Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 20, Problem 49P
Interpretation Introduction
Interpretation:
The structure of compound that has molecular weight
Concept introduction:
Spectroscopy method is used to identify the structure of the molecule. It is based on the interactions between matter and
Proton NMR spectroscopy identifies the number of hydrogen atoms present in a molecule and the nature of the
The value of chemical peaks depends upon the chemical environment around the hydrogen atom.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The H1H1 NMR spectrum shown corresponds to an unknown compound with the molecular formula C6H10C6H10. There are no strong IR bands between 2100 and 2300 or 3250 and 3350 cm−1. Deduce and draw the structure of the molecule that corresponds to the spectrum.
An IR spectrum, a 13C NMR spectrum, and a 1H NMR spectrum were obtained for an unknown structure with a molecular formula of C8H10O2. Draw the structure of this compound.
Assume a compound with the formula C4H8O.
a) How many double bonds and/or rings does your compound contain?
b) If your compound shows an infrared absorption peak at 1715 cm-1, what functional group does it have?
c) If your compound shows a single 1H NMR absorption peak at 2.1 δ, what is its structure?
Chapter 20 Solutions
Organic Chemistry - Standalone book
Ch. 20.1 - Prob. 1PCh. 20.2 - Prob. 2PCh. 20.3 - Prob. 3PCh. 20.4 - Prob. 4PCh. 20.5 - Prob. 5PCh. 20.8 - Prob. 6PCh. 20.8 - Prob. 7PCh. 20.8 - Prob. 8PCh. 20.9 - Prob. 9PCh. 20.9 - Prob. 10P
Ch. 20.9 - Prob. 11PCh. 20.9 - Prob. 12PCh. 20.10 - Prob. 13PCh. 20.10 - Prob. 14PCh. 20.11 - Prob. 15PCh. 20.11 - Prob. 16PCh. 20.11 - Prob. 17PCh. 20.12 - Prob. 18PCh. 20.12 - Prob. 19PCh. 20.12 - Prob. 20PCh. 20.12 - Prob. 21PCh. 20.13 - Prob. 22PCh. 20.13 - Prob. 23PCh. 20.14 - Prob. 24PCh. 20.15 - Prob. 25PCh. 20.16 - Prob. 26PCh. 20.17 - Prob. 27PCh. 20 - Prob. 28PCh. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Write a structural formula for the principal...Ch. 20 - Prob. 32PCh. 20 - Prob. 33PCh. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - The preparation of the sex pheromone of the...Ch. 20 - Prob. 44PCh. 20 - Suggest a reasonable explanation for each of the...Ch. 20 - Prob. 46PCh. 20 - Prob. 47PCh. 20 - Prob. 48PCh. 20 - Prob. 49PCh. 20 - A compound has a molecular formula of C8H14O4, and...Ch. 20 - Prob. 51PCh. 20 - Prob. 52DSPCh. 20 - Prob. 53DSPCh. 20 - Prob. 54DSPCh. 20 - Prob. 55DSPCh. 20 - Prob. 56DSPCh. 20 - Thioesters Thioesters have the general formula ....Ch. 20 - Prob. 58DSP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Compound 2 has molecular formula C6H12. It shows three signals in the 1H-NMR spectrum, one at 0.96 ppm, one at 2.03 ppm, and one at 5.33 ppm. The relative integrals of these three signals are 3, 2, and 1, respectively. Provide structure for compound 2, explain how you reached your conclusion.arrow_forwardIdentify the compound with molecular formula C8H10O that gives the IR and 1H NMR spectra shown here.arrow_forwardThe 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.arrow_forward
- Compound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.arrow_forwardThe H1H1 NMR spectra corresponds to an alcohol with the molecular formula C5H12O. Deduce the structure from the spectraarrow_forward11 10 9 8 7 9 +6 5 -3 2 1 ppmarrow_forward
- + 11 10 1H 9 A ¹H NMR spectrum is shown for a molecule with the molecular formula of C8H8O2. Draw the structure that best fits this data. 1H 1H 1H 1H ill 8 6 5 A 3H + 3 + 2 1 ppmarrow_forwardAn unknown compound has the molecular formula C6H12O2. The compound shows a strong peak in its IR spectrum at 1700 cm-1. The 1H NMR data of the compound is given in the graph. Which structure corresponds to the unknown compound?arrow_forwardDraw the structure of C3H8O and indicate which sets of hydrogens correspond to which signal in the H NMR spectrum.arrow_forward
- A compound with molecular formula C3H8O produces a broad signal between 3200 and 3600 cm1 in its IR spectrum and produces two signals in its 1°C NMR spectrum. Draw the structure of the compound.arrow_forwardThe infrared spectrum of a compound has a strong absorption at 1669 cm. The mass spectrum of the compound is provided below. What is the structure of the compound? 100 - 80 - 60 40 20 0- 50 75 100 125 m/z OH NH2 Relative Intensityarrow_forward07) The proton NMR spectrum of a compound with formula C5H12O2 is shown below. THE The carbon-13 NMR spectrum has three peaks, respectively at 15 ppm, 63 ppm and 95 ppm. Based on this information draw the structure of this compound.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
NMR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=SBir5wUS3Bo;License: Standard YouTube License, CC-BY