Chapter 2, Problem 2D.9P

(a)

Interpretation Introduction

Interpretation: The value of Joule-Thomson coefficient, $\mu$ has to be calculated at $0.100\text{MPa}$ and $300\text{K}$.

Concept introduction: Joule-Thomson coefficient is the ratio of change in enthalpy with respect to change in pressure at constant enthalpy.  The expression to calculate the Joule-Thomson coefficient is given by,

    $\mu =-\frac{1}{C_p}{\left(\frac{\partial H}{\partial p}\right)}_T$

Where,

• • $C_p$ is the heat capacity.
• • $H$ is the specific enthalpy.
• • $p$ is the pressure.
• • $T$ is the temperature.

(b)

Interpretation Introduction

Interpretation: The value of Joule-Thomson coefficient, $\mu$ has to be calculated at $1.00\text{MPa}$ and $350\text{K}$.

Concept introduction: Joule-Thomson coefficient is the ratio of change in enthalpy with respect to change in pressure at constant enthalpy.  The expression to calculate the Joule-Thomson coefficient is given by,

    $\mu =-\frac{1}{C_p}{\left(\frac{\partial H}{\partial p}\right)}_T$

Where,

• • $C_p$ is the heat capacity.
• • $H$ is the specific enthalpy.
• • $p$ is the pressure.
• • $T$ is the temperature.