Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 29, Problem 11P
Interpretation Introduction
Interpretation:
The reason for making DNA radioactive needs to be suggested.
Concept introduction:
DNA endonuclease is an enzyme which can cut the DNA strand by breaking the phosphodiester bond between two nucleotides. It will generate one 3’OH and one 5’ phosphoryl group at the end of broken strands.
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Please help me solve this problem. I am really having a hard time understanding this lesson. Please help. Kindly provide all the necessary information to this problem. Thank you! Please answer numbers 1-5
determine what amino acid will be formed from the given DNA strand below:
3’ T A C A T G C C G A A T G C C 5’
Note: Prepare the partner strand of this DNA. Discuss how will replication happen by mentioning the enzyme needed then transcribe to form mRNA. Discuss what will happen to mRNA, then translate, mentioning the anticodon to be used. Look at the genetic code to know what amino acid will become part of the polypeptide chain.
1. Partner DNA strand
2. the mRNA strand
3. The tRNA
4. the formed amino acids
5. the discussion of the entire procedure
Pstl.
EcoRI
Origin of
replication
(ori)
Ampicillin Tetracycline
resistance resistance
(Amp) (Tet")
pBR322
(4,361 bp)
BamHI
Pvull
Sall
Recombinant
Plasmid DNA
Bacterial cell contains...
No plasmid DNA
pBR322 (no insert)
Recombinant plasmid
00,000.
Host DNA
Transformation
of E. coli cells
+AMP plate
pBR322
Figure 7-5
+TET plate
Based on the recombinant plasmid growth pattern (bottom row of blue table), which of
the depicted plasmid's restriction sites was used to prepare this sample? Explain how
you can tell.
Need answer ASAP.
The double-stranded molecule of DNA: AG/TC is a very good representation of the much larger chromosome. Diagram and label this molecule, then describe how would this molecule look if it were a DNA/RNA hybrid using the AG for the DNA strand.
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.Similar questions
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- gene. If the JM109 strain is transformed by the PBKSK plasmid, the strain will produce the B-galactosidase (from the lac gene) and will hydrolyze X-gal to produce the blue compound. Therefore, colonies that were transformed and contain the pBSKS wil you appear blue. IPTG & X-Gal & NO colonies Amp E. coli JM109 E. coli JM109 50 mM calcium chloride-15% glycerol lac lac lac IPTG & I Recovery X-Gal solution at -702C PBSKS White colonies E. coli JM109 E. coli JM109 ampR amp I amp lac lac Heat Shock Non-transformed 42°C E. coli JM109 E. coli JM109 amps amps lac lac IPTG & X-Gal lac I Recovery lac PBSKS BLUE colonies PBSKS ampRI (amp Transformed IPTG & X-Gal & BLUE colonies Amp Hypotheses: Circle the correct answer 1. If PBSKS is transformed into JM109 cells, colonies will be (able/not able) to grow in the presence of ampicillin. a. Why? _ 2. If PBSKS is transformed into JM109 cells, colonies in media with IPTG (will/will not) induce the production the B- galactosidase enzyme. a. Why?_ 3. If…arrow_forwardplease help me with this question. As this is a non-directional cloning, recombinant plasmids can contain an insert ligated into the vector in two different orientations. Provide two diagrams to illustrate the two potential recombinant plasmids, with the inserts ligated in opposite orientations. Include all RE sites and distances between sites on the diagram.arrow_forwardQuestion. What would the forward primer sequence look like if it were intended to bind the area of the DNA template?arrow_forward
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