A particle moving along the x axis has a position given by x = (24t – 2.0t 3) m, where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero?

An object's position as a function of time in one dimension is given by the expression; 3.89t2 + 2.22t + 7.48 where are constants have proper SI Units. What is the object's average velocity between the times t = 3.16 s and t = 8.38 s? with everything in 3 sig figs

A particle's velocity is described by the function vx = t^2− 10t+7m/s, where t is in s How many turning points does the particle reach.

The x-coordinate of a particle in curvilinear motion is given by x= 2.1t³ -2.4t where x is in feet and t is in seconds. The y-component of acceleration in feet per second squared is given by ay = 2.0t. If the particle has y-components y = 0 and vy= 2.2 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 2.7 sec. Sketch the path for the first 2.7 seconds of motion, and show the velocity and acceleration vectors for t = 2.7 sec. Answers: V = i a= i ft/sec ft/sec²

A proton initially has 7 = (-7.10)î + (5.10)Ƒ + (−6.60)î : and then 2.70 s later has 7 = (4.70)î + (5.10)ĵ + (13.0)ê (in avg meters per second). (a) For that 2.70 s, what is the proton's average acceleration a in unit vector notation, (b) in magnitude, and the angle between a and the positive direction of the x axis? avg (a) Number i 11.8 (b) Number i (c) Number i î+ Units Units i 19.6 k Units m/s

A point particle of mass m = 1.8 kg moves according to the position function: r(t) = xtai + ytbj + ztck, where t denotes time and x, y, z, a, b, and c are constants such that the exponents are positive integers and the position function has the dimension of length.  Part (a)  We can write the particle’s velocity function in the form v(t) = ntdi + otej + ptgk. Enter an expression for n in terms of x, y, z, a, b, and c.   Part (b)  The particle’s velocity function will have the form v(t) = ntdi + otej + ptgk. Enter an expression for d in terms of x, y, z, a, b, and c.  Part (c)  Here is a set of parameter values for the motion of the particle: m = 1.8 kg, x = 1.8 m/s0, y = 2.4 m/s1, z = 0.15 m/s2, a = 0, b = 1, c = 2. Calculate the x-component of the particle’s angular momentum, in units of kg˙m2/s, about the origin at time t = 1 s.   Part (d)  Use the same set of parameter values (m = 1.8 kg, x = 1.8 m/s0, y = 2.4 m/s1, z = 0.15 m/s2, a = 0, b = 1, c = 2) to calculate the y-component of…

Two-dimensional motion: Object A has a position as a function of time given by rA(t) = (3.00 m/s)t i + (1.00 m/s2)t2j. Object B has a position as a function of time given by r p(t) = (4.00 m/s)ti + (-1.00 m/s2)t2i. All quantities are SI units. What is the distance between object A and object B at timet= 3.00 s?

The position of a particle is described byr = (t3+ 4t –4) m and θ = (t3/2) rad, where t is inseconds. Determine the magnitudes of the particle’svelocity and acceleration at the instant t = 2 s.

A particle moves along a circular path having a radius of 1.1 m. At an instant when the speed of the particle is equal to 3.22 m/s and changing at the rate of 6.46 m/s², what is the magnitude of the total acceleration of the particle?