Physics Fundamentals
2nd Edition
ISBN: 9780971313453
Author: Vincent P. Coletta
Publisher: PHYSICS CURRICULUM+INSTRUCT.INC.
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Chapter 2, Problem 7P
To determine
The instantaneous velocity and the acceleration of a particle.
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A particle trajectory is described by x= ( 0.7t -5.
7 t ) m, and y=(1t -4.4 t) m. where t is in seconds.
red
(1) what is the position of the particle at t = 4.2 s
3.0
tion
(2) what is the velocity of the particle at t = 4.2 s
)j m/s
(3) What is the speed of the particle at t = 3 s
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abus Summary
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The coordinates of a particle moving along a curve
are x(t) = -2t2 +15 and y(t) = t2 -10t + 15 , m whent is
in seconds. Calculate the magnitude of velocity and
acceleration when t= 5 sec.
During a 4.65 s interval, a particles coordinates change from x = 10.9m, y = 5.25m to x = 29.7m, y = - 5.25 m. Assuming the particle's velocity is constant, what will its coordinates be at the end of the next 4.65 s interval?
Chapter 2 Solutions
Physics Fundamentals
Ch. 2 - Prob. 1QCh. 2 - Prob. 2QCh. 2 - Prob. 3QCh. 2 - Prob. 4QCh. 2 - Prob. 5QCh. 2 - Prob. 6QCh. 2 - Prob. 7QCh. 2 - Prob. 8QCh. 2 - Prob. 9QCh. 2 - Prob. 1P
Ch. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55P
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- A particle moving along the x axis has a position given by x = (24t – 2.0t 3) m, where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero?arrow_forwardThe velocity of a particle is given by v = 23t2 - 110t + 52, where v is in meters per second and t is in seconds. Plot the velocity v and acceleration a versus time for the first 6.4 seconds of motion and evaluate the velocity when a is zero. Make the plots and then answer the questions. Questions: When t = 0.8 s, V = i m/s, a = i m/s2 When t = 3.7 s, V = i m/s, a = i m/s? When t = 4.7 s, V = i m/s, a = i m/s? When a = 0, V = m/sarrow_forwardThe position of a particle in millimeters is given by s = 27 – 12t + t, where t is in seconds. Plot the s-t and v-t relationships for the first 9 seconds. Determine the net displacement As during that interval and the total distance D traveled. By inspection of the s-t relationship, what conclusion can you reach regarding 3. the acceleration?arrow_forward
- A particle travels along the x-axis such that its velocity is given by v(t) = t sin (2t). If the position of the particle is x = -2 when t = 0, what is the position of the particle when t = 6? You may use a calculator and round your answer to the nearest thousandth.arrow_forward(Figure 1) shows the velocity graph of a particle moving along the xx-axis. Its initial position is x0x0 = 2.0 mm at t0t0 = 0 ss. At t = 2.0 ss, what is the particle's position? Express your answer to two significant figures and include the appropriate units. At ttt = 2.0 ss, what is the particle's velocity? Express your answer to two significant figures and include the appropriate units. At ttt = 2.0 ss, what is the particle's acceleration? Express your answer to two significant figures and include the appropriate units.arrow_forwardA particle has an acceleration of a=4i + (t-2)j The velocity at t=0 is v0=-2i + 0j and is at the origin at t=0 What is the y position when the x velocity is zero? answer in m,arrow_forward
- A particle moving along the x-axis has velocity function v(t) = t³ sin t. How far does the particle travel from time t = 0to t = π?arrow_forwardThe acceleration of a point moving on a vertical line is given by the equation a = 12t – 20. It is known that its displacement s = -10 m at time t = 0 and that its displacement s = 10m at time t = 5 seconds. Derive the equations for its motion.arrow_forwardAt t = 0 the coordinates of a particle are x = 0, y = 2.10 m. At a time 1.05 s later, its coordinates are x = 2.94 m, y = 3.80 m. Find the components of the particle's average velocity during this time interval. vx = ? vy = ?arrow_forward
- The velocity of a particle is given by v [16t'i + 4t'j + (5t + 2)k) m/s, where t is in seconds. If the particle if at the origin when t 0, determine the z-coordinate position of the particle when t- 2 s.arrow_forwardA particle moves along the curve y= x–(x2/400), where x and y are in ft. If the velocity component in the xdirection isvx= 2 ft/sand remains constant, determine themagnitudes of the velocity and acceleration when x = 20 ft.arrow_forwardThe height of an object as a function of time is given by y(t) = A cos(wt + to) + B, where A = B = 1.00 m, w = 3.0s and to = At what instant(s) is the y-component of the object's velocity zero over the time interval fromt=0.0 to t 2.0 s?arrow_forward
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