EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
4th Edition
ISBN: 9781119192107
Author: BULLARD
Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT
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Question
Chapter 2, Problem 2.32P
Interpretation Introduction
(a)
Interpretation:
The units of 3.00 and 2.00 should be determined.
Concept introduction:
A concentration C (mol/L) varies with time (min) according to the equation.
It is assumed that the given equation is valid and therefore dimensionally homogeneous. So, the dimension of the left hand side and right hand side of the equation is equal. In addition, the exp () component is dimensionless.
Interpretation Introduction
(b)
Interpretation:
Suppose the concentration is measured at t=0 and t=1 min. Use two-point interpolation or extrapolation to estimate concentration at t=0.6 min and time at C= 0.1 mol/L.
Concept introduction:
A concentration C (mol/L) varies with time (min) according to the equation.
The two endpoints of a linear graph are assumed to be (x1, y1) and (x2, y2) and extrapolation should be done for the value of the point x, then for extrapolation, the formula is given by,
Interpretation Introduction
(c)
Interpretation:
A curve of C versus t should be sketched.
Concept introduction:
A concentration C (mol/L) varies with time (min) according to the equation.
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Initial temp: 19.06 C
trial 1: 0.5 M concentration
trial 2 : 1.0 M concentration
200 mL of HCl and 200 mL of NaOH are combined in an insulated container.
HCl = 0.5 mol/ml x 200 x 10^-3 ml = 0.1 mol
NaOH = 0.5 mol/ml x 200 x 10^-3 ml= 0.1 mol
H+(aq) + OH-(aq) - - -> H2O (l)
∆H H++ = 0, ∆H OH−− = -230 kJ/mol, ∆H H2O = -286 kJ/mol
∆H reactants = ∆H H++ + ∆H OH−−
= -230 + 0
= -230 kJ/mol
∆H reactants = -286 kJ/mol - ( -230 kJ/mol)
= -56 kJ/mol
For each trial, calculate how much energy is released during this reaction.
Chapter 2 Solutions
EBK ELEMENTARY PRINCIPLES OF CHEMICAL P
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - During the early part of the 20th century,...Ch. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - The Prandtl number, Np,, is a dimensionless group...Ch. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. 2.33PCh. 2 - 2.34. You arrive at your lab at 8 a.m. and add an...Ch. 2 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - A hygrometer, which measures the amount of...Ch. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. 2.44PCh. 2 - Prob. 2.45PCh. 2 - Prob. 2.46PCh. 2 - Prob. 2.47PCh. 2 - Prob. 2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55P
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