Explanation The given temperature of argon is 273.15 K . The given initial volume, V i of argon is 1 .00 dm 3 . The given final volume, V f of argon is 3 .00 dm 3 . The value of universal gas constant is 8.314 J K − 1 mol − 1 . The value of molar heat capacity at constant volume for argon, C V , m , is 12.47 J mol − 1 K − 1 . The value of constant c in reversible adiabatic expansion is calculated by the equation, c = C V , m R Where, • C V , m is the molar heat capacity at constant volume for argon. • R is the universal gas constant. Substitute the values of molar heat capacity and universal gas constant in the above equation. c = 12.47 J mol − 1 K − 1 8.314 J K − 1 mol − 1 = 1

11th Edition

ISBN: 9780198769866

Author: ATKINS, P. W. (peter William), De Paula, Julio, Keeler, JAMES

Publisher: Oxford University Press

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Chapter 2, Problem 2E.2AE

Interpretation Introduction

Interpretation: The final temperature of a given sample of argon having mass 12.0 g has to be calculated.

Concept introduction: The process in which heat or mass of the material does not exchange between the system and the surrounding is known as adiabatic process.

The final temperature of a reversible adiabatic expansion of any gas is calculated by the expression,

Tf=Ti(ViVf)1/c

Expert Solution & Answer

Chapter 2 Solutions

Atkins' Physical Chemistry

Ch. 2 - Prob. 2A.1ST Ch. 2 - Prob. 2B.1ST Ch. 2 - Prob. 2B.2ST Ch. 2 - Prob. 2C.1ST Ch. 2 - Prob. 2C.2ST Ch. 2 - Prob. 2D.1ST Ch. 2 - Prob. 2D.2ST Ch. 2 - Prob. 2A.1DQ Ch. 2 - Prob. 2A.2DQ Ch. 2 - Prob. 2A.3DQ

Ch. 2 - Prob. 2A.4DQ Ch. 2 - Prob. 2A.5DQ Ch. 2 - Prob. 2A.1AE Ch. 2 - Prob. 2A.1BE Ch. 2 - Prob. 2A.2AE Ch. 2 - Prob. 2A.2BE Ch. 2 - Prob. 2A.3AE Ch. 2 - Prob. 2A.3BE Ch. 2 - Prob. 2A.4AE Ch. 2 - Prob. 2A.4BE Ch. 2 - Prob. 2A.5AE Ch. 2 - Prob. 2A.5BE Ch. 2 - Prob. 2A.6AE Ch. 2 - Prob. 2A.6BE Ch. 2 - Prob. 2A.1P Ch. 2 - Prob. 2A.2P Ch. 2 - Prob. 2A.3P Ch. 2 - Prob. 2A.4P Ch. 2 - Prob. 2A.5P Ch. 2 - Prob. 2A.6P Ch. 2 - Prob. 2A.7P Ch. 2 - Prob. 2A.8P Ch. 2 - Prob. 2A.9P Ch. 2 - Prob. 2A.10P Ch. 2 - Prob. 2B.1DQ Ch. 2 - Prob. 2B.2DQ Ch. 2 - Prob. 2B.1AE Ch. 2 - Prob. 2B.1BE Ch. 2 - Prob. 2B.2AE Ch. 2 - Prob. 2B.2BE Ch. 2 - Prob. 2B.3AE Ch. 2 - Prob. 2B.3BE Ch. 2 - Prob. 2B.4AE Ch. 2 - Prob. 2B.4BE Ch. 2 - Prob. 2B.1P Ch. 2 - Prob. 2B.2P Ch. 2 - Prob. 2B.3P Ch. 2 - Prob. 2B.4P Ch. 2 - Prob. 2B.5P Ch. 2 - Prob. 2C.1DQ Ch. 2 - Prob. 2C.2DQ Ch. 2 - Prob. 2C.3DQ Ch. 2 - Prob. 2C.4DQ Ch. 2 - Prob. 2C.1AE Ch. 2 - Prob. 2C.1BE Ch. 2 - Prob. 2C.2AE Ch. 2 - Prob. 2C.2BE Ch. 2 - Prob. 2C.3AE Ch. 2 - Prob. 2C.3BE Ch. 2 - Prob. 2C.4AE Ch. 2 - Prob. 2C.4BE Ch. 2 - Prob. 2C.5AE Ch. 2 - Prob. 2C.5BE Ch. 2 - Prob. 2C.6AE Ch. 2 - Prob. 2C.6BE Ch. 2 - Prob. 2C.7AE Ch. 2 - Prob. 2C.7BE Ch. 2 - Prob. 2C.8AE Ch. 2 - Prob. 2C.8BE Ch. 2 - Prob. 2C.1P Ch. 2 - Prob. 2C.2P Ch. 2 - Prob. 2C.3P Ch. 2 - Prob. 2C.4P Ch. 2 - Prob. 2C.5P Ch. 2 - Prob. 2C.6P Ch. 2 - Prob. 2C.7P Ch. 2 - Prob. 2C.8P Ch. 2 - Prob. 2C.9P Ch. 2 - Prob. 2C.10P Ch. 2 - Prob. 2C.11P Ch. 2 - Prob. 2D.1DQ Ch. 2 - Prob. 2D.2DQ Ch. 2 - Prob. 2D.1AE Ch. 2 - Prob. 2D.1BE Ch. 2 - Prob. 2D.2AE Ch. 2 - Prob. 2D.2BE Ch. 2 - Prob. 2D.3AE Ch. 2 - Prob. 2D.3BE Ch. 2 - Prob. 2D.4AE Ch. 2 - Prob. 2D.4BE Ch. 2 - Prob. 2D.5AE Ch. 2 - Prob. 2D.5BE Ch. 2 - Prob. 2D.1P Ch. 2 - Prob. 2D.2P Ch. 2 - Prob. 2D.3P Ch. 2 - Prob. 2D.4P Ch. 2 - Prob. 2D.5P Ch. 2 - Prob. 2D.6P Ch. 2 - Prob. 2D.7P Ch. 2 - Prob. 2D.8P Ch. 2 - Prob. 2D.9P Ch. 2 - Prob. 2E.1DQ Ch. 2 - Prob. 2E.2DQ Ch. 2 - Prob. 2E.1AE Ch. 2 - Prob. 2E.1BE Ch. 2 - Prob. 2E.2AE Ch. 2 - Prob. 2E.2BE Ch. 2 - Prob. 2E.3AE Ch. 2 - Prob. 2E.3BE Ch. 2 - Prob. 2E.4AE Ch. 2 - Prob. 2E.4BE Ch. 2 - Prob. 2E.5AE Ch. 2 - Prob. 2E.5BE Ch. 2 - Prob. 2E.1P Ch. 2 - Prob. 2E.2P Ch. 2 - Prob. 2.1IA Ch. 2 - Prob. 2.3IA Ch. 2 - Prob. 2.4IA Ch. 2 - Prob. 2.5IA Ch. 2 - Prob. 2.6IA Ch. 2 - Prob. 2.7IA

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