To graph: the function
Answer to Problem 129CR
Vertical asymptote is at x= 5
Horizontal asymptote is at y=2
No holes
No slant asymptotes
Explanation of Solution
Given information:
Graph: Assuming the value of x to find
Interpretation :
To find the vertical asymptotes we have to solve the denominator by equating it equal to zero:
A horizontal asymptotes is defined when the degree of the denominator is greater than or equal to degree of the numerator.
Here the degree of numerator and denominator is same therefore the ratio of coefficient are
Slant asymptotes occur when the degree of denominator is lower than that of the numerator and since the function is having horizontal asymptotes therefore slant asymptote is not possible.
Now , the degree of the denominator is equal to degree of the numerator therefore there will be a hole in the graph at x=c but not on the x=axis. The y value of hole can be found by solving the function into its simplest form by substituting the value of x=c but in the given function there is no hole because the value of constant ‘c’ is different in numerator as well as denominator.
Chapter 2 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning