Assume the tree node structure is following....... struct node { int data; struct node* left; struct node* right; }; struct node *root = null; and there is a created new node function, called newnode(int new_data). Please filled the Blank of Insertion function. void insert(struct node *root int key) {

#include <iostream> using namespace std; #define SIZE 5   //creating the queue using array int A[SIZE]; int front = -1; int rear = -1;   //function to check if the queue is empty bool isempty() { if(front == -1 && rear == -1) return true; else return false; }   //function to enter elements in queue void enqueue ( int value ) { //if queue is full if ((rear + 1)%SIZE == front)    cout<<"Queue is full \n"; else {  //now the first element is inserted  if( front == -1)     front = 0; //inserting element at rear end rear = (rear+1)%SIZE;   A[rear] = value; } }   //function to remove elements from queue void dequeue ( ) { if( isempty() )  cout<<"Queue is empty\n"; else //only one element if( front == rear )  front = rear = -1; else  front = ( front + 1)%SIZE; }   //function to show the element at front void showfront() { if( isempty()) cout<<"Queue is empty\n"; else cout<<"element at front is:"<<A[front]; }   //function to display the queue void…

Use the following node definition for this problem.struct NodeInt32{int32_t value; NodeInt32* next;} Write a function which searches a non-empty linked list for a target value. Its exact signature should be: NodeInt32* find(NodeInt32* head, int32_t target); The function should return the first node whose value equals target. If the target is not found in the list, then the function should return NULL.

C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed)  int childCount(node* p) {         bool Cright = false;         bool Cleft = false;         if(p->right != NULL){             Cright = true;         }         if(p->left != NULL){                 Cleft = true;          }         if(Cleft == true && Cright== true){             return 2;         }         if(Cright){             return 1;         }         if(Cleft){             return -1;         }         return 0;              }       int set(node* p, int e) {         int elem = p->element;         p->element = e;         return elem;     }       node* addSibling(node* p, int e) {         node* P = p->parent;         if(P != NULL){             if(sibling(p) == NULL){…

use code below in part with bts #include <stdio.h>#include <stdlib.h>#include <time.h> typedef struct node_struct {int item;struct node_struct *next;} node; /*** 10->NULL* We want to insert 20* First call ([10], 20) [not complete]* {10, {20, NULL}} To compute the conditional probabilities you need to determine unigram andbigram counts first (you can do this in a single pass through a file if you do thingscarefully) and store them in a Binary Search Tree (BST). After that, you can computethe conditional probabilities.Input filesTest files can be found on (http://www.gutenberg.org/ebooks/). For example,search for “Mark Twain.” Then click on any of his books. Next download the “PlainText UTF-8” format.In addition, you should test your program on other input files as well, for which youcan hand-compute the correct answer.Output filesYour program must accept the name of an input file as a command line argument.Let's call the file name of this file fn. Your program must…

Project 2: Singly-Linked List The purpose of this assignment is to assess your ability to: ▪Implement sequential search algorithms for linked list structures ▪Implement sequential abstract data types using linked data ▪Analyze and compare algorithms for efficiency using Big-O notation For this assignment, you will implement a singly-linked node class. Use your singly-linked node to implement a singly-linked list class that maintains its elements in ascending order. The SinglyLinkedList class is defined by the following data: ▪A node pointer to the front and the tail of the list Implement the following methods in your class: ▪A default constructor list<T> myList ▪A copy constructor list<T> myList(aList) ▪Access to first elementmyList.front() ▪Access to last elementmyList.back() ▪Insert value myList.insert(val) ▪Remove value at frontmyList.pop_front() ▪Remove value at tailmyList.pop_back() ▪Determine if emptymyList.empty() ▪Return # of elementsmyList.size() ▪Reverse order of…

LAB: Playlist (output linked list) Given main(), complete the SongNode class to include the function PrintSongInfo(). Then write the PrintPlaylist() function in main.cpp to print all songs in the playlist. DO NOT print the head node, which does not contain user-input values. Ex: If the input is: Stomp! 380 The Brothers Johnson The Dude 337 Quincy Jones You Don't Own Me 151 Lesley Gore -1 the output is: LIST OF SONGS ------------- Title: Stomp! Length: 380 Artist: The Brothers Johnson Title: The Dude Length: 337 Artist: Quincy Jones Title: You Don't Own Me Length: 151 Artist: Lesley Gore

C++ please

Language/Type: C++ binary trees pointers recursion Write a function named hasPath that interacts with a tree of BinaryTreeNode structures representing an unordered binary tree. The function accepts three parameters: a pointer to the root of the tree, and two integers start and end, and returns true if a path can be found in the tree from start down to end. In other words, both start and end must be element data values that are found in the tree, and end must be below start, in one of start's subtrees; otherwise the function returns false. If start and end are the same, you are simply checking whether a single node exists in the tree with that data value. If the tree is empty, your function should return false. For example, suppose a BinaryTreeNode pointer named tree points to the root of a tree storing the following elements. The table below shows the results of several various calls to your function: 67 88 52 1 21 16 99 45 Call Result Reason hasPath(tree, 67, 99) true path exists…

C++ AVL trees help can someone please explain to me what is this code and how it works