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Concept explainers
(a)
Interpretation:
Whether the molecule acetoacetyl CoA is a C2, C4, C6 or C8 molecule has to be determined.
Concept introduction:
(b)
Interpretation:
Whether the molecule 3-hydroxy-3-methylglutaryl CoA is a C2, C4, C6 or C8 molecule has to be determined.
Concept introduction:
Ketone bodies are water-soluble molecules which are synthesized from acetyl CoA through the process of ketogenesis. Ketogenesis occurs in the mitochondria of the liver cells. The initial reactants are the molecules of acetyl CoA which are produced by the β-oxidation of fatty acid molecules. Ketone bodies are generally produced when the amount of acetyl CoA in the body is much larger than the amount of oxaloacetate. This happens due to the carbohydrate-lipid imbalance in the body caused by much smaller intake of food rich in carbohydrates, or inefficient processing of glucose by the body.
(c)
Interpretation:
Whether the molecule acetoacetate is a C2, C4, C6 or C8 molecule has to be determined.
Concept introduction:
Ketone bodies are water-soluble molecules which are synthesized from acetyl CoA through the process of ketogenesis. Ketogenesis occurs in the mitochondria of the liver cells. The initial reactants are the molecules of acetyl CoA which are produced by the β-oxidation of fatty acid molecules. Ketone bodies are generally produced when the amount of acetyl CoA in the body is much larger than the amount of oxaloacetate. This happens due to the carbohydrate-lipid imbalance in the body caused by much smaller intake of food rich in carbohydrates, or inefficient processing of glucose by the body.
(d)
Interpretation:
Whether the molecule β-hydroxybutyrate is a C2, C4, C6 or C8 molecule has to be determined.
Concept introduction:
Ketone bodies are water-soluble molecules which are synthesized from acetyl CoA through the process of ketogenesis. Ketogenesis occurs in the mitochondria of the liver cells. The initial reactants are the molecules of acetyl CoA which are produced by the β-oxidation of fatty acid molecules. Ketone bodies are generally produced when the amount of acetyl CoA in the body is much larger than the amount of oxaloacetate. This happens due to the carbohydrate-lipid imbalance in the body caused by much smaller intake of food rich in carbohydrates, or inefficient processing of glucose by the body.
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Chapter 25 Solutions
General, Organic, and Biological Chemistry
- Nonearrow_forwardNonearrow_forwardWhat spectral features allow you to differentiate the product from the starting material? Use four separate paragraphs for each set of comparisons. You should have one paragraph each devoted to MS, HNMR, CNMR and IR. 2) For MS, the differing masses of molecular ions are a popular starting point. Including a unique fragmentation is important, too. 3) For HNMR, CNMR and IR state the peaks that are different and what makes them different (usually the presence or absence of certain groups). See if you can find two differences (in each set of IR, HNMR and CNMR spectra) due to the presence or absence of a functional group. Include peak locations. Alternatively, you can state a shift of a peak due to a change near a given functional group. Including peak locations for shifted peaks, as well as what these peaks are due to. Ideally, your focus should be on not just identifying the differences but explaining them in terms of functional group changes.arrow_forward
- Nonearrow_forwardNonearrow_forwardIn the solid state, oxalic acid occurs as a dihydrate with the formula H2C2O4 C+2H2O. Use this formula to calculate the formula weight of oxalic acid. Use the calculated formula weight and the number of moles (0.00504mol) of oxalic acid in each titrated unknown sample recorded in Table 6.4 to calculate the number of grams of pure oxalic acid dihydrate contained in each titrated unknown sample.arrow_forward
- 1. Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their (2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these orbitals from the two atoms forming a homonuclear л-bond. Which element would have a stronger bond, and why? (4 points)arrow_forwardWrite the reaction and show the mechanism of the reaction. Include the mechanism for formation of the NO2+ 2. Explain, using resonance structures, why the meta isomer is formed. Draw possible resonance structures for ortho, meta and para.arrow_forwardNonearrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
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