Concept explainers
Interpretation:
The equilibrium constant for the given reaction is to be calculated with the standard reduction potential.
Concept introduction:
The change in free energy is called Gibbs free energy and is denoted as
If
The standard EMF of a cell is represented as follows:
The standard Gibbs free energy change is calculated by the expression as:
Here,
The equilibrium constant is calculated by the expression as:
The relation between free energy change and standard free energy change is as:
Here,
At equilibrium the above equation is reducedto the expression:
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Chemistry
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- Consider the following cell reaction at 25C. 2Cr(s)+3Fe2+(aq)2Cr3+(aq)+3Fe(s) Calculate the standard cell potential of this cell from the standard electrode potentials, and from this obtain G for the cell reaction. Use data in Appendix C to calculate H; note that Cr(H2O)63+(aq) equals Cr3+(aq). Use these values of H and G to obtain S for the cell reaction.arrow_forwardWhat is the standard cell potential you would obtain from a cell at 25C using an electrode in which Hg22+(aq) is in contact with mercury metal and an electrode in which an aluminum strip dips into a solution of Al3+(aq)?arrow_forwardCopper(I) ion disproportionates to copper metal and copper(ll) ion. (See Study Question 99.) 2 Cu+(aq) Cu(s) + Cu2 + (aq) (a) What two half-reactions make up the disproportionation reaction? (b) Use values of the standard reduction potentials for the two half-reactions in part (a) to determine whether this disproportionation reaction is product-favored at equilibrium. (c) What is the equilibrium constant for this reaction? If you have a solution that initially contains 0.10 mol of Cu+ in 1.0 L of water, what are the concentrations of Cu+ and Cu2+ at equilibrium?arrow_forward
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