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DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Textbook Question
Chapter 21, Problem 4RQ
How is feed related to speed in the machining operations called turning?
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Students have asked these similar questions
A part to be turned in an engine lathe must have asurface finish of 1.6 mm. The part is made of a freemachining aluminum alloy. Cutting speed = 150 m/min,and depth of cut = 4.0 mm. The nose radius on the tool =0.75 mm. Determine the feed that will achieve thespecified surface finish.
Electroforming is an example of secondary machining process.
Select one:
True
False
Turning Operation
In a production turning operation, the foreman has decreed that
a single pass must be completed on the cylindrical workpiece in
4.8 min. The piece is 400 mm long and 150 mm in diameter.
Using a feed = 0.43 mm/rev and a depth of cut = 4.0 mm, what
cutting speed must be used to meet this machining time
requirement?
Hint: Re-arrange the Tm equation to find v in m/min
Tm=
T.DO.L
v.f
1.522
Chapter 21 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 21 - Why has the metal-cutting process resisted...Ch. 21 - What variables must be considered in understanding...Ch. 21 - Which of the seven basic chip formation processes...Ch. 21 - How is feed related to speed in the machining...Ch. 21 - Before you select speed and feed for a machining...Ch. 21 - Milling has two feeds. What are they, and which...Ch. 21 - What is the fundamental mechanism of chip...Ch. 21 - What is the difference between oblique machining...Ch. 21 - What are the implications of Figure 21.13, given...Ch. 21 - Note that the units for the approximate equation...
Ch. 21 - For orthogonal machining, the cutting edge radius...Ch. 21 - How do the magnitude of the strain and strain rate...Ch. 21 - Why is titanium such a difficult metal to machine?...Ch. 21 - Explain why you get segmented or discontinuous...Ch. 21 - Why is metal cutting shear stress such an...Ch. 21 - Which of the three cutting forces in oblique...Ch. 21 - How is the energy in a machining process typically...Ch. 21 - Where does the energy consumed in metal cutting...Ch. 21 - What are two ways of estimating the primary...Ch. 21 - What are the three different ways to perform...Ch. 21 - Why does the cutting force Fc increase with...Ch. 21 - Why doesnt the cutting force Fc increase with...Ch. 21 - Prob. 23RQCh. 21 - How does the selection of the machining parameters...Ch. 21 - Suppose you had a machining operation (boring)...Ch. 21 - Make a sketch like that shown in Figure 21.1 with...Ch. 21 - Show how you would do near orthogonal machining in...Ch. 21 - Can you do orthogonal machining on a shaper or...Ch. 21 - What process and material combination would yield...Ch. 21 - What is meant by the statement that machining...Ch. 21 - Prob. 31RQCh. 21 - Figure 21.4 provides suggested cutting speeds and...Ch. 21 - For problem 1, suppose you selected a speed of 145...Ch. 21 - If the cutting forces is 1000 lb calculate the...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - For a turning operation, you have selected a...Ch. 21 - For a slab milling operation using a...Ch. 21 - The power required to machine metal is related to...Ch. 21 - In order to drill a hole in the material described...Ch. 21 - Suppose you have the data in Table 21.A obtained...Ch. 21 - Calculate the horsepower that a process is going...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - Derive equations for F and N using the circular...Ch. 21 - Prob. 14PCh. 21 - Prob. 15PCh. 21 - A manufacturing engineer needs an estimate of the...Ch. 21 - Using Figure 21.4 for input data, determine the...Ch. 21 - Estimate the horsepower needed to remove metal at...Ch. 21 - For a turning process, the horsepower required was...
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- In orthogonal machining operation the chip thickness and the uncut chip thickness are equal to 0.45 mm. If the tool rake and is 0 deg. What is the shear plane angle?arrow_forwardHow much machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by turning using a carbide insert. If the approach length and over run length is = 5 mm, Cutting speed is 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mm Darrow_forwardIdentify the machining operation Facing Profiling Thread cutting Form Millingarrow_forward
- 3) Turning: A turning operation is to be adopted under the following machining conditions: Cutting speed: V = 75 m/min Feed rate: f= 0.25 mm/rev Depth of cut: a = 1.75 mm External workpiece diameter: Do = 50 mm Determine: a. The final workpiece diameter b. The rotational speed of the workpiece c. The tool feed rate expressed in m/min d. The material removal rate mm³/min e. The specific energy of the material assuming that the measured cutting force is F= 750 N. Knowing the specific energy, which of materials from the table below could the workpiece be composed? Approximate Specific-Energy Requirements in Cutting Operations SPECIFIC ENERGY* MATERIAL Aluminum alloys Cast irons Copper alloys High-temperature alloys W-s/mm³ 0.4-1.1 1.6-5.5 1.4-3.3 3.3-8.5 0.4-0.6 4.9-6.8 3.8-9.6 3.0-5.2 2.7-9.3 3.0-4.1 hp-min/in³ 0.15-0.4 0.6-2.0 0.5-1.2 1.2-3.1 0.15-0.2 1.8-2.5 1.1-3.5 1.1-1.9 1.0-3.4 1.1-1.5 Magnesium alloys Nickel alloys Refractory alloys Stainless steels Steels Titanium alloys * At…arrow_forwardWhat are the different types of milling and its uses?arrow_forward3. A slot of 20 mm width is to be produced using horizontal milling machine. The ks 5,000 N/mm?, cutting speed is 50 m/min, feed rate is 200 mm/min, depth of cut is 4 mm, cutter diameter is 140 mm, and the number of teeth is 12. Calculate the machining power.arrow_forward
- Determine the total machining time for a workpiece 30mm in diameter and the required length is 145 mm. Other data: Material: 38mm dia. X 149 mm Depth of cut (turning): 4mm Depth of cut (facing): 2mm Feed : 0.05 mm/rev : 35 SMPM Cutting speedarrow_forward1. In a production turning operation, the cylindrical workpiece is 425 mm long and 190 mm in diameter, Feed 0.30 mm/rev. What cutting speed must be used to achieve a machining time of 7.0 min?arrow_forwardIn a turning operation, cutting speed =200 m/min; feed = 0.25mm mm/rev, and depth of cut = 4.00mm Thermal diffusivity of the work material = 20m mm^2/s and volumetric specific heat =3.5(10^ -3 )J/mm^ 3 -C If the temperature increase above ambient temperature (20degreesC) is the angle measured by a tool-chip thermocouple to be 700degreesC, determine the specific energy for the work material in this operation.arrow_forward
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