(a) Interpretation: The reason of more electronegative nature of oxygen than sulfur should be explained. Concept introduction: The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons. The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 1

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Students have asked these similar questions

(b) Is boron a metal or a non-metal? Give reasons for your answer. (c) Why is aluminium a useful structural material even though it reacts readilywith water and oxygen? (d) What is the usual valence shown by elements of Group 13 in compounds?

Explain each of the following observations: (a) At room temperature I2 is a solid, Br2 is a liquid, and Cl2 and F2 are both gases.

Boron’s chemistry is not typical of its group.(a) Cite three ways in which boron and its compounds differ sig-nificantly from the other 3A(13) members and their compounds.(b) What is the reason for these differences?

Answer 2

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 3

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 4

Question

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

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Answer 5

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 6

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 7

Chapter 22, Problem 22.139SP

Interpretation Introduction

(a)

Interpretation:

The reason of more electronegative nature of oxygen than sulfur should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here, oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The reason for the formation of long S_nchains by Sulfur which is not possible in O atom should be explained.

Concept introduction:

The group 6A elements show variation from non-metals to metals down in the group. The first element of the group 6A is oxygen with 6 valence electrons.

The group 6A is a combination of non-metal, metalloid and metals. The first element of the group 6A is oxygen with 6 valence electrons. Here oxygen and sulfur are non-metals, selenium and tellurium are metalloid and polonium is the last element of group 6A.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 22 - Which element has more nonmetallic character:Cl or...Ch. 22 - Prob. 22.2A Ch. 22 - Prob. 22.3P Ch. 22 - Prob. 22.4A Ch. 22 - Prob. 22.5P Ch. 22 - Look at the location of elements A, B, C, and Din...Ch. 22 - What are the formula and charge of the silicate...Ch. 22 - Suggest a plausible structure for the silicate...Ch. 22 - Prob. 22.9P Ch. 22 - Write balanced net ionic equations for the...

Solution Summary: The author explains that the group 6A is a combination of non-metal, metalloid and metals.

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Chapter 22 Solutions