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The current flowing through a
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Electrical Engineering: Principles & Applications (7th Edition)
- A 790 uF capacitor has an initial voltage, v(0) = 2 V. If the current flowing through the capacitor is i(t) = 12 mA, what is the voltage v(t) across the capacitor, at time t= 51ms? Enter your answer to 3 significant figures. i(t) C + t v(t)arrow_forwardIn the circuit depicted below, determine the voltage across the capacitor for t > 0. Your answer will be a function of t, using impulsive functions to represent discontinuities. 50 5 A 0.01 F 0.2 H 25 u(t) V Edit View Insert Format Tools Table 12pt v Paragraph v BIUA ...arrow_forwardA series circuit has a capacitor of 0.25 x 10-0 F, a resistor of 5x 10' 2, and an inductor of 1 H. The initial charge on the capacitor is zero. If a 12-volt battery is connected to the ircuit and the circuit is closed at t = 0, determine the charge on the capacitor at t = 0.001 seconds, at t = 0.01 seconds, and at any time t. Also determine the limiting charge as - 0. Enter the exact answer with a < b. The charge at any time is given by the formula Q (1) = (Ae" + Beb + C) x 10-6 coulombs, where %3D x10-6 coulombs as t→ 0 tound your answers to two decimal places. 20 001) = x10-6 Coulomhsarrow_forward
- For the circuit in Figure 3 the switch is in the left position for several minutes: (a) Find the Initlal voltage, V, on the capacitor just before the switch is flipped (b) Find an expression v(t) that describes the voltage across the 20 N resistor after the switch has been Figure 3 U 09 flipped to the right NOTE: Remember what we said in class: use a Circuit-Specific Equation to get a value you know. Then solve for whatever else the problem asks for +50 µF 380 0 20 2arrow_forwardPlease help me, thank you so much. I have underlined what I thought the answer was. The questions are as follows: The switch in the following circuit closes at t = 0 (assume no initial charge on the capacitor). Determine the voltage, vC(t), and the current, iC(t), prior to the switch closing for t = 0‒ Vc(0-)= 0V because the initial charge is 0 Ic(0-)= 0mA because there is no power supply Determine the vC(t) and iC(t) after the switch closes and after a long time (i.e. t = 0+ and t = ∞). Vc(0+)= 0V because the capacitor doesn’t charge instantaneously but increases exponentially. Ic(0+)= Current shoots up to 3.75 mAmps when the switch is closed. Vc(infinity) = asymptotic limit of 637 volts after increasing exponentially. Ic(infinity) = 0 mA after decreasing exponentially Determine the time constant, τ, for t > 0. τ=RC = (0.25uF)*(25.5k ohms) = 0.0063 Write out the equations for the voltage, vC(t), and the current, iC(t), for t > 0. Vc(t)=…arrow_forwardFind VouT(t) for t > 0 when the switch closes in the circuit below at time t = 0. The capacitor has no initial energy stored prior to t = 0. VIN = 5 V. Solve also for Vout(2t). 2F 200 200 t=0 VIN VOUTarrow_forward
- In the circuit below, at t = 0, switch S, is closed and switch S2 is closed 4 seconds later. Calculate the current through the inductor at t = 5 second. 40 60 S1 20 40 V 10 V Type your answer here:arrow_forwardPlease see the question and figure in the image: The initial voltage on the 0.5 mF capacitor shown below is −20V at t = 0. The capacitor current is ic(t) = 0.070e−1000t A. a) How much energy is stored in the capacitor at t = 500ms? b) How much energy is stored in the capacitor as time goes to infinity?arrow_forwardThe two parallel inductors in the figure below are connected across the terminals of a black box at t = 0. The resulting voltage v for t > 0 is known to be 12e-V. It is also known that i₁(0) = 2A and i2(0) = 4A. - i1(t) L1 3 H i2(t) L2 6 H i(t) t=0 Black Box (a) Replace the original inductors with an euivalent inductor and find i(t) for t≥ 0. (b) Find i₁(t) for t≥ 0. (c) Find i2(t) for t≥ 0. (d) How much energy is delivered to the black box in the time interval 0 ≤ t ≤∞. (e) How much energy was initially stored in the the parallel inducutors? (f) How much energy is trapped in the ideal inductors? (g) Show that your solutions for i₁(t) and i2(t) agree with your answer in (f).arrow_forward
- In the figure, the capacitor is initially uncharged and R the switch (S) is closed at t = 0. (a) Find the current through each resistor and capacitor at t = 0. (b) Find the current through each resistor and capacitor at t → * (c) What is the charge on the capacitor as t → *? (d) Find the charge on the capacitor for t> 0.arrow_forward6 - In the circuit given below let R=2 Q,8=10 V, and C=1pF. The capacitor is uncharged before closing the switch S. After closing S at t=0,find the current in the circuit at t=2µs. S. R Ceva a) 1.01 A b) 1.84 A 1 1.21 A 7 1.36 A 13 0.84 A 19 Boş bırak 3. 00 0 0 00arrow_forwardAssume that the switch has remained open for a very long time before t=0. Find the voltage v across the capacitor (as indicated on the diagram & accurate to 1%) as t→∞o (i.e. a long time after the switch changes position) for the following values: Is = 3 mA, R1 = 2.3 k0, R2 = 3.7 k0, R3 = 1.5 k0, C = 90 nF Is ↑ R1Q v(t) R20 t = 0 CF || R3 Qarrow_forward
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