Starting Out with C++ from Control Structures to Objects (9th Edition)
Starting Out with C++ from Control Structures to Objects (9th Edition)
9th Edition
ISBN: 9780134498379
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 21, Problem 8RQE
Program Description Answer

A binary tree contains left and right pointers points to the “root” node.

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#ifndef BT_NODE_H#define BT_NODE_H struct btNode{   int data;   btNode* left;   btNode* right;}; // pre:  bst_root is root pointer of a binary search tree (may be 0 for//       empty tree) and portArray has the base address of an array large//       enough to hold all the data items in the binary search tree// post: The binary search tree has been traversed in-order and the data//       values are written (as they are encountered) to portArray in//       increasing positional order starting from the first elementvoid portToArrayInOrder(btNode* bst_root, int* portArray);void portToArrayInOrderAux(btNode* bst_root, int* portArray, int& portIndex); // pre:  (none)// post: dynamic memory of all the nodes of the tree rooted at root has been//       freed up (returned back to heap/freestore) and the tree is now empty//       (root pointer contains the null address)void tree_clear(btNode*& root); // pre:  (none)// post: # of nodes contained in tree rooted at root is returnedint…
C programming I need help writing a code that uses a struct pointer into a binary tree and using the same pointer into an array
Find the errors in the program then correct them. CODE: #include <bits/stdc++.h>using namespace std; /* A binary tree node has key, pointer to leftchild and a pointer to right child */struct Node {    int key;    struct Node *left, *right}; /* function to create a new node of tree andreturn pointer */struct Node* newNode(int key){    struct Node* temp = new node;    temp->key = key;    temp->left = temp->right = NULL;    return temp;}; /* Inorder traversal of a binary tree*/void inorder(struct Node* temp){    if (!temp)        return 0    inorder(temp->left);    cout << temp->key << " ";    inorder(temp->right)} /* function to delete the given deepest node(d_node) in binary tree */void deletDeepest(struct Node* root,                  struct Node* d_node){    queue<struct Node*> q    q.push(root);     // Do level order traversal until last node    struct Node* temp;    while (!q.empty()) {        temp = q.front();        q.pop();        if (temp…
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