Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 21, Problem 30QLP
To determine
Explain why it is possible to remove more material between tool re-sharpenings by lowering the cutting speed.
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3) Explain the advantages and any disadvantages of indexable cutting inserts. Why
were they developed?
4) How does the coefficient of friction affect the relationship between the friction
force and the normal force on the tool face?
5) A turning operation is being carried out on a long, round bar at a constant depth of
cut. Explain what differences, if any, there may be in the machined diameter from
one end of the bar to the other. Give reasons for any changes that may occur.
The outside diameter of a cylinder made of steel is to be turned. The starting diameter is 120 mm and the length is 1400 mm. The feed is 0.3 mm/rev and the depth of cut is 2.5mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.33 and C=500. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time required to complete this turning operation.
During orthogonal cutting of mild steel with a 10° rake angle tool, the chip thickness ratio was obtained as 0.4 .Calaculate the shear angle.
Chapter 21 Solutions
Manufacturing Engineering & Technology
Ch. 21 - Explain why continuous chips are not necessarily...Ch. 21 - Name the factors that contribute to the formation...Ch. 21 - What is the cutting ratio? Is it always less than...Ch. 21 - Explain the difference between positive and...Ch. 21 - Explain how a dull tool can lead to negative rake...Ch. 21 - Comment on the role and importance relief angle.Ch. 21 - Explain the difference between discontinuous chips...Ch. 21 - Why should we be interested in the magnitude of...Ch. 21 - What are the differences between orthogonal and...Ch. 21 - What is a BUE? Why does it form?
Ch. 21 - Is there any advantage to having a built-up edge...Ch. 21 - What is the function of chip breakers? How do they...Ch. 21 - Identify the forces involved in a cutting...Ch. 21 - Explain the characteristics of different types of...Ch. 21 - List the factors that contribute to poor surface...Ch. 21 - Explain what is meant by the term machinability...Ch. 21 - What is shaving in machining? When would it be...Ch. 21 - List reasons that machining operations may be...Ch. 21 - Are the locations of maximum temperature and...Ch. 21 - Is material ductility important for machinability?...Ch. 21 - Explain why studying the types of chips produced...Ch. 21 - Prob. 22QLPCh. 21 - Tool life can be almost infinite at low cutting...Ch. 21 - Explain the consequences of allowing temperatures...Ch. 21 - The cutting force increases with the depth of cut...Ch. 21 - Why is it not always advisable to increase the...Ch. 21 - What are the consequences if a cutting tool chips?Ch. 21 - What are the effects of performing a cutting...Ch. 21 - Prob. 29QLPCh. 21 - Prob. 30QLPCh. 21 - Prob. 31QLPCh. 21 - Prob. 32QLPCh. 21 - Comment on your observations regarding Figs. 21.1...Ch. 21 - Prob. 34QLPCh. 21 - Comment on your observations regarding the...Ch. 21 - Why does the temperature in cutting depend on the...Ch. 21 - You will note that the values of a and b in Eq....Ch. 21 - Prob. 38QLPCh. 21 - Prob. 39QLPCh. 21 - Explain whether it is desirable to have a high or...Ch. 21 - The Taylor tool-life equation is directly...Ch. 21 - Prob. 42QLPCh. 21 - Why are tool temperatures low at low cutting...Ch. 21 - Can high-speed machining be performed without the...Ch. 21 - Prob. 45QLPCh. 21 - Prob. 46QLPCh. 21 - State whether or not the following statements are...Ch. 21 - Let n = 0.5 and C = 400 in the Taylor equation for...Ch. 21 - Assume that, in orthogonal cutting, the rake angle...Ch. 21 - Prob. 50QTPCh. 21 - Prob. 51QTPCh. 21 - Using trigonometric relationships, derive an...Ch. 21 - An orthogonal cutting operation is being carried...Ch. 21 - Prob. 54QTPCh. 21 - Prob. 55QTPCh. 21 - Prob. 56QTPCh. 21 - Show that, for the same shear angle, there are two...Ch. 21 - With appropriate diagrams, show how the use of a...Ch. 21 - In a cutting operation using a 5 rake angle, the...Ch. 21 - For a turning operation using a ceramic cutting...Ch. 21 - In Example 21.3, if the cutting speed V is...Ch. 21 - Using Eq. (21.30), select an appropriate feed for...Ch. 21 - With a carbide tool, the temperature in a cutting...Ch. 21 - The following flank wear data were collected in a...Ch. 21 - The following data are available from orthogonal...Ch. 21 - Prob. 66QTPCh. 21 - Design an experimental setup whereby orthogonal...Ch. 21 - Describe your thoughts on whether chips produced...Ch. 21 - Recall that cutting tools can be designed so that...Ch. 21 - Recall that the chip-formation mechanism also can...Ch. 21 - Prob. 73SDPCh. 21 - Describe your thoughts regarding the recycling of...Ch. 21 - List products that can be directly produced from...Ch. 21 - Obtain a wood planer and some wood specimens. Show...Ch. 21 - It has been noted that the chips from certain...Ch. 21 - As we have seen, chips carry away the majority of...
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- . Let n = 0.5 and C = 90 in the Taylor equation for tool wear. What is the percent increase %3D in cutting speed if the tool life is reduced by (a) 50% and (b) 75%?arrow_forwardNote: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.arrow_forwardIn turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n = 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the tool life to be 10% longer than the machining time for this part.arrow_forward
- Assume that, in orthogonal cutting, the rake angle is 20 and the friction angle is 35 at thechip-tool interface. Determine the percentage change in chip thickness when the frictionangle is 50. Note that Merchant’s equation is more preferable.arrow_forward4) How does the coefficient of friction affect the relationship between the friction force and the normal force on the tool face? 5) A turning operation is being carried out on a long, round bar at a constant depth of cut. Explain what differences, if any, there may be in the machined diameter from one end of the bar to the other. Give reasons for any changes that may occur.arrow_forwardQuestion 2. The two sources of heat are (a) shearing in the primary shear plane and (b) friction at the tool-chip interface. What type of the tool wear or tool failure could be caused as a result of developing these heat sources on machining process? Explain your answer in accordance with following representation of tool wear. Insert cutting edgearrow_forward
- In a cutting test with 0.3 mm flank wear as tool failure criterion, a tool life of 10 min was obtained at a cutting velocity of 20 m/min. Taking tool life exponent as 0.25, the tool life in minutes at 40 m/min of cutting velocity will be?arrow_forwardA tool with zero rake angle used in orthogonal cutting when its clearance angle a is changed from 10 to 7 deg, Calculate the approximate % change in the life of the tool.arrow_forwardDiscuss the effects of cutting speed, feed rate, and depth of cut on the tool wear rate during a turning operation. How does each parameter influence the surface finish of the workpiece? Provide a detailed explanation based on the principles of metal cutting mechanics.arrow_forward
- An orthogonal cutting operation is being carried out under the following conditions: depth of cut, to = 0.1 mm, rake angle, a = 10°, Cutting force, Fc =1500 N, and Thrust force, Ft = 800 N. Calculate the shear force.arrow_forwardWrite down the important properties of cutting tool?Write short note on4different types of cutting fluids commonly used in detail.arrow_forwardThe orthogonal cutting of steel is done with 10° rake tool with a depth of cut of 4mm feed rate of 0.4mm/rev. The cutting speed is 200m/min. The chip thickness ratio is 0.35. The vertical cutting force is 1200N and the horizontal cutting force is 700N. Calculate from the Merchant's theory, the various work done in metal cutting and shear stress.arrow_forward
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