DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 21, Problem 10RQ
Note that the units for the approximate equation for MRR for turning are not correct. When is the approximate equation not very good (yields a large error in MRR values)?
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Chapter 21 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 21 - Why has the metal-cutting process resisted...Ch. 21 - What variables must be considered in understanding...Ch. 21 - Which of the seven basic chip formation processes...Ch. 21 - How is feed related to speed in the machining...Ch. 21 - Before you select speed and feed for a machining...Ch. 21 - Milling has two feeds. What are they, and which...Ch. 21 - What is the fundamental mechanism of chip...Ch. 21 - What is the difference between oblique machining...Ch. 21 - What are the implications of Figure 21.13, given...Ch. 21 - Note that the units for the approximate equation...
Ch. 21 - For orthogonal machining, the cutting edge radius...Ch. 21 - How do the magnitude of the strain and strain rate...Ch. 21 - Why is titanium such a difficult metal to machine?...Ch. 21 - Explain why you get segmented or discontinuous...Ch. 21 - Why is metal cutting shear stress such an...Ch. 21 - Which of the three cutting forces in oblique...Ch. 21 - How is the energy in a machining process typically...Ch. 21 - Where does the energy consumed in metal cutting...Ch. 21 - What are two ways of estimating the primary...Ch. 21 - What are the three different ways to perform...Ch. 21 - Why does the cutting force Fc increase with...Ch. 21 - Why doesnt the cutting force Fc increase with...Ch. 21 - Prob. 23RQCh. 21 - How does the selection of the machining parameters...Ch. 21 - Suppose you had a machining operation (boring)...Ch. 21 - Make a sketch like that shown in Figure 21.1 with...Ch. 21 - Show how you would do near orthogonal machining in...Ch. 21 - Can you do orthogonal machining on a shaper or...Ch. 21 - What process and material combination would yield...Ch. 21 - What is meant by the statement that machining...Ch. 21 - Prob. 31RQCh. 21 - Figure 21.4 provides suggested cutting speeds and...Ch. 21 - For problem 1, suppose you selected a speed of 145...Ch. 21 - If the cutting forces is 1000 lb calculate the...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - For a turning operation, you have selected a...Ch. 21 - For a slab milling operation using a...Ch. 21 - The power required to machine metal is related to...Ch. 21 - In order to drill a hole in the material described...Ch. 21 - Suppose you have the data in Table 21.A obtained...Ch. 21 - Calculate the horsepower that a process is going...Ch. 21 - Explain how you would estimate the cutting force...Ch. 21 - Derive equations for F and N using the circular...Ch. 21 - Prob. 14PCh. 21 - Prob. 15PCh. 21 - A manufacturing engineer needs an estimate of the...Ch. 21 - Using Figure 21.4 for input data, determine the...Ch. 21 - Estimate the horsepower needed to remove metal at...Ch. 21 - For a turning process, the horsepower required was...
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- thickness is HW3.A block of steel has a length L-600mm and a width W-450mm. The Machined 10mm, once by Peripheral Milling and once by planing Machine.Calculate :Machining time for each operation if you know the following For peripheral milling: cutting speed V =80 m/min, Feed f-0.15mm/rev, the cutter .1 diameter D =50 mm with five teeth and depth of cut d =3mm For planing: clearance on both sides c =25mm, cutting speed V =36.56 m/min, retum to .2 cutting ratio m =0.25, feed f=5 mm/stroke and depth of cut d =5 mm .Calculate Material removal rate in both processes .3 Solutionarrow_forwardIn a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution) L Tm- 1,= Nf N AD, vT" = C %3| AD,L Tm fvarrow_forwardA HSS tool is used to turn a steel workpart that is 300 mm long and 80 mm in diameter. The parameters in the Taylor equation are: n=0.13 and C= 75 (m/min) for a feed of 0.4 mm/rev. The operator and machine tool rate = $30.00/hr, and the tooling cost per cutting edge = $4.00. It takes 2.0 min to load and unload the workpart and 3.50 min to change tools. Determine: a. Tutting speed for maximum production rate, b. Tool life in min of cutting, and c. Cycle time and cost per unit of product.arrow_forward
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