A site is underlain by a soil that has a unit weight of
a. 2.2 m
b. 4.0 m
c. 6.0 m
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- A site is underlain by a soil that has a unit weight of 18.7 kN/m3 above the groundwater table and 19.9 kN/m3 below. The groundwater table is located at a depth of 3.5 m below the groundsurface. Compute the total vertical stress, pore water pressure, and effective vertical stress atthe following depths below the ground surface:a. 2.2 mb. 4.0 mc. 6.0 marrow_forwardProblem 7: The soil profile at the site consists of 5.0 m of silty sand underlain by 13 m of clay. The groundwater table is at a depth of 2.8 m below the ground surface. The silty sand has a unit weight of 19 kN/m3 above the groundwater table and 20 kN/m³ below. The clay has a unit weight of 15.7 kN/m³. Determine the depth of groundwater table from the ground surface to have an average effective stress at the clay layer of 100 kPa?arrow_forwardThe soil profile at the site consists of a 5.0 m sand layer underlain by 13 m of clay layer. The groundwater table is at a depth of 2.8 m below the ground surface. The sand has a unit weight of 19 kN/m3 above the groundwater table and 20 kN/m³ below the ground water table. Meanwhile, the saturated unit weight of clay is 15.7 kN/m3. At a depth of 11m from the ground lever, calculate the Total Pressure, Porewater Pressure, and the Effective Pressure (in kPa).arrow_forward
- Ground surface 2. The soil profile for a proposed construction site is shown. The groundwater table is located 2 m below the ground surface. Assume geostatic conditions and ignore any negative pore-water pressures due to capillary rise. Yt = 13.2 kN/m 2. Sand Ysat =? G, = 2.70 n= 0.5 (a) What is the effective stress (kPa) at point A? (Ans: 43 kPa) (b) What is the effective stress (kPa) at point B? (Ans: 82 kPa) (c) Ten years from now, the depth of the groundwater table will change, resulting in a new effective stress at point B of 72.6 kPa. Based on this information, how far below the ground surface will the new location of the groundwater table be? (Ans: 0 m; GWT is at the ground surface) A Clay Ysat = 19.6 kN/marrow_forwardSolve the following problems. Provide complete solutions and summary of answers. The water table in soil deposit is 2 meters below the ground surface. The soil above the water table has a dry unit weight of 14.85 kN/cu. Meter. The saturated unit weight of the soil is 20.58 kN/cu.meter. Determine the following: a. Total Stress at a point 4.80 meters below the ground b. Total Pore pressure 4.80 meters below the ground c. Total effective stress at a point 4.80 meters below the ground.arrow_forwardConsider the soil profile shown in the figure below, and an initial groundwater depth of 5 feet below the ground surface. Assuming the soil above the water table is dry, then Ground Surface Ya = 115 Ib/ft G.= 2.65 5 ft SAND 15 ft Ysat = 120 Ib/ft3 e,- 1.1 C = 0.5 C, = 0.05 o- 2.8 ksf 15 ft CLAY ROCK a. The in-situ effective vertical stress in the middle of the clay layer is psf. b. If a uniform permanent load of 500 psf is applied on the ground surface, the estimated primary consolidation settlement of the clay layer is inches. c. If the groundwater table is lowered to the top of the clay layer at a final depth of 20 feet below the ground surface after the consolidation settlement in part (b) is completed, the effective vertical stress increase in the middle of the clay layer is psf.arrow_forward
- 5. A soil profile at a site consists of a 10-foot thick layer of sand over a thick clay layer. The water table is located at the bottom of the sand layer. The moist unit weight of the sand is 100 pcf and the saturated unit weight of the clay 115 pcf. Calculate the total vertical stress, pore water pressure, and vertical effective stress at a depth of 15 feet below the ground surface. 6. The subsurface conditions at a site consist of a 4-meter thick layer of clay over bedrock. The water table is located at the ground surface. The total (saturated) unit weight of the soil is 15 kN/m³. A consolidation test is performed on an undisturbed sample of the clay obtained from the midpoint of the clay layer (i.e., 2 meters below the mudline) and the 'e-log-p curve' is shown in the figure below. (a) Using Casagrande's construction procedure estimate the preconsolidation stress. (b) Assess the stress history of the sample (i.e., normally consolidated or overconsolidated). (c) Determine the…arrow_forwardWater flows at a rate of 0.09 m3/s upward through a sand sample with a coefficient of permeability of 27 cm/s. The thickness of the soil is 0.24 m and the area is 0.54 sq. m. Saturated unit weight is 18.9 kN/m3. a) Determine the hydraulic gradient (Ans. 0.617) b) Compute the effective stress at the middle of the sample (Ans. 354 N/m2) c) Compute the effective stress at the bottom of the sample. (Ans. 728 N/m2)arrow_forwardThe soil profile consists of 5m sand underlain by 13 m layer of clay. The ground water table is at a depth 2.8 m below the surface. The sand has a unit weight of 19 kN per cu. Meter above the ground water table and the saturated unit weight below was 20 kN per cu. meter. The saturated unit weight of the clay is 15.7 kN per cu. meter. At a depth of 11 m determine the following:a. Total stressb. Pore water pressurec. Effective stress.....arrow_forward
- Effective Stress in Soil Problem 1. The water table in a certain deposit of soil is at a depth of 2m below the ground surface. The soil consists of clay up to depth of 4m from the ground and below which lies sand. The clay soil is saturated even above the water table: Clay strata: ? = 30%,?? = 2.72 Sandy Strata: ? = 26%, ?? = 2.64 1. Compute the total pressure. 2. Compute the pore water pressure. 3. Compute the effective stress pressure at a depth of 8m below the ground surfacearrow_forwardQuestion 1: (10) For the soil profile shown below where H1 = 5 m and H2 = 5 m: a) Calculate the total stress (o), pore water pressure (u), and effective stress (o') at point A. b) In order to decrease the effective stress at point A by 15 kN/m2, what would be the depth of the water table from the ground surface. XXXX H1 Dry Sand e = 0.60 G, = 2.68 Clay H2 e 0.80 G = 2.75 %3D %23arrow_forwardb) The soil layers on a site consist of: 0 - 10 m sand (g- 20 kN/m) 10-15 m clay (g 22 kN/m') Draw an effective stress/total stress profile between 0 and 15 m, when the water table is at a depth of 5 m below the ground surface. If because of capillary action the soil becomes fully saturated upto 3 m above the ground water table, what will be the value of total / effective stress at a depth of 3 m below the ground surface? Assume g 22 kN/m' for fully saturated soil.arrow_forward
- Principles of Geotechnical Engineering (MindTap C...Civil EngineeringISBN:9781305970939Author:Braja M. Das, Khaled SobhanPublisher:Cengage Learning