Concept explainers
Interpretation:
The given chemical equations are need to be balanced.
Concept Introduction:
Chemical equations are symbolic representations of
The reactants are written on the left side whereas the products are written on the right side of an arrow.
Chemical equations are denoted using chemical formulae of the elements and compounds involved.
The
Atomicity is defined as the number of atoms in a molecule of an element.
Chemical formulae of compounds are written on the basis of their molecularity.
Molecularity is the number of molecules that come to react in an elementary (single-step) reaction.
A balanced chemical equation shows the same number of atoms of each element on both sides of the arrow.
Chemical equations are balanced on the basis of the Law of Conservation of Mass.
Answer to Problem 25QP
Solution:
a)
b)
c)
d)
e)
f)
g)
h)
i)
j)
k)
l)
m)
n)
Explanation of Solution
a)
There are two atoms of nitrogen on either side of the equation. However, there are five oxygen atoms on the left side and six oxygen atoms on the right side of the equation. The entire equation is balanced by adding the coefficient
b)
There is one atom of potassium on either side of the equation. Also, there is one atom of nitrogen on both the sides. However, on the left there are three oxygen atoms while on the right, there are four oxygen atoms. The entire equation is balanced by adding the coefficient
c)
There are two atoms of nitrogen on either side of the equation. However, there is an imbalance in the number of hydrogen and oxygen atoms. In case of hydrogen, there are four atoms on the left side and two on the right side. In case of oxygen, there are three atoms on the left side and two on the right side. The entire equation is balanced by adding the coefficient
d)
There are two atoms of nitrogen on either side of the equation. However, there are four atoms of hydrogen on the left side and two atoms on the right side. Also, there are two oxygen atoms on the left side and one on the right side of the equation. The entire equation is balanced by adding the coefficient
e)
There is one atom of sodium on the left side while two atoms on the right side of the equation. For hydrogen, there is one atom on the left but two atoms on the right. For carbon also, there is one atom in the left but two atoms on the right. For oxygen, there are three atoms on the left but six atoms on the right of the equation. The entire equation is balanced by adding the coefficient
f)
There are four atoms of phosphorus on the left side but only one on the right side of the equation. In case of hydrogen, there are two atoms on the left side and three on the right. In case of oxygen, there are eleven atoms on the left but four on the right. The entire equation is balanced by adding the coefficient
g)
There is only one atom of calcium on either side of the equation. It is the same case with the elements carbon and oxygen, where it is one carbon atom and three oxygen atoms on the either side of the equation. However, there are discrepancies in the number of hydrogen and chlorine atoms. In case of chlorine, there is one on the left side and two on the right side. In case of hydrogen, there is one atom on the left side but two on the right side. The entire equation is balanced by adding the coefficient
h)
Apart from hydrogen, the number of all other atoms is different on the either side of the equation. In case of hydrogen, there are two atoms on both sides of the equation. On the other hand, for aluminium, there is one atom on the left and two atoms on the right. For sulphur, there is one atom on the left but three on the right. For oxygen, there are four atoms on the left but twelve on the right. The entire equation is balanced by adding the coefficient
i)
There is one atom of carbon on both sides of the equation. For potassium, there is one atom on the left but two on the right side of the equation. For hydrogen, there is one atom on the left side and two on the right side of the equation. For oxygen, there is one atom on the left side but four on the right side. The entire equation is balanced by adding the coefficient
j)
There is one atom of carbon on both sides of the equation. For hydrogen, there are four atoms on the left side and two on the right side of the equation. For oxygen, there are two atoms on the left side but three on the right side. The entire equation is balanced by adding the coefficient
k)
There is one atom of carbon on both sides of the equation. For hydrogen, there are two atoms on the left side but six on the right side of the equation. For oxygen, there is one atom on the left side but two on the right side. For beryllium, there is one atom on the left side but one on the right side. The entire equation is balanced by adding the coefficient
l)
There is one atom of copper on both sides of the equation. For oxygen, there are three atoms on the left side but eight on the right side of the equation. For hydrogen, there is one atom on the left side but two on the right side. For nitrogen, there is one atom on the left side but three on the right side. The entire equation is balanced by adding the coefficient
m)
There is one atom of sulphur on both sides of the equation. For oxygen, there are three atoms on the left side but seven on the right side of the equation. For hydrogen, there is one atom on the left side but four on the right side. For nitrogen, there is one atom on the left side and one on the right side. The entire equation is balanced by adding the coefficient
n)
There is one atom of copper on both sides of the equation. It is the same for oxygen. For hydrogen, there are three atoms on the left side but two on the right side. For nitrogen, there is one atom on the left side but two on the right side. The entire equation is balanced by adding the coefficient
Want to see more full solutions like this?
Chapter 3 Solutions
Chemistry
- Iron oxide ores, commonly a mixture of FeO and Fe2O3, are given the general formula Fe3O4. They yield elemental iron when heated to a very high temperature with either carbon monoxide or elemental hydrogen. Balance the following equations for these processes: Fe3O4(s)+H2(g)Fe(s)+H2O(g)Fe3O4(s)+CO(g)Fe(s)+CO2(g)arrow_forwardThe space shuttle environmental control system handles excess CO2 (which the astronauts breathe out; it is 4.0% by mass of exhaled air) by reacting it with lithium hydroxide, LiOH, pellets to form lithium carbonate, Li2CO3, and water. If there are seven astronauts on board the shuttle, and each exhales 20. L of air pee minute, how long could clean air be generated if there were 25,000 g of LiOH pellets available for each shuttle mission? Assume the density of air is 0.0010 g/mL.arrow_forward3.92 Many chemical reactions take place in the catalytic con- verter of a car. In one of these reactions, nitric oxide (NO) reacts with ammonia (NH3) to give nitrogen (N2) and water. Write a balanced equation for this reaction.arrow_forward
- Balance the following chemical equation. 1. Al2(SO4)3 + Ca(OH)2 → Al(OH)3 +CaSO4hsheT ni Ineeerg Inemsle rloss to noulacgmoo Inaoeg ant onimsledpy 2. H2SO4 + HI → H2S + 12 + H2Oarrow_forwardPredict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit is balanced. (You can edit both sides of the equation to balance it, if you need to.) Note: you are writing the molecular, and not the net ionic equation. → BaBr₂(aq) + H₂O(1) X S ?arrow_forwardBalance the equation below, which uses imaginary elements (they still follow the usual convention – each element symbol is one or two letters long, beginning with a capital letter). MTy3 + Gr2WaX4 → GrTy + M2(WaX4)3arrow_forward
- Consider the chemical reaction that takes place between aqueous iron(III) nitrate and aqueous sodium hydroxide. a.) Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arrow. Be sure to include the proper phases for all species within the reaction. Fe(NO₃)₃(aq) + NaOH(aq) → b.) Write the balanced COMPLETE ionic equation for the reaction. If no precipitation reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction. c.) Write the balanced NET ionic equation for the reaction. If no reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction.arrow_forwardFrom the balanced molecular equation, select the correct net ionic equations for the following: CaCO3(s)+ H2SO4(aq)→ CaSO4(s) + CO2(g) +H2O(l) a. CaCO3(s)+ 2H+ + SO42-(aq)→ CaSO4(s) + CO2(g) +H2O(l) b. 2H+ + SO42-(aq)→ CaSO4(s) + CO2(g) +H2O(l) c. CaCO3(s)+ SO42-(aq)→ CaSO4(s) + CO2(g) +H2O(l) d. CaCO3(s) → CaSO4(s) + CO2(g) +H2O(l)arrow_forwardRead the information below, then answer the question. A laboratory assistant was experimenting with chemical reactions when she combined a small amount of zinc (Zn) with hydrochloric acid (HCI). She discovered that zinc chloride (ZnCl2) and hydrogen (H2) were produced. Equations Which equation correctly describes this reaction? O 2zn + 2HCI 2(ZnCl2 + H2) O Zn + 2HCI ZnCl2 + H2 O ZnCl2 + H2 - Zn + 2HCI O Zn + HCI - ZnCl2 + H2 8. 10 11 12 13 14 15 1 Help Center | Schoology Blog | PRIVACY POLICY I Terms c pe here to searcharrow_forward
- When magnesium hydroxide reacts with nitric acid, it produces magnesium nitrate and water. g(OH)2 + 2HNO3 → Mg(NO3)2 + 2H2O how can i explain how this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.arrow_forwardCloth can be waterproofed by coating it with a silicone layer. This is done by exposing the cloth to (CH3)2 SiCl2 vapor. The silicon compound reacts with OH groups on the cloth to form a waterproofing film (density = 1.0 g/cm³) of [(CH3)2 SiO], where n is a large integer number. n (CH3) SiCl2 + 2n OH → 2n Cl + n H₂O + [(CH3)2 SiO] n The coating is added layer by layer, with each layer of [(CH3)2 SiO], being 0.60 nm thick. Suppose you want to waterproof a piece of cloth that is 4.00 square meters, and you want 250 layers of waterproofing compound on the cloth. What mass of (CH3)2 SiCl2 do you need? Mass= g Submit Answer Try Another Version [References] 8 item attempts remainingarrow_forwardPredict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit is balanced. (You can edit both sides of the equation to balance it, if you need to.) Note: you are writing the molecular, and not the net ionic equation. [] → Ba(C1O₂)₂ (aq) + H₂O(1) 2 X LIEarrow_forward
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning