63 x 10-34 J.s, c = 2,99 x 108 m/s, m(elétron) = 9,11 x 10-31 kg e m(próton) = 1,67 x 10-27 kg
The Ka X-ray emission line of tungsten occurs at
λ = 0.021 nm. The energy difference between K and L levels
in this atoms is about
(a) 0.51 MeV (b) 1.2 MeV (c) 59 keV (d) 13.6 eV
Calculate the frequency, energy (in keV), and wavelength of the Ka x ray for the elements (a) calcium (Ca, Z = 20); (b) cobalt (Co, Z = 27); (c) cadmium (Cd, Z = 48).
Chapter 31 Solutions
Physics (5th Edition)
Ch. 31.1 - Prob. 1EYUCh. 31.2 - Prob. 2EYUCh. 31.3 - Prob. 3EYUCh. 31.4 - Prob. 4EYUCh. 31.5 - Prob. 5EYUCh. 31.6 - Prob. 6EYUCh. 31.7 - Prob. 7EYUCh. 31 - Prob. 1CQCh. 31 - Prob. 2CQCh. 31 - Prob. 3CQ
Ch. 31 - Prob. 4CQCh. 31 - Prob. 5CQCh. 31 - Prob. 6CQCh. 31 - Prob. 7CQCh. 31 - Prob. 8CQCh. 31 - Prob. 9CQCh. 31 - Prob. 1PCECh. 31 - Prob. 2PCECh. 31 - Prob. 3PCECh. 31 - Prob. 4PCECh. 31 - Prob. 5PCECh. 31 - Prob. 6PCECh. 31 - Prob. 7PCECh. 31 - Prob. 8PCECh. 31 - Prob. 9PCECh. 31 - Prob. 10PCECh. 31 - Prob. 11PCECh. 31 - Prob. 12PCECh. 31 - Prob. 13PCECh. 31 - Prob. 14PCECh. 31 - Prob. 15PCECh. 31 - Prob. 16PCECh. 31 - Prob. 17PCECh. 31 - Prob. 18PCECh. 31 - Prob. 19PCECh. 31 - Prob. 20PCECh. 31 - Prob. 21PCECh. 31 - Prob. 22PCECh. 31 - Prob. 23PCECh. 31 - Prob. 24PCECh. 31 - Prob. 25PCECh. 31 - Prob. 26PCECh. 31 - Prob. 27PCECh. 31 - Prob. 28PCECh. 31 - Prob. 29PCECh. 31 - Prob. 30PCECh. 31 - Prob. 31PCECh. 31 - Prob. 32PCECh. 31 - Prob. 33PCECh. 31 - Prob. 34PCECh. 31 - Prob. 35PCECh. 31 - Prob. 36PCECh. 31 - Prob. 37PCECh. 31 - Prob. 38PCECh. 31 - Prob. 39PCECh. 31 - Prob. 40PCECh. 31 - Prob. 41PCECh. 31 - Prob. 42PCECh. 31 - Prob. 43PCECh. 31 - Prob. 44PCECh. 31 - Prob. 45PCECh. 31 - Prob. 46PCECh. 31 - Prob. 47PCECh. 31 - Prob. 48PCECh. 31 - Prob. 49PCECh. 31 - Prob. 50PCECh. 31 - Prob. 51PCECh. 31 - Prob. 52PCECh. 31 - Give the electronic configuration for the ground...Ch. 31 - Prob. 54PCECh. 31 - Prob. 55PCECh. 31 - Prob. 56PCECh. 31 - The configuration of the outer electrons in Ni is...Ch. 31 - Prob. 58PCECh. 31 - Prob. 59PCECh. 31 - Prob. 60PCECh. 31 - Prob. 61PCECh. 31 - Prob. 62PCECh. 31 - Prob. 63PCECh. 31 - Prob. 64PCECh. 31 - Prob. 65PCECh. 31 - Prob. 66PCECh. 31 - Prob. 67PCECh. 31 - Prob. 68GPCh. 31 - Prob. 69GPCh. 31 - Prob. 70GPCh. 31 - Prob. 71GPCh. 31 - Prob. 72GPCh. 31 - Prob. 73GPCh. 31 - Prob. 74GPCh. 31 - Prob. 75GPCh. 31 - Prob. 76GPCh. 31 - Prob. 77GPCh. 31 - Prob. 78GPCh. 31 - Prob. 79GPCh. 31 - Prob. 80GPCh. 31 - Prob. 81GPCh. 31 - Prob. 82GPCh. 31 - Prob. 83GPCh. 31 - Prob. 84PPCh. 31 - Prob. 85PPCh. 31 - Prob. 86PPCh. 31 - Prob. 87PPCh. 31 - Prob. 88PPCh. 31 - Prob. 89PP
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- What is the probability of finding a hydrogen electron (n=2, l=1, ml =-1) within three bohr radii of the nucleus?arrow_forward(a) Show that the speed of an electron in the nth Bohr orbit of hydrogen is αc/n, where α is the fine structure constant, equal to e2/4πε0ħc. (b) What would be the speed in a hydrogen like atom with a nuclear charge of Ze?arrow_forwardThe energy of the n = 2 Bohr orbit is -30.6 eV for an unidentified ionized atom in which only one electron moves about the nucleus. What is the radius of the n = 3 orbit for this species? Number i Units >arrow_forward
- What are the approximate energies (in keV) of the K and K x rays for scandium? Ka 6 × kev kevarrow_forwardThree isotopes of hydrogen occur in nature; ordinary hydrogen, deuterium, and tritium. Their nuclei consist of, respectively, 1 proton, 1 proton and 1 neutron (deuteron), and 1 proton and 2 neutrons (triton). (a) Determine Rydberg constants for deuterium and tritium. (b) Determine the wavelength difference between the Balmer α lines of deuterium and tritium. (c) Determine the wavelength difference between the Balmer α lines of hydrogen and tritium. Note: The difference in this case would be caused by the nuclear mass. In deriving the Bohr atom, the first order of approximation was to assume that the nucleus doesn't move at all. The correction to this can be done by replacing the mass of the electron with the reduced mass of the electron-nucleus system, where, as you studied in mechanics, the reduced mass is given by μ=m1m2/(m1+m2). Additionally, the Balmer series is the one that terminates in the n=2 level with the α line corresponding to the n=3→n=2 transition.arrow_forwardJ 5 Question 2 (1) Assume that the average energy of β-rays (electrons) emitted from the S-ray source is 0.8 MeV, and the average ionization energy of gas molecules (atoms) in the GM counter tube is about 30 eV. Find the number of gas molecules ionized when one electron enters the GM tube (1MeV = 10°eV). (2) Assuming that the electrons and cations thus generated are attracted to the electrode as they are, what is the total amount of negative charge generated by ionization in C (coulombs)? (3) If this ionization takes 10-4s, what is the current flowing through the anode?arrow_forward
- A proton is fired from very far away towards a nucleus with charge Q = 120 e, where e is the electronic charge. It makes a closest approach of 10 fm to the nucleus. The de-Broglie wavelength (in units of fm) of the proton at its start is [Take the proton mass, mp = (5/3)× 10-²7 kg; h/e= 4.2 × 10-¹5 р J-s/C: 1 ATTEO = 9× 10⁹ m/F; 1 fm = 10-¹5 m] (2013 Adv.)arrow_forwardUsing the Thomson model, estimate the average scatter- ing angle when alpha particles (z = 2) with kinetic energy 3 MeV are scattered from gold (Z = 79). The atomic radius of gold is 0.179 nm.arrow_forwardCan a hydrogen atom emit x rays? If so, how? If not, why not?arrow_forward
- Characteristic x‐rays emitted by molybdenum have a wavelength of 0.072 nm. What is the energy of one of these x‐ray photons? [Answer: 17,371 eV = 17.4 keV]arrow_forwardWhich hydrogen like atom has the wavelength difference between the first line of Lyman and Balmer is equal to 59.3nm?arrow_forward5 6 À (x10-² nm) 7 8 9 10 Relative intensity Mo 9 9 12 vith → To 15.2 → To 37.2arrow_forward
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