Chapter 22, Problem 62A

To determine

Voltage of the battery.

Answer to Problem 62A

  $V=6\text{V}$

Explanation of Solution

Given:

Resistance of resistor, $R=4\Omega$

Current, $I=1.5\text{A}$

Formula Used:

Ohm’s law is given as,

  $V=IR$

Where, $V$ is applied voltage, $I$ is current and $R$ is resistance.

Calculation:

On substituting the values in above relation,

  $\begin{array}{c}V=1.5\times 4\\ =6\text{V}\end{array}$

Conclusion:

Therefore, the voltage of the source is $V=6\text{V}$