(a)
Interpretation:
The steps of the given reaction are to be classified as Lewis acid-base association reaction, Lewis acid-base association reaction, electron-pair displacement reaction, a Brønsted acid-base reaction.
Concept introduction:
Lewis acid-base association reactions are those reaction in which a compound dissociates to form a Lewis acid and a Lewis base as a product. Brønsted acid-base reactions are those reactions in which electron pair displacement takes place and electrophilic center is a proton. Lewis acid-base association reactions are those reaction in which a Lewis acid combines with Lewis base to form a product.
(b)
Interpretation:
The conjugate acid-base pair formed in the Brønsted acid-base reaction is to be indicated.
Concept introduction:
Brønsted acid-base reactions are those reactions in which electron pair displacement takes place and electrophilic center is a proton. The species which accepts proton are known as Brønsted base. On the other hand, the species which donates proton from another species are termed as Brønsted acid.
(c)
Interpretation:
Each atom of the species present in the mechanism is to be classified as a nucleophile, nucleophilic center, electrophile, electrophilic center, leaving group, Brønsted base, Brønsted acid.
Concept introduction:
The species which donates electron pair is known as Lewis base. On the other hand, the species which accepts electron pair from another species is known as Lewis acid. Lewis acid-base association reactions are those reaction in which a Lewis acid combines with Lewis base to form a product.
(d)
Interpretation:
The curved arrow notation of each step is to be drawn.
Concept introduction:
The curved-arrow notation is used to show the transfer of electrons from one atom to another. The curved arrow has two barbs (head and tail) which represent the direction of electron flow.
Want to see the full answer?
Check out a sample textbook solution
Chapter 3 Solutions
Organic Chemistry
- 7. Calculate the following for a 1.50 M Ca(OH)2 solution. a. The concentration of hydroxide, [OH-] b. The concentration of hydronium, [H3O+] c. The pOH d. The pHarrow_forwardA first order reaction is 46.0% complete at the end of 59.0 minutes. What is the value of k? What is the half-life for this reaction? HOW DO WE GET THERE? The integrated rate law will be used to determine the value of k. In [A] [A]。 = = -kt What is the value of [A] [A]。 when the reaction is 46.0% complete?arrow_forward3. Provide the missing compounds or reagents. 1. H,NNH КОН 4 EN MN. 1. HBUCK = 8 хно Panely prowseful kanti-chuprccant fad, winddively, can lead to the crading of deduc din-willed, tica, The that chemooices in redimi Грин. " like (for alongan Ridovi MN نيا . 2. Cl -BuO 1. NUH 2.A A -BuOK THE CF,00,H Ex 5)arrow_forward
- 2. Write a complete mechanism for the reaction shown below. NaOCH LOCH₁ O₂N NO2 CH₂OH, 20 °C O₂N NO2arrow_forward4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forwardThe following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forward
- Please correct answer and don't use hand rating and don't use Ai solutionarrow_forward1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forwardThe following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forward
