Foundation Design: Principles and Practices (3rd Edition)
Foundation Design: Principles and Practices (3rd Edition)
3rd Edition
ISBN: 9780133411898
Author: Donald P. Coduto, William A. Kitch, Man-chu Ronald Yeung
Publisher: PEARSON
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Chapter 3, Problem 3.11QPP

A 2m thick fill is to be placed on the soil shown in Figure 3.21. Once it is compacted, this fill will have a unit weight of 19.5 kN/m 3 . Compute the ultimate consolidation settlement.

Chapter 3, Problem 3.11QPP, A 2m thick fill is to be placed on the soil shown in Figure 3.21. Once it is compacted, this fill

Figure 3.21

Soil profile for Problem 3.11.

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For the soil profile given below, assume that the primary consolidation settlement for the clay layer is completed in 3 years. Estimate the secondary consolidation settlement for the clay layer at the end of 10 years. Yw= 10kN/m³, Ca= 0.03 1m 1.5m 2m BxL= 2m x 4m Groundwater table 0.5m 90 = 100kPa Sand y = 17.0 kN/m³ Sand Ysat 19.0 kN/m³ a retaining wall are shown in Normally consolidated Clay Ysat 20 kN/m³ eo = 0.7 Cs=0.09 Cc = 0.2
10.17 A 4.0 m thick fill is to be made of a soil with a Proctor maximum dry unit weight of 19.4 kN/m² and an optimum moisture content of 13.0%. This fill will be compacted at optimum moisture content to an average relative compaction of 92%. The underlying soils are as shown in Figure 10.26. Consolidation tests were performed at Points A and B, with the following results: Sample A Сс 0.59 Cr ୧୦ 0.19 1.90 σ (kPa) 75 B 0.37 0.14 1.21 100 The silty sand is normally consolidated. Using hand computations, determine the ultimate consolidation settlement due to the weight of this fill.
5. For the soil profile given below, assume that the primary consolidation settlement for the clay layer is completed in 3 years. Estimate the secondary consolidation settlement for the clay layer at the end of 10 years. Yw= 10kN/m³, Ca = 0.03 1m 1.5m 2m Groundwater table 0.5m BXL = 2m x 4m Sand y = 17.0 kN/m³ 90 = 100kPa Sand Ysat = 19.0 kN/m² Normally consolidated Clay Ysat = 20 kN/m³ eo = 0.7 Cs = 0.09 Cc = 0.2 -

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