At t = 0 the coordinates of a particle are x = 0, y = 2.10 m. At a time 1.05 s later, its coordinates are x = 2.94 m, y = 3.80 m. Find the components of the particle's average velocity during this time interval. vx = ? vy = ?

At t = 0 the coordinates of a particle are x = 0, y = 2.10 m. At a time 1.05 s later, its coordinates are x = 2.94 m, y = 3.80 m. Find the components of the particle's average velocity during this time interval. vx = ? vy = ?

Name: At t = 0 the coordinates of a particle are x = 0, y = 2.10 m. At a tim
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: At t = 0 the coordinates of a particle are x = 0, y = 2.10 m. At a time 1.05 s later, its coordinates are x = 2.94 m, y = 3.80 m. Find the components of the particle's average velocity during this time interval.vx = ?vy = ?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 11P: A particle moves along the x axis according to the equation x = 2.00 + 3.00t 1.00t2, where x is in...

See similar textbooks

Related questions

Q: A jetliner, traveling northward, is landing with a speed of 68.2 m/s. reduce its speed to 7.16 m/s.…

Q: A particle moves along the x axis according to the equation x=2.00 + 3.00t - 1.00t², where x is in…

A: Given information: The position of a particle is, x(t)=2.00+3.00t-1.00t2 We have to find the…

Q: A particle is thrown into air at the origin with initial velocity v = Ai + Bj where A and B are…

Q: The height of an object as a function of time is given by y(t) = A cos(wt + to) + B, %3D where A =…

A: Please see the answer below

Q: Starting from rest, a particle moving in a straight line has an acceleration of a = (2t−6)m/s^2 ,…

A: Given data: Acceleration a =2t-6 ms-2 Time t= 6s To determine Position at Time t = 11 s

Q: The position of a particle in millimeters is given by s = 54 - 15t + t² where t is in seconds. Plot…

Q: The velocity of a particle moving along the x-axis varies in time according to the expression v(t) =…

A: The variation of velocity with time v(t) = α - βt2 α = 52.9m/s , β = 3.72m/s3 To find: Accleration…

Q: A bus makes a trip according to the position-time graph shown in the drawing. What is the average…

Q: a particle moves in one dimension, and its position as a function of time is given by x = (1.9m/s)t…

Q: Starting from the origin of some coordinate system, a chicken moves 2 m to the +x-direction for 2 s,…

A: Given: The chicken moves 2 m to the +x-direction for 2 s. The chicken moves 3 m to the +y-direction…

Concept explainers

Projectile Motion

Topic Video

Question

vx = ?

vy = ?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

The velocity of a particle is given by v = 23t2 - 110t + 52, where v is in meters per second and t is in seconds. Plot the velocity v and acceleration a versus time for the first 6.4 seconds of motion and evaluate the velocity when a is zero. Make the plots and then answer the questions. Questions: When t = 0.8 s, V = i m/s, a = i m/s2 When t = 3.7 s, V = i m/s, a = i m/s? When t = 4.7 s, V = i m/s, a = i m/s? When a = 0, V = m/s
A particle moves along two dimensions based on the following position vector r= [2.0 m + (3.00 m/s)f ]i + [(3.0 m)t - (2.00 m/s2)rlj a. Find the distance it covered in the first minute. b. Find the general expression of the instantaneous acceleration of the particle.
A particle is moving with a velocity of 60m/s in the positive x-direction at t = 0s. Between t = 0s andt = 15s, the velocity decreases uniformly to zero. What was the acceleration during this 15s interval? Whatis the signi cance of the sign of your answer?
(Figure 1) shows the velocity graph of a particle moving along the xx-axis. Its initial position is x0x0 = 2.0 mm at t0t0 = 0 ss. At t = 2.0 ss, what is the particle's position? Express your answer to two significant figures and include the appropriate units. At ttt = 2.0 ss, what is the particle's velocity? Express your answer to two significant figures and include the appropriate units. At ttt = 2.0 ss, what is the particle's acceleration? Express your answer to two significant figures and include the appropriate units.
Two-dimensional motion: Object A has a position as a function of time given by rA(t) = (3.00 m/s)t i + (1.00 m/s2)t2j. Object B has a position as a function of time given by r p(t) = (4.00 m/s)ti + (-1.00 m/s2)t2i. All quantities are SI units. What is the distance between object A and object B at timet= 3.00 s?
A particle’s velocity along the x-axis is described by v(x) = A x + B x2, where x is in meters, v is in meters per second, A = 3.56, and B = -1.5 what is the acceleration, in meters per second squared, of the particle position at x = 2.31m?
An object's position as a function of time in one dimension is given by the expression; 3.89t2 + 2.22t + 7.48 where are constants have proper SI Units. What is the object's average velocity between the times t = 3.16 s and t = 8.38 s? Quantities and answer in 3 sig figs
The displacement of a particle is given by s = 3t3 - 42t2 + 109t - 39 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 11 seconds of motion. After you have made the plots, answer the questions. Questions: Att = 2.4 ft. v= ft/sec. a = ft/sec? sec, Att= 5.4 i ft, v= i ft/sec, a = i ft/sec? S= sec, Att = 8.5 ft. v= i ft/sec, a = i ft/sec? sec, The velocity is zero when t = i sec and when t = i sec
The displacement of a particle is given by s = 2t³ - 42t² + 120t - 68 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 16 seconds of motion. After you have made the plots, answer the questions. Questions: At t = 3.3 sec, S= i ft, v = i ft/sec, a = i ft/sec At t = 8.9 sec, S = ft, v = i ft/sec, a = i ft/sec Att = 14.2 sec, S= i ft, v = i ft/sec, a = i ft/sec The velocity is zero when t = i i sec and when t = i sec
Problem 2: The position of a particle is given by the following expression, where t is time measured in seconds: r(t) = [(3.65 m/s?)f²]į+ (-4.23 m)j + [(4.48 m/s³)r*]k. Part (a) What is the magnitude of the velocity of the particle, in m/s, at t = 0.00 s? Part (b) What is the magnitude of the velocity of the particle, in m/s, at t = 1.65 s? Part (c) What angle, in degrees, does the velocity of the particle make with the +z axis at t = 1.65 s? Part (d) What is the magnitude of the average velocity, in m/s, betweent = 0.00 s and t = 1.65 s? Part (e) What angle, in degrees, does the average velocity between t = 0.00 s and t = 1.65 s make with the z axis?
The acceleration of a particle is given by a = 2t-20, where a is in meters per second squared and t is in seconds. Determine the velocity and displacement as functions of time. The initial displacement at t = 0 is so = -5 m, and the initial velocity is vo = 6 m/s. Once you have determined the functions of time, answer the questions. Questions: When t = 5.1 s, S= V = a = Mi MI i m m/s m/s²
We are standing on the top of a 1040 feet tall building and launch a small object upward. The object's height, measured in feet, after t seconds is h(t) = 16t? + 128t + 1040. A) What is the object initial velocity? ft/second B) What is the highest point that the object reaches? feet