Concept explainers
(a)
To graph: Applying leading coefficient test and draw the graph of the function.
(a)
Explanation of Solution
Given information:
By leading coefficient test:
As the x3is a leading variable and its coefficient is -3 which is a negative coefficient
And x is having odd number as its degree.
So when the large numbers were taken than x3will be dominating
For
For
The graph will be
(b)
To calculate: Zeros of the polynomial.
(b)
Answer to Problem 34CR
The curve will pass through
Explanation of Solution
Given information:
Calculation:
Zeros of the polynomial is:
The curve will pass through
(c)
To graph: Plot the point of the graph.
(c)
Answer to Problem 34CR
The curve also passes through (-1,8), (0,-18), (1,-40)
Explanation of Solution
Given information:
Calculation:
a) Plotting points:
F(x) | x |
8 | -1 |
-18 | 0 |
-40 | 1 |
So the curve also passes through (-1, 8), (0, -18), (1, -40)
(d)
To graph:
(d)
Explanation of Solution
Given information:
Graph:
Interpretation: It is a continuous curve passes through (-1, 8), (0, -18), (1, -40).
Chapter 2 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning