Principles of Physics: A Calculus-Based Text
5th Edition
ISBN: 9781133104261
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 28.5, Problem 28.5QQ
To determine
The quantity which is same for both the electron and the proton.
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Chapter 28 Solutions
Principles of Physics: A Calculus-Based Text
Ch. 28.1 - Prob. 28.1QQCh. 28.2 - Prob. 28.2QQCh. 28.2 - Prob. 28.3QQCh. 28.2 - Prob. 28.4QQCh. 28.5 - Prob. 28.5QQCh. 28.5 - Prob. 28.6QQCh. 28.6 - Prob. 28.7QQCh. 28.10 - Prob. 28.8QQCh. 28.10 - Prob. 28.9QQCh. 28.13 - Prob. 28.10QQ
Ch. 28 - Prob. 1OQCh. 28 - Prob. 2OQCh. 28 - Prob. 3OQCh. 28 - Prob. 4OQCh. 28 - Prob. 5OQCh. 28 - Prob. 6OQCh. 28 - Prob. 7OQCh. 28 - Prob. 8OQCh. 28 - Prob. 9OQCh. 28 - Prob. 10OQCh. 28 - Prob. 11OQCh. 28 - Prob. 12OQCh. 28 - Prob. 13OQCh. 28 - Prob. 14OQCh. 28 - Prob. 15OQCh. 28 - Prob. 16OQCh. 28 - Prob. 17OQCh. 28 - Prob. 18OQCh. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQCh. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQCh. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 13CQCh. 28 - Prob. 14CQCh. 28 - Prob. 15CQCh. 28 - Prob. 16CQCh. 28 - Prob. 17CQCh. 28 - Prob. 18CQCh. 28 - Prob. 19CQCh. 28 - Prob. 20CQCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50PCh. 28 - Prob. 51PCh. 28 - Prob. 52PCh. 28 - Prob. 53PCh. 28 - Prob. 54PCh. 28 - Prob. 55PCh. 28 - Prob. 56PCh. 28 - Prob. 57PCh. 28 - Prob. 58PCh. 28 - Prob. 59PCh. 28 - Prob. 60PCh. 28 - Prob. 61PCh. 28 - Prob. 62PCh. 28 - Prob. 63PCh. 28 - Prob. 64PCh. 28 - Prob. 65PCh. 28 - Prob. 66PCh. 28 - Prob. 67PCh. 28 - Prob. 68PCh. 28 - Prob. 69PCh. 28 - Prob. 70PCh. 28 - Prob. 71PCh. 28 - Prob. 72PCh. 28 - Prob. 73PCh. 28 - Prob. 74P
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- An electron with a mass of 9.11 x 10–31 kg is accelerated to 25% the speed of light (c = 3.00 x 108 m/s). What is the de Broglie wavelength in picometers (pm) for this electron?arrow_forwardA proton in a linear accelerator has a de Broglie wavelength of 117 pm. What is the speed of the proton? Express your answer with the appropriate units.arrow_forwardAn electron is moving at 6.0 x 10^6 m/s. A photon of what wavelength would have the same (relativistic) momentum as the electron?arrow_forward
- When developing a night vision night vision equipment, you need to measure the work function for the surface of a metal, so you perform a photoelectric photoelectric effect experiment. You measure the cutoff potential V0 as a function of of the wavelength À of light striking the surface. The results appear in the following table. In your analysis, you use c = 2.998 X 10^8 m/s and e = 1.602 X 10^-19 C, which are values obtained in other experiments. (a) Select a way to represent your results graphicallyso that the data points are close to a straight line. Using this graph, find the slope and the intercept y of the straight line that best fits the data. (b) Use the results from (a) to calculate the Planck constant h (as a test of your data) and the work function ( in and V) of the surface. ( c) What is the longest wavelength of light that will produce photoelectrons from this surface? (d) What wavelength of wavelength of light is required to produce photoelectrons with a kinetic energy…arrow_forwardA relativistic electron has a de Broglie wavelength of 2.45 pm2.45 pm (1 pm=10−12 m).(1 pm=10−12 m). Determine its velocity, expressed as a fraction of the speed of light ?.arrow_forwardIt is stated in the text that special relativity must be used to calculate the de Broglie wavelength of electrons in an electron microscope. Let us discover how much of an effect relativity has. Consider an electron accelerated through a potential difference of 1.00 x 105 V.a. Using the Newtonian (nonrelativistic) expressions for kinetic energy and momentum, what is the electron’s de Broglie wavelength?b. The de Broglie wavelength is λ = h/p, but the momentum of a relativistic particle is not mv. Using the relativistic expressions for kinetic energy and momentum, what is the electron’s de Broglie wavelength?arrow_forward
- What speed must an electron have if its momentum is to be the same as that of an X-ray photon with a wavelength of 0.35 nm?arrow_forwardAn electron is moving at 3.5 x 106 m/s. A photon of what wavelength would have the same momentum?arrow_forwardQ. 22 : The de-Broglie wavelength of waves associated with an a-particle of momentum 52.96 x 10- 21 kg m/s is, (a) . 2.250 × 10-14 m (b) 1.251 x 10 11 m (c) 1.251 x 10-14 m (d) 2.250 x 10-11 marrow_forward
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