Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 20, Problem 13PDQ
The Drosophila homeotic mutation spineless aristapedia (ssa) results in the formation of a miniature tarsal structure (normally part of the leg) on the end of the antenna. What insight is provided by (ssa) concerning the role of genes during determination?
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Discuss the morphological differences between the parasegments and segments of Drosophila. Discuss the evidence, providing specific examples, that suggests the parasegments of the embryo are the subdivisions for the organization of gene expression.
Suppose a researcher has three different Drosophila strains that have mutations in the bicoid gene called bicoid-A, bicoid-B, and bicoid-C; the wild type is designated bicoid +. To study these mutations,
phenotypically normal female flies that are homozygous for the given bicoid mutation were obtained, and their oocytes were analyzed using a Northern blot to determine the size and/or amount of the bicoid
mRNA and in situ hybridization to determine the bicoid mRNA location within the oocyte. A wild-type strain was also analyzed as a control. In both cases, the probe was complementary to the bicoid mRNA and
the results are shown below. (Anterior is on the left; posterior is on the right.)
Northern blot
1
2
-
3 4
In situ hybridization
Wild type
Lane 1. Wild type (bicoid*)
Lane 2. bicoid-A
Lane 3. bicoid-B
Lane 4. bicoid-C
bicoid-B
bicoid-A
bicoid-C
Which mutation is likely to cause the embryo to develop two "anterior" ends?
bicoid-B
Obicoid-A
bicoid-C
) Explain how and why dorsal/ventral polarity will be affected in fly
Question 3 (1.
embryos carrying the following mutations; also in each case darken in the area of the cells
in the cross-sectional view of the fly embryo which are expected to express the paulie gene.
D = dorsal; V = ventral.
a) a mutation which results in the deletion of the cytoplasmic domain of the Cookie protein.
b) A mutation which results in a constitutively active Bombe protein, i.e. the Bombe protein
is always in an activated state.
c) A mutation which causes the Pickle protein to be retained in the cytoplasm of the
embryo.
Chapter 20 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 20 -
CASE STUDY |One foot or another
In humans the...Ch. 20 - CASE STUDY| One foot or another In humans the HOXD...Ch. 20 - CASE STUDY| One foot or another In humans the HOXD...Ch. 20 - HOW DO WE KNOW? In this chapter, we have focused...Ch. 20 - Review the Chapter Concepts list on page 403. Most...Ch. 20 -
3. Nuclei from almost any source may be injected...Ch. 20 -
4. Distinguish between the syncytial blastoderm...Ch. 20 - (a) What are maternal-effect genes? (b) When are...Ch. 20 - (a) What are zygotic genes, and when are their...Ch. 20 - List the main classes of zygotic genes. What is...
Ch. 20 -
8. Experiments have shown that any nuclei placed...Ch. 20 - How can you determine whether a particular gene is...Ch. 20 -
10. You observe that a particular gene is being...Ch. 20 - What are Hox genes? What properties do they have...Ch. 20 -
12. The homeotic mutation Antennapedia causes...Ch. 20 - The Drosophila homeotic mutation spineless...Ch. 20 - A number of genes that control expression of Hox...Ch. 20 - In Arabidopsis, flower development is controlled...Ch. 20 - Prob. 16PDQCh. 20 - Dominguez et al. (2004) suggest that by studying...
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- Researchers have exploited Minute mutations in orderto study the phenotypes associated with recessive lethal mutations (l−) that decrease the rate of cell divisionand thus make only very tiny homozygous mutant clones that are difficult to analyze. Many differentstrains of Drosophila carry dominant loss-of-functionMinute (M) mutations in a variety of genes encodingribosomal protein subunits. The M genes are haploinsufficient; flies with only one wild-type M+ gene copyhave a slower pace of cell division, and thus prolongeddevelopment and subtle morphological abnormalities.To circumvent the tiny clone problem, researchersgenerate GFP-marked homozygous l−/ l− clones thatare also M+/ M+, in flies that are l−/ l+ and M−/ M+.The loss of the Minute mutation only in cells withinthe clone gives the l−/ l− cells a growth advantageover their neighbors, enabling the mutant clone togrow large enough to study. Diagram chromosomesthat could be used to generate such clonesarrow_forwardFor the first experiment ever on Drosophila mutations. Answer the following questions. a. What is the title of the first published paper explained the experiment and what is the name of the Author? b. What is the first mutation discovered in Drosophila? c. Explain the changes in the Drosophila yellow mutant (Y)compared to wild type.arrow_forwardThe homeotic mutation Antennapedia causes mutant Drosophila to have legs in place of antennae and is a dominant gain-of-function mutation. List all the properties of such mutations. How does the Antennapedia gene change antennae into legs?arrow_forward
- Explain the Retrotransposons—the Copia –White-Apricot System in Drosophila ?arrow_forwardGeneticists often use ethylmethane sulfonate (EMS) to induce mutations in Drosophila. Why is EMS a mutagen of choice for genetic research? What would be the effects of EMS in a strain of Drosophila lacking functional mismatch repair systems?arrow_forwardHow do we know that the mutant Bar-eye phenotype in Drosophila is due to a duplicated gene region rather than to a change in the nucleotide sequence of a gene?arrow_forward
- What would be the most likely result of injecting bicoid mRNA into the posterior end of a Drosophila embryo and inhibiting the translation of nanos mRNA?arrow_forwardWhat is the signaling pathway that mediates the organizing activity of the A/P organizer in the Drosophila wing disc? Describe two experiments that suggest this pathway functions to organize pattern and promote growth along the anterior/posterior axis of wing imaginal discs.arrow_forwardGeneticists often use the alkylating agent ethylmethane sulfonate (EMS; see Figure 15.6) to induce mutations in Drosophila. Why is EMS a mutagen of choice for genetic research? What would be the effects of EMS in a strain of Drosophila lacking functional mismatch repair systems?arrow_forward
- Following a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call C and d. The two homozygous C/C and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/C and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for C and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Using the number of flies expected for the Parental and the Recombinant genotypes and the formula that defines recombination frequency, what is the distance between loci C…arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Considering that out of 1000 flies resulting from the Testcross only 125 are rhythmic how many flies in total are approximatively expected for the Parental genotypes?…arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Which is the genotype of the rhythmic flies resulting from the testcross? Select only one answer 1. C/C d/d 2. C/c D/d 3. C/c d/d 4. c/c…arrow_forward
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