a.
Power used by heater.
a.
Answer to Problem 31PP
Explanation of Solution
Given:
Current drawn by heater,
Source voltage,
Operation time is 5 h/day
Formula used:
Power consumed is given as,
Where,
Calculation:
On substituting the given values in above relation
Conclusion:
Therefore, the power used by heater is
b.
Energy consumed in given time.
b.
Answer to Problem 31PP
Explanation of Solution
Given:
Current drawn by heater,
Source voltage,
Operation time is 5 h/day
Time is
Formula used:
The energy power relation is given as,
Where,
Calculation:
As,
So total operating time in hour is
And from previous subpart
So, on substituting the values in above relation
Conclusion:
Therefore, the energy consumed is
c.
Cost of operation for given time and rate.
c.
Answer to Problem 31PP
Operation cost is
Explanation of Solution
Given:
Current drawn by heater,
Source voltage,
Operation time is 5 h/day
Time is
Rate of electricity is $ 0.12/kWh
Formula used:
The cost is given as,
Calculation:
As from previous subpart, the energy consumed in 30 days is 270 kWh.
So, the cost of electricity is
Conclusion:
Therefore, the cost of electricity is
Chapter 22 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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