(a) Explanation Given info: The n th state of an electron is 3 . The kinetic energy of an electron is, K = 1 2 m ( 2 π k e 2 n h ) 2 Here, k is the coulomb’s constant. e is the charge of an electron. n is the n th orbital of an electron. h is the Planck’s constant. The value of Planck’s constant is 6.63 × 10 − 34 J ⋅ s . The mass of an electron is 9.11 × 10 − 31 kg . The value of coulomb’s constant is 9 × 10 9 N ⋅ m 2 / C 2 . The charge on an electron is 1.6 × 10 − 19 C . Substitute 6.63 × 10 − 34 J ⋅ s for h , 9.11 × 10 − 31 kg for m , 3 for n , 1.6 × 10 − 19 C for e and 9 × 10 9 for k to calculate K . K = 1 2 × 9 (b) To determine The potential energy of an electron. (c) To determine The total energy of an electron.

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ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Question

Chapter 31, Problem 21PCE

(a)

To determine

The Kinetic energy of an electron.

(b)

To determine

The potential energy of an electron.

(c)

To determine

The total energy of an electron.

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Chapter 31, Problem 20PCE

Chapter 31, Problem 22PCE

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Chapter 31 Solutions

Physics (5th Edition)

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The Kinetic energy of an electron.

Solution Summary: The author explains how the kinetic energy of an electron is 1.506eV.

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The Kinetic energy of an electron.

The potential energy of an electron.

The total energy of an electron.

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Chapter 31 Solutions