Concept explainers
The Norton and Thevenin equivalent networks from node
Answer to Problem 3.71HP
The Thevenin equivalent Network is shown in Figure 6 and the Norton equivalent network is shown in Figure 4
Explanation of Solution
Calculation:
The given diagram is shown in Figure 1
To determine the Norton equivalent, short circuit the output terminals, Mark the values, current direction, and redraw the circuit.
The required diagram is shown in Figure 2
Apply KVL to the first loop.
Apply KVL to the second loop.
The equation for the Norton current is given by,
Substitute
To obtain the Norton resistance of the circuit, short circuit the voltage source, open circuit the current source and redraw the circuit.
The required diagram is shown in Figure 3
Form the above circuit the Norton impedance of the circuit is calculated as,
Substitute
Mark the values and draw the Norton equivalent circuit.
The required diagram is shown in Figure 4
To calculate the Thevenin voltage, remove the load resistance and redraw the circuit.
The required diagram is shown in Figure 5
From the above circuit the value of the current
Substitute
The expression for the value of the current
Substitute
The expression for the voltage across the resistor
Substitute
The expression for the voltage across the resistor
Substitute
From Figure (5), the expression for the Thevenin voltage is given by,
Substitute
The Thevenin and the Norton resistance of the circuit are equal, thus the expression for the Thevenin resistance is given by,
Substitute
Mark the values and draw the Thevenin equivalent of the circuit.
The required diagram is shown in Figure 6
Conclusion:
Therefore, the Thevenin equivalent Network is shown in Figure 6 and the Norton equivalent network is shown in Figure 4
Want to see more full solutions like this?
Chapter 3 Solutions
Principles and Applications of Electrical Engineering
- Using mesh current analysis, find the voltage, v,across the source in the circuit of Figure P3.18.arrow_forwardUsing mesh current analysis, find the voltage vacross R4 in the circuit of Figure P3.25. LetVS1 = 12 V; VS2 = 5 V; R1 = 50 Ω; R2 = R3 = 20Ω ;R4 = 10 Ω; R5 = 15Ω .arrow_forwardUsing KCL, perform node analysis on the circuitshown in Figure P3.24, and determine the voltageacross R4. Note that one source is a controlled voltagesource! Let VS = 5 V; AV = 70; R1 = 2.2 kΩ;R2 = 1.8 kΩ; R3 = 6.8 kΩ; R4 = 220Ωarrow_forward
- Using mesh current analysis, find the currents i1 and i2 for the circuit of Figure P3.14.arrow_forwardIn the circuit shown in Figure P3.33, F1 and F2 arefuses. Under normal conditions they are modeled as ashort circuit. However, if excess current flows througha fuse, it “blows” and the fuse becomes an open circuit.VS1 = VS2 = 120 VR1 = R2 = 2 Ω R3 = 8Ω R4 = R5 = 250 mΩIf F1 blows, or opens, determine, using KCL and nodeanalysis, the voltages across R1, R2, R3, and F1.arrow_forwardFind the voltage v across the 3- resistor in thecircuit of Figure P3.52 by replacing the remainder ofthe circuit with its Thévenin equivalentarrow_forward
- The equivalent circuit of Figure P3.73 hasVT = 35 V RT = 600Ω If the conditions for maximum power transfer exist,determinea. The value of RL.b. The power developed in RL.c. The efficiency of the circuitarrow_forwardFind the Thévenin equivalent of the circuitconnected to RL in Figure P3.58, where R1 = 10Ω ,R2 = 20 Ω, Rg = 0.1 Ω, and Rp = 1 Ω.arrow_forwardUsing mesh current analysis, find the currents I1, I2, and I3 in the circuit of Figure P3.17 (assume polarity according to I2).arrow_forward
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,