Concept explainers
Write the electron configurations of the following ions:
Interpretation:
The electronic configuration of the given transition metal ions is to be determined.
Concept introduction:
The transition metals are those that form at least one stable ion with incomplete d subshell.
The transition metals show a variable oxidation state.
The transition metals have partially filled d subshell.
The energy of electrons present in the d subshell is similar.
The nearest inert gas to the third transition series is argon with atomic number 18.
Answer to Problem 5QP
Solution:
Explanation of Solution
The transition metals have unpaired electrons in a d subshell and the species containing unpaired electrons are unstable and readily lose an electron to form a bond with another chemical species.
Atomic number of vanadium atom is
The electronic configuration of vanadium atom is as follows:
When a vanadium atom loses five electrons from its valence shell, it forms a vanadium ion with
Therefore, the electronic configuration of vanadium ion is as follows:
The electronic configuration of vanadium ion in terms of the nearest inert gas is as follows:
Atomic number of a chromium atom is
The electronic configuration of a chromium atom is as follows:
When chromium atom loses three electrons from its valence shell, it forms a chromium ion with
Therefore, the electronic configuration of the chromium ion is as follows:
The electronic configuration of a chromium ion in terms of the nearest inert gas is as follows:
Atomic Number of manganese atom is
The electronic configuration of a manganese atom is as follows:
When manganese atom loses two electrons from its valence shell, it forms a manganese ion with
Therefore, the electronic configuration of manganese ion is as follows:
The electronic configuration of a manganese ion in terms of the nearest inert gas is as follows:
Atomic number of an iron atom is
The electronic configuration of an iron atom is as follows:
When an iron atom loses three electrons from its valence shell, it forms an iron ion with
Therefore, the electronic configuration of an iron ion is as follows:
The electronic configuration of an iron ion in terms of the nearest inert gas is as follows:
Atomic number of copper atom is
The electronic configuration of a copper atom is as follows:
When a copper atom loses two electrons from its valence shell, it forms a copper ion with
Therefore, the electronic configuration of a copper ion is as follows:
The electronic configuration of a copperion in terms of the nearest inert gas is as follows:
Atomic number of a scandium atom is
The electronic configuration of a scandium atom is as follows:
When a scandiumatom loses three electrons from its valence shell, it forms a scandium ion with
Therefore, the electronic configuration of a scandium ion is as follows:
The electronic configuration of a scandium ion in terms of the nearest inert gas is as follows:
Atomic number of a titanium atom is
The electronic configuration of atitanium atom is as follows:
When titanium atom loses four electrons from its valence shell, it forms a titanium ion with
Therefore, the electronic configuration of a titanium ion is as follows:
The electronic configuration of a titanium ion in terms of the nearest inert gas is as follows:
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Chapter 22 Solutions
Chemistry
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